Take right string after ^ in SQL Server - sql-server

Question

I have some data in SQL Server:
test1^test2^test3^test4
test5
test6^test7
null
Desired output:
test4
test5
test7
null

Answer 1

You can use right() with charindex() & reverse():
select *, right(col, charindex('^', reverse(col) + '^')-1)
from ( values ('test1^test2^test3^test4'), ('test5'), ('test6^test7'), (null)
) t(col);
Demo

Answer 2

One method would be to split the value, using DelimitedSplit8k_LEAD and then take the "last" one (by ordering high to low). This method uses TOP 1 WITH TIES I used this method as order seems to be irrelevant here:
WITH VTE AS (
SELECT Col
FROM (VALUES('test1^test2^test3^test4'),
('test5'),
('test6^test7'),
('test9^test10'),
(null)) V(col))
SELECT TOP 1 WITH TIES
V.Col,
DS.item
FROM VTE V
CROSS APPLY dbo.delimitedsplit8k_LEAD(V.Col,'^') DS
ORDER BY ROW_NUMBER() OVER (PARTITION BY V.Col ORDER BY DS.ItemNumber DESC);
This avoids what can be an expensive REVERSE.

Answer 3

using charindex and reverse:
I left all the functions in there so you could see the process.
declare #t table (test varchar(100))
insert into #t
values
('test1^test2^test3^test4')
,('test5')
,('test6^test7')
,(null )
select test
,revTest
,charInd
,reverse(left(revTest,case when charind = 0 then len(revTest) else charInd-1 end))
from #t t
cross apply (select reverse(rtrim(ltrim(test)))) a(revTest)
cross apply (select CHARINDEX('^',revTest)) b(charInd)
Results:
**test revTest charInd (Result)**
test1^test2^test3^test4 4tset^3tset^2tset^1tset 6 test4
test5 5tset 0 test5
test6^test7 7tset^6tset 6 test7
NULL NULL NULL NULL

Answer 4

Try This
declare
#col varchar(500), #reveCol varchar(500);
set #col='test133^test2^test3^test4';
set #reveCol=reverse(#col)
Select charindex('^', #revecol )
select right( #col ,charindex('^', #revecol )-1)

Answer 5

Assuming you're on SQL Server 2016+
Also assuming this schema and data:
DROP TABLE IF EXISTS #Data;
CREATE TABLE #Data(StringValue NVARCHAR(MAX));
INSERT INTO #Data(StringValue)VALUES
('test1^test2^test3^test4')
,('test5')
,('test6^test7')
,(NULL)
;
The query:
;WITH cte AS (
SELECT '["' + REPLACE(COALESCE(d.StringValue,''),'^','","') + '"]' AS [JSONValue]
,ROW_NUMBER()OVER(ORDER BY d.StringValue) AS [ID]
FROM #Data d
)
SELECT NULLIF(a.value,'') AS [Value]
FROM (
SELECT j.value,ROW_NUMBER()OVER(PARTITION BY c.ID ORDER BY j.[key] DESC) AS [rn]
FROM cte AS c
CROSS APPLY OPENJSON(c.JSONValue) j
) a
WHERE a.rn = 1
;

Answer 6

If you're on SQL Server 2017+
SELECT MAX(CASE WHEN d.StringValue LIKE '%'+s.value THEN s.[value] ELSE NULL END) AS [Result]
FROM ( VALUES
('test1^test2^test3^test4')
,('test5')
,('test6^test7')
,(NULL)
) d(StringValue)
CROSS APPLY STRING_SPLIT(COALESCE(d.StringValue,''),'^') s
GROUP BY d.StringValue
;