Read lines of file in C - c

Question

I am trying to read line by line a standard file input.
This is my code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#define BUFFER_SIZE 1204
char* readLine(char* buffer){
int i = 0;
for(i; i< BUFFER_SIZE; i++){
printf("%c",buffer[i]);
if( '\n' == buffer[i]){
char* line[124];
memcpy( line, &buffer[0], i-1 );
return *line;
}
}
free(buffer);
}
int doStuffWithLine(char* line){
return 1;
}
int main(int argc, char *argv[])
{
ssize_t aux1;
char *buffer = malloc(sizeof(char)*BUFFER_SIZE);
char *line = malloc(sizeof(char)*BUFFER_SIZE);
while((read(STDIN_FILENO, buffer, BUFFER_SIZE))>0){
line = readLine(buffer);
doStuffWithLine(line);
printf("%s", line);
}
return 0;
}
This is the input file content:
lol1
lol2
lol3
And this is the output of my program:
lol1
Segmentation fault (core dumped)
I want to know how read lines 2 and 3, solve it and a little explanation about what I am doing wrong because I do not understand the problem.
Thank you in advance.

Answer 1

Function read reads in raw bytes and will not terminate your buffer with a string termination character '\0'; Using it then for printf("%s",...), which expects a 0-terminated C-string, yields undefined behaviour (e.g. a crash).
I'd suggest to use fgets instead.

Answer 2

First of all, thank you all that helped me and spent some time trying it.
After spending some hours learning and breaking my brain I have found a solution. In conclusion I am ***** and noob.
If someone is having the same problem I am submitting my code. Easy peasy:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <limits.h>
char* doStuff(char* line){
return line;
}
int main(int argc, char *argv[])
{
char *line = malloc(sizeof(char)*LINE_MAX);
while(fgets(line, LINE_MAX, stdin)!= NULL)
{
line = doStuff(line);
printf("%s", line);
}
return 0;
}