Storing user-inputted strings into a string array in c? - c

Fairly new to C, I am trying to read a file of multiple words using bash indirection, and put the words into a string array. The end of the file is marked with a -1.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void init(char* words[]);
int main(int argc,char *argv[]){
char* words[400000];
init(words);
int i = 0;
do{
printf("%s",words[i]);
i++;
}while(!strcmp(words[i],"-1"));
}
void init(char* words[]){ // initializes array
int i = 0;
do{
fgets(words[i],1024,stdin);
i++;
}while(!strcmp(words[i],"-1"));
}
This gives me a segmentation fault, if any other information is needed I'm more than happy to provide it.

If I guessed correctly, '400000' means the max lines the user can input. But the default size of stack on Windows OS is 1M, sizeof(void*) * 400000 = 1,600,000...
The other thing is that you have not allocated memory for every line.
So, I try to correct your code like this:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAX_LINE 4000 // '400000' is really too big!
void init(char* words[]);
int main(int argc,char *argv[]){
char* words[MAX_LINE];
memset(words, 0 , sizeof(words));
init(words);
int i = 0;
do{
printf("%s",words[i]);
delete words[i];
words[i] = nullptr;
i++;
}while(!strcmp(words[i],"-1"));
}
void init(char* words[]){ // initializes array
int maxLen = 1024;
int i = 0;
do{
words[i] = new char[maxLen];
memset(words[i], 0, maxLen);
fgets(words[i], maxLen, stdin);
i++;
}while(!strcmp(words[i],"-1") && i < MAX_LINE);
}

Related

How do you assign structs into an array?

I have currently made this much of the code:
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <ctype.h>
#define STRSIZE 21
struct PInven{
int count;
struct PItem{
char name[STRSIZE];
int amount;
}Pitem;
}Pinven;//this needs to be an output file
int ReadInProduce (){
//read in file and check to see if the file exist or not.
FILE * PinFile = fopen("produce.txt","r");
if (PinFile == NULL){
printf("ERROR: WRONG FILE");
}
else{
printf("I did it!!\n");
}
//assigning the value gotten into the struct variable(but need to maybe change this since it needs to be an output)
fscanf(PinFile,"%d",&Pinven.count);
printf("%d\n", Pinven.count);
int i;
for(i =0; i <Pinven.count; i++){
fscanf(PinFile,"%20s %d",Pinven.Pitem.name, &Pinven.Pitem.amount);
printf("%s %d\n",Pinven.Pitem.name, Pinven.Pitem.amount);
}
//making an array to hold the variables
//FILE * PoutFile = fopen("produce_update.txt","w");
fclose(PinFile);
return 0;
}
From there I want to get the file that is read to the structs to be printed out into an array so that later on I can make a function that will be able to compare to the to it.
Basically a store management system. Where the file of the inventory is read in and compared to the file that is store and return a new value for the amount of produce now either left or gained.
10 //number of items that will be stored in the store
apple 19
banana 31
broccoli 9
...
In general, it's a really bad idea to include header information in the file about the number of entries in the file. You want to be able to do stream processing, and that will be more difficult if you need that meta-data. More importantly, it is important to understand how to write the code so that you don't need it. It's not really that difficult, but for some reason people avoid it. One simple approach is just to grow the array for each entry. This is horribly inefficient, but for the sake of simplicity, here's an example that expects the file not not include that first line:
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <ctype.h>
#include <limits.h>
#define STRSIZE 128
struct PItem{
char name[STRSIZE];
int amount;
};
struct PInven{
int count;
struct PItem *PItem;
};
static void
grow(struct PInven *p)
{
p->PItem = realloc(p->PItem, ++p->count * sizeof *p->PItem);
if( p->PItem == NULL ){
perror("out of memory");
exit(1);
}
}
int
ReadInProduce(struct PInven *P, const char *path)
{
FILE * PinFile = fopen(path, "r");
if( PinFile == NULL ){
perror(path);
exit(1);
}
char fmt[64];
int max_len;
max_len = snprintf(fmt, 0, "%d", INT_MAX);
snprintf(fmt, sizeof fmt, "%%%ds %%%dd", STRSIZE - 1, max_len - 1);
grow(P);
struct PItem *i = P->PItem;
while( fscanf(PinFile, fmt, i->name, &i->amount) == 2 ){
i += 1;
grow(P);
}
P->count -= 1;
fclose(PinFile); /* Should check for error here! */
return P->count;
}
int
main(int argc, char **argv)
{
struct PInven P = {0};
char *input = argc > 1 ? argv[1] : "produce.txt";
ReadInProduce(&P, input);
struct PItem *t = P.PItem;
for( int i = 0; i < P.count; i++, t++ ){
printf("%10d: %s\n", t->amount, t->name);
}
}
As an exercise for the reader, you should add some error handling. At the moment, this code simply stops reading the input file if there is bad input. Also, it would be a useful exercise to do fewer reallocations.
you should change Structure of PInven to it can save a dynamic array of Pitem with a Pitem pointer.
tested :
#include <ctype.h>
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#define STRSIZE 21
typedef struct {
char name[STRSIZE];
int amount;
} Pitem;
struct PInven {
int count;
Pitem *pitem;
} Pinven; // this needs to be an output file
int main() {
// read in file and check to see if the file exist or not.
FILE *PinFile = fopen("produce.txt", "r");
if (PinFile == NULL) {
printf("ERROR: WRONG FILE");
} else {
printf("I did it!!\n");
}
// assigning the value gotten into the struct variable(but need to maybe
// change this since it needs to be an output)
fscanf(PinFile, "%d", &Pinven.count);
Pinven.pitem = (Pitem *)malloc(sizeof(Pitem) * Pinven.count);
printf("%d\n", Pinven.count);
int i;
for (i = 0; i < Pinven.count; i++) {
fscanf(PinFile, "%20s %d", Pinven.pitem[i].name,
&Pinven.pitem[i].amount);
// printf("%s %d\n",Pinven.pitem[i].name, Pinven.pitem[i].amount);
}
for (i = 0; i < Pinven.count; i++) {
printf("%s %d\n", Pinven.pitem[i].name, Pinven.pitem[i].amount);
}
// making an array to hold the variables
// FILE * PoutFile = fopen("produce_update.txt","w");
fclose(PinFile);
// remember free
free(Pinven.pitem);
return 0;
}

C programming : Creating substring

I'm new in C and I need some explanation on what I am doing wrong.
I'm trying to iterate over a string and find the first '\' then make a substring from that place in the array.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main() {
struct info{
char* name;
char* type;
char* path;
};
struct info user1;
char* a = "/home/users/user1";
for (int i = strlen(a) ; i < 0 ; i--) {
printf("%d",i);
if(strcmp(a[i],'/')==0){
strncpy(a,user1.name,i);
break;
}
}
return 0;
}
There are many errors I will explain them one by one. The code will be something like this.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void) {
struct info{
char* name;
char* type;
char* path;
};
struct info user1;
user1.name = malloc(40);
if( user1.name == NULL){
fprintf(stderr, "%s\n","Error in malloc" );
exit(1);
}
const char* a = "/home/users/user1";
for(int i = strlen(a) -1; i >= 0 ; i--) {
if(a[i]=='/'){
strncpy(user1.name,a+i+1,i);
user1.name[i]='\0';
break;
}
}
printf("%s\n",user1.name );
free(user1.name);
return 0;
}
Things you did wrong
There was no memory allocated to name it was simply an uninitialized pointer. Here we have allocated memory to it.
Second thing, strcmp as the name suggests compares null terminated char array not char-s. It can be done with simple == operator.
The copy part is modified to only copy the user name part nothing else. That's why we have incremented the pointer to point to the correct position.
You forgot to check the return value of malloc and then you should free the allocated memory.
Also you can't modify a string literal because it stays in non-modifiable portion of the memory.
try this,
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main() {
struct info{
char* name;
char* type;
char* path;
};
struct info user1;
user1.name = malloc(10);
char* a = "/home/users/user1";
int len=strlen(a);
for (int i = 0; i < len; i++) {
printf("%d",i);
if(a[i]=='/'){
strncpy(user1.name,a+i+1,i);
user1.name[i]='\0';
break;
}
}
return 0;
}

Randomize letters in string in C

I have for example "asd" and I want it to be randomized to DAS, DSA, SAD, you know. How can I code this? Tried a few solutions but It didnt really work.
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <string.h>
int main()
{
printf("type in the word\n");
char haslo[128];
scanf("%s", haslo);
char set[128];
char hasloa[128];
strcpy(set, haslo);
unsigned int Ind = 0;
srand(time(NULL) + rand());
int len = strlen(set);
while(Ind < len)
{
hasloa[Ind++] = set[rand()%62];
}
hasloa[len] = '\0';
printf("%s", hasloa);
return 0;
}
Change 62 inside the while loop to "len"

What is wrong with my program reversing strings in C?

I want to create a function to reverse a string in C. I found a couple pre-made on the internet but I wish to create mine. Here is the code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* inverseCarac(char* chaine){
if(chaine==0||*chaine==0) return NULL;
int j, i;
int taille=strlen(chaine);
char* inverse=malloc(taille*sizeof(char));
for(j=taille-1, i=0; j>0; j--, i++){
*(inverse+i)=*(chaine-j);
}
return inverse;
}
int main(void){
char* test="bonjour";
char* inv=inverseCarac(test);
printf("%s", inv);
return 0;
}
I can't figure out why I get a segmentation fault.
There were several errors in your code, the most significant being the offset from chaine in the wrong direction. Also, lack of space for a string terminator, and j ending prematurely.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* inverseCarac(char* chaine){
if(chaine==0||*chaine==0) return NULL;
int j, i;
int taille=strlen(chaine);
char* inverse=malloc(taille+1); // add 1 for terminator
for(j=taille-1, i=0; j>=0; j--, i++){ // change j>0 to j >= 0
*(inverse+i)=*(chaine+j); // change -j to +j
}
inverse[taille] = '\0'; // write terminator
return inverse;
}
int main(void){
char* test="bonjour";
char* inv=inverseCarac(test);
printf("%s\n", inv);
return 0;
}
Program output
ruojnob

Wrong result when copying an array of strings

I have the following code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* user;
char* passwd;
int nr;
void test()
{
int i=0;
for(i=0;i<argc;i++)
printf("Hello %s \n",user);
}
int main(int argc,char*argv[])
{
int i;
nr=argc;
for (i=0; i<argc; i++)
{
user=strdup(argv[i]);
}
test();
return 0;
}
The result is the argv[argc] on all the positions. How can I fix this? I wwant to have that test() outside the loop.
**
EDIT
**
After the ANSWERS here this is my new code, which is not working. Can anyone say why?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* user;
void test(int n)
{
int i=0;
for(i=0;i<n;i++)
printf("%s \n",user[i]);
}
int main(int argc,char*argv[])
{
user = (char*) malloc(argc*sizeof(char));
int i;
for (i=0;i<argc;i++)
{
user[i]=argv[i];
}
test(argc);
return 0;
}
You are assigning to both password and user at each iteration of the for loop. The final values you see are from the last iteration. Also, there is memory leak due to overwriting the pointers from previous strdup calls. In fact, you do not need a loop:
int main(int argc,char*argv[])
{
if(argc == 3) {
user=strdup(argv[1]);
passwd=strdup(argv[2]);
} else {
// error: usage
}
test();
return 0;
}
If you want to have multiple user/password combinations:
char *user[256], *passwd[256];
void test(int n) {
int i;
for(i=0;i<n;i++)
printf("Hello %s \n",user[i]);
}
int main(int argc,char*argv[])
{
int i;
for(i = 0; i < argc && i < 256; i+=2) {
user[i]=strdup(argv[i]);
passwd[i]=strdup(argv[i+1]);
}
test(argc);
return 0;
}
Because you overwrite the pointers user and passwd in every iteration. Hence, you'll only see the last string.
If you can tell your aim of the program, a better answer can be provided. Because I am not sure whether you want to read one user and passwd Or an array of users and passwds.
After you edit, I see you want to read an array of strings:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char** user;
// or char *user[100]; /* If you want a fix length array of pointers. Now, you dont have to malloc. /*
char* passwd;
int nr;
void test(int argc)
{
int i=0;
for(i=0;i<argc;i++)
printf("Hello %s \n",user[i]);
}
int main(int argc,char*argv[])
{
int i;
nr=argc;
user = malloc(argc*sizeof(char*));
for (i=0; i<argc; i++)
{
user[i]=strdup(argv[i]);
}
test(argc);
return 0;
}
Of course; in test() you don't use i other than a loop variable and in main() you keep overwriting the previous value of user and passwd. In effect, what you do is:
user = strdup(argv[0]); /* Note: argv[0] is the program name. */
passwd = strdup(argv[0]);
user = strdup(argv[1]);
passwd = strdup(argv[1]);
user = strdup(argv[2]);
passwd = strdup(argv[2]);
user = strdup(argv[3]);
passwd = strdup(argv[3]);
printf("%s %s \n", user, passwd);
With this information, can you fix your program?
$ cat trash.c
#include <stdio.h>
#include <string.h>
void test(FILE* stream, char* usr, char* pass) {
fprintf( stream, "%s#%s\n", usr, pass);
}
int main(int argc, char** argv) {
int i = 1;
if (argc % 2) {
while(argv[i]) {
test(stdout, argv[i], argv[i + 1]);
i += 2;
}
}
return 0;
}
$ clang trash.c
$ ./a.out user1 pass1 user2 pass2
user1#pass1
user2#pass2
$
also if you call strdup() don't forget to free memory, because strdup called malloc().

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