How to implement Protected Route using React Route Config - reactjs

I want to implement Protected Routes using React Route config .

As I understand, you can now add render method in config
{
{
path: "/restricted-area",
render: (props) => isUserLoggedIn() ? <RestrictedArea/> : <Redirect to="/login"/>
},
{
path: "/login",
component: Login
}
}
https://github.com/ReactTraining/react-router/pull/6217

If anyone need this behavior, I recommend this protected-react-routes-generator
it will handle all the logic for you, you only need to provide the structure.

Related

Gatsby wildcard route

Is it not possible to route to the same component with a wildcard path?
If in React I have something like:
<Router>
<Switch>
<Route path="/path/:id" children={<Component />} />
</Switch>
</Router>
all the requests:
/path/123
/path/123/p
/path/123/p/1
will route to the same /path/123
How can I tell Gatsby to do the same?
createPage({
path: `/path/123/*`,
component,
context
})
Or what is the solution to this problem, a redirect engine of some sorts?
I think you are looking for client-only routes. Given a page (or template if it's created from gatsby-node.js) you can:
import React from "react"
import { Router } from "#reach/router"
import Layout from "../components/Layout"
import SomeComponent from "../components/SomeComponent"
const App = () => {
return (
<Layout>
<Router basepath="/app">
<SomeComponent path="/path" />
</Router>
</Layout>
)
}
export default App
Note: assuming a src/pages/app/[...].js page (File System Route API structure).
When a page loads, Reach Router looks at the path prop of each component nested under <Router />, and chooses one to render that best matches window.location (you can learn more about how routing works from the #reach/router documentation).
Alternatively, you can use an automated approach (plugin: gatsby-plugin-create-client-paths) by:
{
resolve: `gatsby-plugin-create-client-paths`,
options: { prefixes: [`/path/*`] },
},
Which will validate all routes under /path.
Or for a more customizable approach, in your gatsby-node.js:
exports.onCreatePage = async ({ page, actions }) => {
const { createPage } = actions
// page.matchPath is a special key that's used for matching pages
// only on the client.
if (page.path.match(/^\/path/)) {
page.matchPath = "/path/*"
// Update the page.
createPage(page)
}
}
Disclaimer: These routes will exist on the client only and will not correspond to index.html files in an app’s built assets. If you’d like site users to be able to visit client routes directly, you’ll need to set up your server to handle those routes appropriately.

Building portfolio website and I want to include my github link [duplicate]

Since I'm using React Router to handle my routes in a React app, I'm curious if there is a way to redirect to an external resource.
Say someone hits:
example.com/privacy-policy
I would like it to redirect to:
example.zendesk.com/hc/en-us/articles/123456789-Privacy-Policies
I'm finding exactly zero help in avoiding writing it in plain JavaScript at my index.html loading with something like:
if (window.location.path === "privacy-policy"){
window.location = "example.zendesk.com/hc/en-us/articles/123456789-Privacy-Policies"
}
Here's a one-liner for using React Router to redirect to an external link:
<Route path='/privacy-policy' component={() => {
window.location.href = 'https://example.com/1234';
return null;
}}/>
It uses the React pure component concept to reduce the component's code to a single function that, instead of rendering anything, redirects browser to an external URL.
It works both on React Router 3 and 4.
With Link component of react-router you can do that. In the "to" prop you can specify 3 types of data:
a string: A string representation of the Link location, created by concatenating the location’s pathname, search, and hash properties.
an object: An object that can have any of the following properties:
pathname: A string representing the path to link to.
search: A string representation of query parameters.
hash: A hash to put in the URL, e.g. #a-hash.
state: State to persist to the location.
a function: A function to which current location is passed as an argument and which should return location representation as a string or as an object
For your example (external link):
https://example.zendesk.com/hc/en-us/articles/123456789-Privacy-Policies
You can do the following:
<Link to={{ pathname: "https://example.zendesk.com/hc/en-us/articles/123456789-Privacy-Policies" }} target="_blank" />
You can also pass props you’d like to be on the such as a title, id, className, etc.
There isn’t any need to use the <Link /> component from React Router.
If you want to go to external link use an anchor tag.
<a target="_blank" href="https://meetflo.zendesk.com/hc/en-us/articles/230425728-Privacy-Policies">Policies</a>
It doesn't need to request React Router. This action can be done natively and it is provided by the browser.
Just use window.location.
With React Hooks
const RedirectPage = () => {
React.useEffect(() => {
window.location.replace('https://www.google.com')
}, [])
}
With React Class Component
class RedirectPage extends React.Component {
componentDidMount(){
window.location.replace('https://www.google.com')
}
}
Also, if you want to open it in a new tab:
window.open('https://www.google.com', '_blank');
I actually ended up building my own Component, <Redirect>.
It takes information from the react-router element, so I can keep it in my routes. Such as:
<Route
path="/privacy-policy"
component={ Redirect }
loc="https://meetflo.zendesk.com/hc/en-us/articles/230425728-Privacy-Policies"
/>
Here is my component in case anyone is curious:
import React, { Component } from "react";
export class Redirect extends Component {
constructor( props ){
super();
this.state = { ...props };
}
componentWillMount(){
window.location = this.state.route.loc;
}
render(){
return (<section>Redirecting...</section>);
}
}
export default Redirect;
Note: This is with react-router: 3.0.5, it is not so simple in 4.x
I went through the same issue. I want my portfolio to redirect to social media handles. Earlier I used {Link} from "react-router-dom". That was redirecting to the sub directory as here,
Link can be used for routing web pages within a website. If we want to redirect to an external link then we should use an anchor tag. Like this,
Using some of the information here, I came up with the following component which you can use within your route declarations. It's compatible with React Router v4.
It's using TypeScript, but it should be fairly straightforward to convert to native JavaScript:
interface Props {
exact?: boolean;
link: string;
path: string;
sensitive?: boolean;
strict?: boolean;
}
const ExternalRedirect: React.FC<Props> = (props: Props) => {
const { link, ...routeProps } = props;
return (
<Route
{...routeProps}
render={() => {
window.location.replace(props.link);
return null;
}}
/>
);
};
And use with:
<ExternalRedirect
exact={true}
path={'/privacy-policy'}
link={'https://example.zendesk.com/hc/en-us/articles/123456789-Privacy-Policies'}
/>
The simplest solution is to use a render function and change the window.location.
<Route path="/goToGoogle"
render={() => window.location = "https://www.google.com"} />
If you want a small reusable component, you can just extract it like this:
const ExternalRedirect = ({ to, ...routeProps }) => {
return <Route {...routeProps} render={() => window.location = to} />;
};
and then use it (e.g. in your router switch) like this:
<Switch>
...
<ExternalRedirect exact path="/goToGoogle" to="https://www.google.com" />
</Switch>
I had luck with this:
<Route
path="/example"
component={() => {
global.window && (global.window.location.href = 'https://example.com');
return null;
}}
/>
I solved this on my own (in my web application) by adding an anchor tag and not using anything from React Router, just a plain anchor tag with a link as you can see in the picture screenshot of using anchor tag in a React app without using React Router
Basically, you are not routing your user to another page inside your app, so you must not use the internal router, but use a normal anchor.
Although this is for a non-react-native solution, but you can try.
In React Router v6, component is unavailable. Instead, now it supports element. Make a component redirecting to the external site and add it as shown.
import * as React from 'react';
import { Routes, Route } from "react-router-dom";
function App() {
return(
<Routes>
// Redirect
<Route path="/external-link" element={<External />} />
</Routes>
);
}
function External() {
window.location.href = 'https://google.com';
return null;
}
export default App;
In React Route V6 render props were removed. It should be a redirect component.
RedirectUrl:
const RedirectUrl = ({ url }) => {
useEffect(() => {
window.location.href = url;
}, [url]);
return <h5>Redirecting...</h5>;
};
Route:
<Routes>
<Route path="/redirect" element={<RedirectUrl url="https://google.com" />} />
</Routes>
I think the best solution is to just use a plain old <a> tag. Everything else seems convoluted. React Router is designed for navigation within single page applications, so using it for anything else doesn't make a whole lot of sense. Making an entire component for something that is already built into the <a> tag seems... silly?
To expand on Alan's answer, you can create a <Route/> that redirects all <Link/>'s with "to" attributes containing 'http:' or 'https:' to the correct external resource.
Below is a working example of this which can be placed directly into your <Router>.
<Route path={['/http:', '/https:']} component={props => {
window.location.replace(props.location.pathname.substr(1)) // substr(1) removes the preceding '/'
return null
}}/>
I don't think React Router provides this support. The documentation mentions
A < Redirect > sets up a redirect to another route in your application to maintain old URLs.
You could try using something like React-Redirect instead.
I was facing the same issue and solved it using by http:// or https:// in React.
Like as:
<a target="_blank" href="http://www.example.com/" title="example">See detail</a>
You can use for your dynamic URL:
<Link to={{pathname:`${link}`}}>View</Link>
For V3, although it may work for V4. Going off of Eric's answer, I needed to do a little more, like handle local development where 'http' is not present on the URL. I'm also redirecting to another application on the same server.
Added to the router file:
import RedirectOnServer from './components/RedirectOnServer';
<Route path="/somelocalpath"
component={RedirectOnServer}
target="/someexternaltargetstring like cnn.com"
/>
And the Component:
import React, { Component } from "react";
export class RedirectOnServer extends Component {
constructor(props) {
super();
// If the prefix is http or https, we add nothing
let prefix = window.location.host.startsWith("http") ? "" : "http://";
// Using host here, as I'm redirecting to another location on the same host
this.target = prefix + window.location.host + props.route.target;
}
componentDidMount() {
window.location.replace(this.target);
}
render(){
return (
<div>
<br />
<span>Redirecting to {this.target}</span>
</div>
);
}
}
export default RedirectOnServer;
I am offering an answer relevant to React Router v6 to handle dynamic routing.
I created a generic component called redirect:
export default function Redirect(params) {
window.location.replace('<Destination URL>' + "/." params.destination);
return (
<div />
)
}
I then called it in my router file:
<Route path='/wheretogo' element={<Redirect destination="wheretogo"/>}/>
import React from "react";
import { BrowserRouter as Router, Route } from "react-router-dom";
function App() {
return (
<Router>
<Route path="/" exact>
{window.location.replace("http://agrosys.in")}
</Route>
</Router>
);
}
export default App;
Using React with TypeScript, you get an error as the function must return a React element, not void. So I did it this way using the Route render method (and using React router v4):
redirectToHomePage = (): null => {
window.location.reload();
return null;
};
<Route exact path={'/'} render={this.redirectToHomePage} />
Where you could instead also use window.location.assign(), window.location.replace(), etc.
Complementing Víctor Daniel's answer here: Link's pathname will actually take you to an external link only when there's the 'https://' or 'http://' before the link.
You can do the following:
<Link to={{ pathname:
> "https://example.zendesk.com/hc/en-us/articles/123456789-Privacy-Policies"
> }} target="_blank" />
Or if your URL doesn't come with 'https://', I'd do something like:
<Link to={{pathname:`https://${link}`}} target="_blank" />
Otherwise it will prepend the current base path, as Lorenzo Demattécommented.
If you are using server-side rending, you can use StaticRouter. With your context as props and then adding <Redirect path="/somewhere" /> component in your app. The idea is every time React Router matches a redirect component it will add something into the context you passed into the static router to let you know your path matches a redirect component.
Now that you know you hit a redirect you just need to check if that’s the redirect you are looking for. then just redirect through the server. ctx.redirect('https://example/com').
You can now link to an external site using React Link by providing an object to to with the pathname key:
<Link to={ { pathname: '//example.zendesk.com/hc/en-us/articles/123456789-Privacy-Policies' } } >
If you find that you need to use JavaScript to generate the link in a callback, you can use window.location.replace() or window.location.assign().
Over using window.location.replace(), as other good answers suggest, try using window.location.assign().
window.location.replace() will replace the location history without preserving the current page.
window.location.assign() will transition to the URL specified, but will save the previous page in the browser history, allowing proper back-button functionality.
location.replace()
location.assign()
Also, if you are using a window.location = url method as mentioned in other answers, I highly suggest switching to window.location.href = url.
There is a heavy argument about it, where many users seem to adamantly want to revert the newer object type window.location to its original implementation as string merely because they can (and they egregiously attack anyone who says otherwise), but you could theoretically interrupt other library functionality accessing the window.location object.
Check out this conversation. It's terrible.
JavaScript: Setting location.href versus location
I was able to achieve a redirect in react-router-dom using the following
<Route exact path="/" component={() => <Redirect to={{ pathname: '/YourRoute' }} />} />
For my case, I was looking for a way to redirect users whenever they visit the root URL http://myapp.com to somewhere else within the app http://myapp.com/newplace. so the above helped.

How only Admin can access to the page?

How in my project only admin can access to /page/admin?
Here my code in module config:
auth : authRoles.admin,
routes : [
{
path : '/page/admin',
component: React.lazy(() => import('./Page')),
},
],
auth : authRoles.notadmin,
routes : [
{
path : '/page',
component: React.lazy(() => import('./Page'))
}
//
]
And this, is my auth role:
const authRoles = {
Admin : ['Admin'],
NotAdmin : ['Admin', 'User'],};
The page/admin, is different from the /page
But the User "NotAdmin" can access too page/admin.
Lets try to understand your problem. You are using React Router, I assume. If yes, you have to create a PrivateRoute, then you should be able to check if someone is authenticated or has some role. Take a look on this page. https://reacttraining.com/react-router/web/example/auth-workflow

Dynamic route not working in build version of my react app

I use react router for routing in my create-react-app. All routes work as expected using "npm start" ("react-scripts start").
However, now I would like to deploy my application and therefore ran "npm run-scripts build" ("react-scripts build"). Afterwards I ran "serve -s build" in order to start the webserver. In this version of my web application the static routes are working but the dynamic ones don't.
An example of a static route configuration looks like this. This route works in both, the dev mode and the build mode of the react application. Example URL: "http://localhost:5000/dashboard/viewData".
{
path: "/dashboard/viewData/",
component: withAuth(CrosstabTest),
exact: false
}
The following route is dynamic and doesn't work. However, my guess is that it is not due to ":processFlowItemId" but instead due to additional URL parameters. Example URL: "http://localhost:5000/dashboard/definition/1?id=0744a761-111c-446c-9bb5-2763c5c8bb04".
{
path: "/dashboard/definition/:processFlowItemId",
component: withAuth(DefinitionContainer),
exact: false
}
When I run the example URL without "?id=0744a761-111c-446c-9bb5-2763c5c8bb04" the application loads the component but as the id parameter is missing, I get an error. But at least it's an indication for the fact that the route is working in general but has issues with the parameter. When opening the complete example URL including the id field, the component seems not to be loaded at all (meaning react-router doesn't recognize the URL as an instance of the pattern defined in the route.
As mentioned, the issue only occurs when using the build version of the app.
Edit:
Below I describe the code in more details:
I have a config with my routes:
export const mainRoutes: any = [
{
path: "/dashboard/",
component: Dashboard,
exact: false
},
]
export const dashboardRoutes: any = [
{
path: "/dashboard/viewData/",
component: withAuth(CrosstabTest),
exact: false
},
{
path: "/dashboard/definition/:processFlowItemId",
component: withAuth(DefinitionContainer),
exact: false
},
]
The main route ("mainRoute") is rendered here:
import { mainRoutes } from './routes/routes'
import { Switch, BrowserRouter, Route } from 'react-router-dom'
class App extends React.Component<any> {
public render() {
return (
<BrowserRouter>
{mainRoutes.map((route: any, i: number) => (
<Switch key={i}>
<Route key={i} path={route.path} component={route.component} exact={route.exact} />
</Switch>
))
}
</BrowserRouter>
)
}
}
export default App
In the Dashboard component ("Dashboard") I render a subroute:
import { Switch, Route } from 'react-router-dom'
import { dashboardRoutes } from '../../routes/routes'
...
dashboardRoutes.map((route: any, i: number) => (
<Switch key={i}>
< Route exact={true} key={i} path={route.path} render={(props) => {
return <route.component key={i} {...props} />
}} />
</Switch>
))
...
I had the same problem and solved it by exchanging BrowserRouter for HashRouter

get pathanme in universal router

In react-router there's withRouter HOC that provides access to location.pathname
How can I get it in Universal Router?
history.location.pathname is only available in the browser so can't use that.
If you have universal routes like this:
const routes = {
path: '/page',
name: 'page',
parent: null,
children: [],
action(context, params) {
return '<h1>The Page</h1>'
},
}
(example from documentation https://github.com/kriasoft/universal-router/blob/master/docs/api.md). then you will have context.pathname inside the action. Hope it will help!

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