Growing arrays. Refer to the elements by pointers, not indexes - c

Question

Since the array address may change when memory is reallocated,
the main part of the program (in the body of the function main ()) should refer to the elements by
indexes, not pointers. Why?
Can you show an example of accessing items with pointers?
(Sorry for my English).
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct Nameval Nameval;
struct Nameval {
char *name;
int value;
};
struct NVtab {
int nval; /* current number of values */
int max; /* allocated number of values */
Nameval *nameval; /* array of name-value pairs */
};
enum {NVINIT = 1, NVGROW = 2};
/* addname: add new name and value to nvtab */
int addname(struct NVtab *nvtab, Nameval newname) {
Nameval *nvp;
if (nvtab->nameval == NULL) { /* first time */
nvtab->nameval = (Nameval *) malloc(NVINIT * sizeof(Nameval));
if (nvtab->nameval == NULL)
return -1;
nvtab->max = NVINIT;
nvtab->nval = 0;
} else if (nvtab->nval >= nvtab->max) { /* grow */
nvp = (Nameval *) realloc(nvtab->nameval,
(NVGROW*nvtab->max)*sizeof(Nameval));
if (nvp == NULL)
return -1;
nvtab->max *= NVGROW;
nvtab->nameval = nvp;
}
nvtab->nameval[nvtab->nval] = newname;
return nvtab->nval++;
}
int main(void) {
struct NVtab nvtab = {0, 0, NULL};
int curnum;
curnum = addname(&nvtab, (Nameval) {.name="Andy", .value=12});
printf("%d\n", curnum);
curnum = addname(&nvtab, (Nameval) {.name="Billy", .value=18});
printf("%d\n", curnum);
curnum = addname(&nvtab, (Nameval) {.name="Jack", .value=71});
printf("%d\n", curnum);
for (int i = 0; i < nvtab.nval; i++) {
printf("%s %d\n", nvtab.nameval[i].name,
nvtab.nameval[i].value);
}
}
For example, why can`t we show array like this:
for (int i = 0; i < nvtab.nval; i++)
printf("%s %d\n", nvtab.*(nameval+i).name, nvtab.*(nameval+i).value);

Answer 1

You are not supposed to assign a pointer calculated for a specific index to a variable with storage duration which could extend over an insert operation.
That pointer could become invalid, so the lesson behind that example is to always re-evaluate iterators on dynamic data structures.
E.g. what not to do:
auto *foo = &nvtab.nameval[i];
addname(&nvtab, (Nameval) {.name="Billy", .value=18});
printf("%s %d\n", foo->name, foo->value);
In the last line it can work or crash. Depending on whether realloc moved the allocation or resized in-place. Except that you can never know for sure until you execute it, as it isn't even fully deterministic.

Answer 2

This is not valid syntax:
nvtab. *(nameval+i).name
The member access operator . expects to be followed by the name of the member. What you want is:
(*(nvtab.nameval+i)).name