Navigate with tabIndex when elements where hidden - reactjs

Summary
I want to understand how the tabulation navigation works on browser, in order to perform custom input with suggestion field on React.
Objective
The objective is to provide 2 custom input to the use with suggestion dropdown. When I click to my input, the dropdown shows correctly and I can navigate through the tabulation key to my suggestions. But when I try to navigate to the next input, the dropdown shows but I can't navigate through my second dropdown suggestion.
Code example
I have the following JSX code:
class InputDropdown React.Component {
render() {
return(<div>
<div id="input1" className="input-wrapper" onMouseEnter={...} onMouseLeave={...} onBlur={...}>
<input className={"input"}
value={this.state.search_input}
onKeyDown={(e) => e.keyCode==13?this.props.validate(this.state.search_input)}
onFocus={this.setState(display_dropdown_input1: true)}
/>
<div className={"dropdown-wrapper" + this.state.display_dropdown_input1?"":"hidden"}>
{this.props.suggestion.map((suggestion, index) =>
<div className="suggestion"
tabIndex={0}
onKeyDown={(e) => e.keyCode==13?this.props.validate(suggestion.text)}
onBlur={index+1==this.props.suggestion.length?this.setState({display_dropdown_input1:false})}
>{suggestion.text}</div>)}
</div>
</div>
<div id="input2" className="input-wrapper" onMouseEnter={...} onMouseLeave={...} onBlur={...}>
<input className={"input"}
value={this.state.search_input}
onKeyDown={(e) => e.keyCode==13?this.props.validate(this.state.search_input)}
onFocus={this.setState(display_dropdown_input2: true)}
/>
<div className={"dropdown-wrapper" + this.state.display_dropdown_input2?"":"hidden"}>
{this.props.suggestion.map((suggestion, index) =>
<div className="suggestion"
tabIndex={0}
onKeyDown={(e) => e.keyCode==13?this.props.validate(suggestion.text)}
onBlur={index+1==this.props.suggestion.length?this.setState({display_dropdown_input2:false})}
>{suggestion.text}</div>)}
</div>
</div>
</div>)
}
}
Question
It's as if the tabulation navigations road is prepared on the first tabulation pressed and if element appear after this press they are not taken in count.
Is it possible to perform it in React?

Related

How to disable second form if first one is clicked

I have two fields that show a modal when clicked on. I want to make one disabled if I select anyone first. I am using react-bootstrap for this project
<>
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how can I add the logic to disable the next field if anyone is selected first. the image below is the form. (the green check mark shows when each form is filled and saved)
Question answer 1
Yes, if you want both inputs to trigger the opening of the modals you have to set onClick prop on both.
This depends on implementation and what do you specifically mean by disable an input. There are a couple of possible scenarios:
2.1 You may add a disabled class like so:
className={`${isOpened ? "disabled" : ""}`}
and then write some css.
2.2 You might rewrite onClick to just return when the modal is already opened instead of opening the second modal like so:
onClick={() => {
if (isOpened) return
setOpened(true)
}
P.S. You may need to add a second boolean flag to your state if you want this behaviour on both modals / inputs
Original answer
You have to use useState hook with a boolean flag isOpened
const [isOpened, setOpened] = useState(false)
Then update the state when clicking on yout input field
onClick={() => setOpened(true)}
Finally in your input fields you can use isOpened to disable them however you want, using styles or other logic.
P.S. Don't forget to call setOpened(false) when closig your modal

Display a specific component by its key

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Now in the "ContactFormular" component I want to display the information that was on the card that was clicked. is this possible?
Here's the code that opens a new component once the card/button is clicked:
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<div>
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</div>
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)
}
It looks like you're passing in showContactDialog as a parameter and using that to decide whether or not to show this new component right? That means you need showContactDialog to be true for only the one you clicked on, and false for the others. ie each component needs a different state variable. It looks like you might be sharing the same state variable between all components. It's impossible to tell unless you share a reproducible example

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How to use hooks in multiple rendered inputs?

I'm creating the form to my app. Problem i'm facing is whenever i click add and generate another row of inputs i got an "Rendered more hooks than during the previous render" error.
I have a "benefit" input with checkbox. When user checks it i want to render another 2 inputs (in the same row) with KPI. Hook works perfectly fine if there is only one row. When i add another row the error occurs.
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Perfect solution would be: when user checks the box react will show another two inputs.
As Ross Hunter mentioned,
1. You should capitalize your component, i.e. RenderBenefitFields
2. No mutation on state/props, in onClick={() => fields.push({})}
In addition, you should call your RenderBenefitFields in renderBenefits as following:
{fields.map((props, index) => <RenderBenefitFields key={index} {...props} />)}
P.S. You can use a unique key instead of index, depending on your situation.
The name of user-defined components needs to be capitalized.
The onClick callback in PlusCircle looks like it's directly mutating state. That's a big problem for React, and almost certainly the root of your issue. I can explain further if you need sometime I'm not on mobile 😊

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My thought is adding onFocus and onBlur function in each inputbox and saved in state. Is that a better way for this?

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