Combine arrays with conditions in Ruby - arrays

I have a class People with three properties
class People
attr_accessor :first_name, :last_name, :age
end
And I have two arrays:
a = [p1, p2]
b = [p3, p4]
Is there any easy way to combine these two arrays in a new array and remove the item with a condition like:
p1.first_name + p1.last_name == p3.first_name + p3.last_name
And after that all the item should be belong to array a
For example
p1.first_name = "Ada"
p1.last_name = "Wang"
p1.age = 28
p2.first_name = "Leon"
p2.last_name = "S"
p2.age = 28
p3.first_name = "Ada"
p3.last_name = "Wang"
p3.age = 18
p4.first_name = "Mario"
p4.last_name = "M"
p4.age = 80
the result should be [p1] the 28 years old Ada.Wang

I'm not sure I get your point, but maybe this is a possible option.
c = a + b
c.uniq! { |e| e.first_name && e.last_name }
Call Array#uniq! with a block on c which is the concatenation of a and b.

If arrays a and b themselves do not contain people with matching first and last names then this would work:
b.each_with_index do |p, i|
if !(b[i].first_name == a[i].first_name and b[i].last_name == a[i].last_name)
a.push(p) # as people p does not contain the same first/last names as a it can now be added to a
end
end
To check for other fields simply replace first_name / last_name with other variables.

Related

LUA getting values from table by using a string

How would I go about compiling values from a table using a string?
i.e.
NumberDef = {
[1] = 1,
[2] = 2,
[3] = 3
}
TextDef = {
["a"] = 1,
["b"] = 2,
["c"] = 3
}
If I was for example to request "1ABC3", how would I get it to output 1 1 2 3 3?
Greatly appreciate any response.
Try this:
s="1ABC3z9"
t=s:gsub(".",function (x)
local y=tonumber(x)
if y~=nil then
y=NumberDef[y]
else
y=TextDef[x:lower()]
end
return (y or x).." "
end)
print(t)
This may be simplified if you combine the two tables into one.
You can access values in a lua array like so:
TableName["IndexNameOrNumber"]
Using your example:
NumberDef = {
[1] = 1,
[2] = 2,
[3] = 3
}
TextDef = {
["a"] = 1,
["b"] = 2,
["c"] = 3
}
print(NumberDef[2])--Will print 2
print(TextDef["c"])--will print 3
If you wish to access all values of a Lua array you can loop through all values like so (similarly to a foreach in c#):
for i,v in next, TextDef do
print(i, v)
end
--Output:
--c 3
--a 1
--b 2
So to answer your request, you would request those values like so:
print(NumberDef[1], TextDef["a"], TextDef["b"], TextDef["c"], NumberDef[3])--Will print 1 1 2 3 3
One more point, if you're interested in concatenating lua string this can be accomplished like so:
string1 = string2 .. string3
Example:
local StringValue1 = "I"
local StringValue2 = "Love"
local StringValue3 = StringValue1 .. " " .. StringValue2 .. " Memes!"
print(StringValue3) -- Will print "I Love Memes!"
UPDATE
I whipped up a quick example code you could use to handle what you're looking for. This will go through the inputted string and check each of the two tables if the value you requested exists. If it does it will add it onto a string value and print at the end the final product.
local StringInput = "1abc3" -- Your request to find
local CombineString = "" --To combine the request
NumberDef = {
[1] = 1,
[2] = 2,
[3] = 3
}
TextDef = {
["a"] = 1,
["b"] = 2,
["c"] = 3
}
for i=1, #StringInput do --Foreach character in the string inputted do this
local CurrentCharacter = StringInput:sub(i,i); --get the current character from the loop position
local Num = tonumber(CurrentCharacter)--If possible convert to number
if TextDef[CurrentCharacter] then--if it exists in text def array then combine it
CombineString = CombineString .. TextDef[CurrentCharacter]
end
if NumberDef[Num] then --if it exists in number def array then combine it
CombineString = CombineString .. NumberDef[Num]
end
end
print("Combined: ", CombineString) --print the final product.

Iterate over array of objects. Then access object method if correct one is found. Otherwise create a new object in the array

I start with an empty array, and a Hash of key, values.
I would like to iterate over the Hash and compare it against the empty array. If the value for each k,v pair doesn't already exist in the array, I would like to create an object with that value and then access an object method to append the key to an array inside the object.
This is my code
class Test
def initialize(name)
#name = name
#values = []
end
attr_accessor :name
def values=(value)
#values << value
end
def add(value)
#values.push(value)
end
end
l = []
n = {'server_1': 'cluster_x', 'server_2': 'cluster_y', 'server_3': 'cluster_z', 'server_4': 'cluster_x', 'server_5': 'cluster_y'}
n.each do |key, value|
l.any? do |a|
if a.name == value
a.add(key)
else
t = Test.new(value)
t.add(key)
l << t
end
end
end
p l
I would expect to see this:
[
#<Test:0x007ff8d10cd3a8 #name=:cluster_x, #values=["server_1, server_4"]>,
#<Test:0x007ff8d10cd2e0 #name=:cluster_y, #values=["server_2, server_5"]>,
#<Test:0x007ff8d10cd1f0 #name=:cluster_z, #values=["server_3"]>
]
Instead I just get an empty array.
I think that the condition if a.name == value is not being met and then the add method isn't being called.
#Cyzanfar gave me a clue as to what to look for, and I found the answer here
https://stackoverflow.com/a/34904864/5006720
n.each do |key, value|
found = l.detect {|e| e.name == value}
if found
found.add(key)
else
t = Test.new(value)
t.add(key)
l << t
end
end
#ARL you're almost there! The last thing you need to consider is when found actually returns an object since detect will find a matching one at some point.
n.each do |key, value|
found = l.detect {|e| e.name == value}
if found
found.add(key)
else
t = Test.new(value)
t.add(key)
l << t
end
end
You actually only want to add a new instance of Test when found return nil. This code should yield your desired output:
[
#<Test:0x007ff8d10cd3a8 #name=:cluster_x, #values=["server_1, server_4"]>,
#<Test:0x007ff8d10cd2e0 #name=:cluster_y, #values=["server_2, server_5"]>,
#<Test:0x007ff8d10cd1f0 #name=:cluster_z, #values=["server_3"]>
]
I observe two things in your code :
def values=(value)
#values << value
def add(value)
#values.push(value)
two methods do the same thing, pushing a value, as << is a kind of syntactic sugar meaning push
you have changed the meaning of values=, which is usually reserved for a setter method, equivalent to attire_writer :values.
Just to illustrate that there are many ways to do things in Ruby, I propose the following :
class Test
def initialize(name, value)
#name = name
#values = [value]
end
def add(value)
#values << value
end
end
h_cluster = {} # intermediate hash whose key is the cluster name
n = {'server_1': 'cluster_x', 'server_2': 'cluster_y', 'server_3': 'cluster_z',
'server_4': 'cluster_x', 'server_5': 'cluster_y'}
n.each do | server, cluster |
puts "server=#{server}, cluster=#{cluster}"
cluster_found = h_cluster[cluster] # does the key exist ? => nil or Test
# instance with servers list
puts "cluster_found=#{cluster_found.inspect}"
if cluster_found
then # add server to existing cluster
cluster_found.add(server)
else # create a new cluster
h_cluster[cluster] = Test.new(cluster, server)
end
end
p h_cluster.collect { | cluster, servers | servers }
Execution :
$ ruby -w t.rb
server=server_1, cluster=cluster_x
cluster_found=nil
server=server_2, cluster=cluster_y
cluster_found=nil
server=server_3, cluster=cluster_z
cluster_found=nil
server=server_4, cluster=cluster_x
cluster_found=#<Test:0x007fa7a619ae10 #name="cluster_x", #values=[:server_1]>
server=server_5, cluster=cluster_y
cluster_found=#<Test:0x007fa7a619ac58 #name="cluster_y", #values=[:server_2]>
[#<Test:0x007fa7a619ae10 #name="cluster_x", #values=[:server_1, :server_4]>,
#<Test:0x007fa7a619ac58 #name="cluster_y", #values=[:server_2, :server_5]>,
#<Test:0x007fa7a619aac8 #name="cluster_z", #values=[:server_3]>]

Accessing instance variables inside an array

I am trying to access a specific value inside an array. The array contains specific class instance variables and is as follows:
[[#<Supermarket:0x007f8e989daef8 #id=1, #name="Easybuy">,
#<Delivery:0x007f8e989f98a8 #type=:standard, #price=5.0>],
[#<Supermarket:0x007f8e99039f88 #id=2, #name="Walmart">,
#<Delivery:0x007f8e989f98a8 #type=:standard, #price=5.0>],
[#<Supermarket:0x007f8e9901a390 #id=3, #name="Forragers">,
#<Delivery:0x007f8e989eae20 #type=:express, #price=10.0>]]
I want to iterate over each array inside the array and find out how many Delivery's within the array have #type:standard. Is this possible? Thank you in advance
array_of_array.inject(0) do |sum, array|
sum + array.count { |el| el.class == Delivery && el.instance_variable_get(:#type) == :standard }
end
You can use select() to filter the elements of an array.
Reconstructing your data:
require 'ostruct'
require 'pp'
supermarket_data = [
['Easybuy', 1],
['Walmart', 2],
['Forragers', 3],
]
supermarkets = supermarket_data.map do |(name, id)|
supermarket = OpenStruct.new
supermarket.name = name
supermarket.id = id
supermarket
end
delivery_data = [
['standard', 5.0],
['standard', 5.0],
['express', 10.0],
]
deliveries = delivery_data.map do |(type, price)|
delivery = OpenStruct.new
delivery.type = type
delivery.price = price
delivery
end
combined = supermarkets.zip deliveries
pp combined
[[#<OpenStruct name="Easybuy", id=1>,
#<OpenStruct type="standard", price=5.0>],
[#<OpenStruct name="Walmart", id=2>,
#<OpenStruct type="standard", price=5.0>],
[#<OpenStruct name="Forragers", id=3>,
#<OpenStruct type="express", price=10.0>]]
Filtering the array with select():
standard_deliveries = combined.select do |(supermarket, delivery)|
delivery.type == 'standard'
end
pp standard_deliveries # pretty print
p standard_deliveries.count
[[#<OpenStruct name="Easybuy", id=1>,
#<OpenStruct type="standard", price=5.0>],
[#<OpenStruct name="Walmart", id=2>,
#<OpenStruct type="standard", price=5.0>]]
2

Max value within array of objects

I'm new in ruby. I'm trying to do the following but haven't succeeded.
I've got an array of objects, let's call it objs. Each object has multiple properties, one of those is a variable that holds a number, let's call it val1. I wanna iterate through the array of objects and determine the max value of val1 through all the objects.
I've tried the following:
def init(objs)
#objs = objs
#max = 0
cal_max
end
def cal_max
#max = #objs.find { |obj| obj.val1 >= max }
# also tried
#objs.each { |obj| #max = obj.val1 if obj.val1 >= #max }
end
As I said, I'm just learning about blocks.
Any suggestion is welcome.
Thanks
Let's say you have set up the following model:
class SomeObject
attr_accessor :prop1, :prop2, :val1
def initialize(prop1, prop2, val1)
#prop1 = prop1
#prop2 = prop2
#val1 = val1
end
end
#define your objects from the class above
david = SomeObject.new('David', 'Peters', 23)
steven = SomeObject.new('Steven', 'Peters', 26)
john = SomeObject.new('John', 'Peters', 33)
#define an array of the above objects
array = [david, steven, john]
Then use max_by by passing the condition into its block as follows to determine the object with the max val1 value. Finally call val1 to get the value of the max object.
array.max_by {|e| e.val1 }.val1 #=> 33
You may also consider using hashes (negating the need to define a new class), like so:
david = {f_name: 'David', s_name: 'Peters', age: 23}
steven = {f_name: 'Steven', s_name: 'Peters', age: 26}
john = {f_name: 'John', s_name: 'Peters', age: 33}
array = [david, steven, john]
array.max_by { |hash| hash[:age] }[:age] #=> 33
#objs.map(&:val1).max
That will invoke the method on each object, and create a new array of the results, and then find the max value. This is shorthand for:
#objs.map{ |o| o.val1 }.max
Alternatively, you can select the object with the largest value, and then operate on it (as properly recomended by Cary Swoveland below):
#objs.max_by(&:val1).val1

Fastest and most effective way of comparing two array of hashes of different format

I have two arrays of hashes with the format:
hash1
[{:root => root_value, :child1 => child1_value, :subchild1 => subchild1_value, bases => hit1,hit2,hit3}...]
hash2
[{:path => root_value/child1_value/subchild1_value, :hit1_exist => t ,hit2_exist => t,hit3_exist => f}...]
IF I do this
Def sample
results = nil
project = Project.find(params[:project_id])
testrun_query = "SELECT root_name, suite_name, case_name, ic_name, executed_platforms FROM testrun_caches WHERE start_date >= '#{params[:start_date]}' AND start_date < '#{params[:end_date]}' AND project_id = #{params[:project_id]} AND result <> 'SKIP' AND result <> 'N/A'"
if !params[:platform].nil? && params[:platform] != [""]
#yell_and_log "platform not nil"
platform_query = nil
params[:platform].each do |platform|
if platform_query.nil?
platform_query = " AND (executed_platforms LIKE '%#{platform.to_s},%'"
else
platform_query += " OR executed_platforms LIKE '%#{platform.to_s},%'"
end
end
testrun_query += ")" + platform_query
end
if !params[:location].nil? &&!params[:location].empty?
#yell_and_log "location not nil"
testrun_query += "AND location LIKE '#{params[:location].to_s}%'"
end
testrun_query += " GROUP BY root_name, suite_name, case_name, ic_name, executed_platforms ORDER BY root_name, suite_name, case_name, ic_name"
ic_query = "SELECT ics.path, memberships.pts8210, memberships.sv6, memberships.sv7, memberships.pts14k, memberships.pts22k, memberships.pts24k, memberships.spb32, memberships.spb64, memberships.sde, projects.name FROM ics INNER JOIN memberships on memberships.ic_id = ics.id INNER JOIN test_groups ON test_groups.id = memberships.test_group_id INNER JOIN projects ON test_groups.project_id = projects.id WHERE deleted = 'false' AND (memberships.pts8210 = true OR memberships.sv6 = true OR memberships.sv7 = true OR memberships.pts14k = true OR memberships.pts22k = true OR memberships.pts24k = true OR memberships.spb32 = true OR memberships.spb64 = true OR memberships.sde = true) AND projects.name = '#{project.name}' GROUP BY path, memberships.pts8210, memberships.sv6, memberships.sv7, memberships.pts14k, memberships.pts22k, memberships.pts24k, memberships.spb32, memberships.spb64, memberships.sde, projects.name ORDER BY ics.path"
if params[:ic_type] == "never_run"
runtest = TestrunCache.connection.select_all(testrun_query)
alltest = TrsIc.connection.select_all(ic_query)
(alltest.length).times do |i|
#exec_pltfrm = test['executed_platforms'].split(",")
unfinishedtest = comparison(runtest[i],alltest[i])
yell_and_log("test = #{unfinishedtest}")
yell_and_log("#{runtest[i]}")
yell_and_log("#{alltest[i]}")
end
end
end
I get in my log:
test = true
array of hash 1 = {"root_name"=>"BSDPLATFORM", "suite_name"=>"cli", "case_name"=>"functional", "ic_name"=>"cli_sanity_test", "executed_platforms"=>"pts22k,pts24k,sv7,"}
array of hash 2 = {"path"=>"BSDPLATFORM/cli/functional/cli_sanity_test", "pts8210"=>"f", "sv6"=>"f", "sv7"=>"t", "pts14k"=>nil, "pts22k"=>"t", "pts24k"=>"t", "spb32"=>nil, "spb64"=>nil, "sde"=>nil, "name"=>"pts_6_20"}
test = false
array of hash 1 = {"root_name"=>"BSDPLATFORM", "suite_name"=>"infrastructure", "case_name"=>"bypass_pts14k_copper", "ic_name"=>"ic_packet_9", "executed_platforms"=>"sv6,"}
array of hash 2 = {"path"=>"BSDPLATFORM/infrastructure/build/copyrights", "pts8210"=>"f", "sv6"=>"t", "sv7"=>"t", "pts14k"=>"f", "pts22k"=>"t", "pts24k"=>"t", "spb32"=>"f", "spb64"=>nil, "sde"=>nil, "name"=>"pts_6_20"}
test = false
array of hash 1 = {"root_name"=>"BSDPLATFORM", "suite_name"=>"infrastructure", "case_name"=>"bypass_pts14k_copper", "ic_name"=>"ic_status_1", "executed_platforms"=>"sv6,"}
array of hash 2 = {"path"=>"BSDPLATFORM/infrastructure/build/ic_1", "pts8210"=>"f", "sv6"=>"t", "sv7"=>"t", "pts14k"=>"f", "pts22k"=>"t", "pts24k"=>"t", "spb32"=>"f", "spb64"=>nil, "sde"=>nil, "name"=>"pts_6_20"}
test = false
array of hash 1 = {"root_name"=>"BSDPLATFORM", "suite_name"=>"infrastructure", "case_name"=>"bypass_pts14k_copper", "ic_name"=>"ic_status_2", "executed_platforms"=>"sv6,"}
array of hash 2 = {"path"=>"BSDPLATFORM/infrastructure/build/ic_files", "pts8210"=>"f", "sv6"=>"t", "sv7"=>"f", "pts14k"=>"f", "pts22k"=>"t", "pts24k"=>"t", "spb32"=>"f", "spb64"=>nil, "sde"=>nil, "name"=>"pts_6_20"}
SO I get only the first to match but rest becomes different and I get result of one instead of 4230
I would like some way to match by path and root/suite/case/ic and then compare the executed platforms passed in array of hashes 1 vs platforms set to true in array of hash2
Not sure if this is fastest, and I wrote this based on your original question that didn't provide sample code, but:
def compare(h1, h2)
(h2[:path] == "#{h1[:root]}/#{h1[:child1]}/#{h1[:subchild1]}") && \
(h2[:hit1_exist] == ((h1[:bases][0] == nil) ? 'f' : 't')) && \
(h2[:hit2_exist] == ((h1[:bases][1] == nil) ? 'f' : 't')) && \
(h2[:hit3_exist] == ((h1[:bases][2] == nil) ? 'f' : 't'))
end
def compare_arr(h1a, h2a)
(h1a.length).times do |i|
compare(h1a[i],h2a[i])
end
end
Test:
require "benchmark"
h1a = []
h2a = []
def rstr
# from http://stackoverflow.com/a/88341/178651
(0...2).map{65.+(rand(26)).chr}.join
end
def rnil
rand(2) > 0 ? '' : nil
end
10000.times do
h1a << {:root => rstr(), :child1 => rstr(), :subchild1 => rstr(), :bases => [rnil,rnil,rnil]}
h2a << {:path => '#{rstr()}/#{rstr()}/#{rstr()}', :hit1_exist => 't', :hit2_exist => 't', :hit3_exist => 'f'}
end
Benchmark.measure do
compare_arr(h1a,h2a)
end
Results:
=> 0.020000 0.000000 0.020000 ( 0.024039)
Now that I'm looking at your code, I think it could be optimized by removing array creations, and splits and joins which are creating arrays and strings that need to be garbage collected which also will slow things down, but not by as much as you mention.
Your database queries may be slow. Run explain/analyze or similar on them to see why each is slow, optimize/reduce your queries, add indexes where needed, etc. Also, check cpu and memory utilization, etc. It might not just be the code.
But, there are some definite things that need to be fixed. You also have several risks of SQL injection attack, e.g.:
... start_date >= '#{params[:start_date]}' AND start_date < '#{params[:end_date]}' AND project_id = #{params[:project_id]} ...
Anywhere that params and variables are put directly into the SQL may be a danger. You'll want to make sure to use prepared statements or at least SQL escape the values. Read this all the way through: http://guides.rubyonrails.org/active_record_querying.html
([element_being_tested].each do |el|
[hash_array_1, hash_array_2].reject do |x, y|
x[el] == y[el]
end
end).each {|x, y| puts (x[bases] | y[bases])}
Enumerate the hash elements to test.
[element_being_tested].each do |el|
Then iterate through the hash arrays themselves, comparing the given hashes by the elements of the given comparison defined by the outer loop, rejecting those not appropriately equal. (The == may actually need to be != but you can figure that much out)
[hash_array_1, hash_array_2].reject do |x, y|
x[el] == y[el]
end
Finally, you again compare the hashes taking the set union of their elements.
.each {|x, y| puts (x[bases] | y[bases])}
You may need to test the code. It's not meant for production so much as demonstration because I wasn't sure I read your code right. Please post a larger sample of the source including the data structures in question if this answer is unsatisfactory.
Regarding speed: if you're iterating through a large data set and comparing multiple there's probably nothing you can do. Perhaps you can invert the loops I presented and make the hash arrays the outer loop. You're not going to get lightning speed here in Ruby (really any language) if the data structure is large.

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