Having problems passing in data to a function - c

Writing a program in C and I am trying to pass two variables into the function kstrextend. Name which is a word or set of characters that is stored in the value kstring and a which is a numeric value, but name is not getting passed into the function at all as far as I can tell and I cannot figure out why. Is something not getting stored correctly? Because the function works just fine I just cannot get name passed in correctly.
Declaration of kstring and name:
kstring name;
char kstring[50];
Typedef:
typedef struct
{
char *data;
size_t length;
} kstring;
Function:
void kstrextend(kstring *strp, size_t nbytes)
{
char *nwData;
int lnth=strp->length;
if(lnth < nbytes)
{
// new array allocate with large size and copy data to new array
nwData = (char *)realloc(strp->data, nbytes);
// call abort in case of error
if(nwData == NULL)
{
abort();
}
//Making strp->data point to the new array
strp->data = nwData;
//Setting strp->length to the new size.
strp->length = nbytes;
for(int i = 0; i <= lnth; i++)
{
printf("\n %s",strp->data);
}
// filled with '\0' in remaining space of new array
for (int lp = lnth; lp < nbytes; lp++)
{
strp->data[lp] = '\0';
printf("\n %s", strp->data[lp]);
}
}
}
Portion of main:
size_t a;
char * k = kstring;
printf("\n Enter number: ");
scanf("%d", &a);
name.data = (char*)calloc(sizeof(k), 1);
strcpy(input, k);
name.length= kstring_length;
kstrextend(&name,a);

First of all, you have misleading variable name kstring. Use something else like kstring_init and assign it a value. I assume you want to initialize the name variable of type kstring with something and then change its length. So this is what it is all about. Then define a constant of type char * and initialize length and data of your kstring with it. Then use realloc to extend the memory of the pointer with the input value a, not with the size of k. That does not make sense. Since the size of k is the size of the pointer, which is constant.
In your function: don't use int if you pass size_t. Use the same datatype where you do the same things.
In your loop from 0 to lnth, you output the same string lnth+1 times, which does not make sense. You probably want to output the characters of the string. So use %c and use an index into the character array and don't set <= lnth but < lnth as upper limit. Take care with data types if signed and unsigned!
Design hint: If you have a if block, that wraps all your code... invert the condition and just exit so that the code is after the if block.
Take care when you work with size_t and int, since int is signed and size_t is not, which can give problems in if statements.
Don't use abort but rather exit. You don't want your program to abort abnormally and core-dump.
A working version of your program is:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
typedef struct
{
char *data;
size_t length;
} kstring;
kstring name;
char *kstring_init = "blabla";
void kstrextend(kstring *strp, size_t nbytes)
{
char *nwData;
size_t lnth = strp->length;
if ((int) lnth >= (int) nbytes) {
printf("Error, size already larger than requested size.\n");
exit(-1);
}
// new array allocate with large size and copy data to new array
nwData = realloc(strp->data, sizeof(char) * (int) nbytes);
if(nwData == NULL)
{
printf("Error, realloc returned NULL\n");
exit(-1);
}
//Making strp->data point to the new array
strp->data = nwData;
//Setting strp->length to the new size.
strp->length = nbytes;
for(int i = 0; i < lnth; i++)
{
printf("\n %c", strp->data[i]);
}
// filled with '\0' in remaining space of new array
for (int lp = lnth; lp < (int) nbytes; lp++)
{
strp->data[lp] = '\0';
printf("\n %c", strp->data[lp]);
}
}
int main(void)
{
size_t a;
printf("\n Enter number: ");
scanf("%d", &a);
name.length = strlen(kstring_init) + 1;
printf("Length of string is: %d\n", name.length);
name.data = (char*)malloc(sizeof(char) * name.length);
strcpy(name.data, kstring_init);
printf("Old string: %s\n", name.data);
printf("You want to reallocate %d bytes\n", a);
kstrextend(&name, a);
return 0;
}

Related

Passing by Struct pointer is returning wrong value

I am new to C but I am trying to edit a struct in a different function. I can print the value of the struct correctly from the target function readCoordinate but when execution returns to the main function the values of the struct changes to a seemingly random integers.
This is the full code below.
#include <stdio.h>
#include <stdlib.h>
typedef struct {
int X;
int Y;
} Coordinate;
void buff_clr(void)
{
char junk;
do{
junk=getchar();
}while(junk!='\n');
}
int main()
{
Coordinate carrierStart = {0,0};
printf("Input Start coordinate for Carrier (example - B2) \n");
readCoordinate(&carrierStart);
printf("%d, %d \n", carrierStart.X, carrierStart.Y);
}
void readCoordinate(Coordinate *cood){
char str[2];
scanf("%s",&str);
buff_clr();
if (isalpha(str[0]) )
{
str[0] = tolower(str[0]);
findChar(str[0], &cood->X);
cood->Y = (str[1] - '0') - 1;
}
else
{
printf("\n Please Enter Valid Coordinate");
exit(EXIT_SUCCESS);
}
printf("%d, %d \n", cood->X, cood->Y);
return;
}
void findChar(char find, int *x){
char vertical_letters[10] = {'a','b','c','d','e','f','g','h','i','j'};
for (int i = 0; i < 10; i++)
{
if (find == vertical_letters[i])
{
*x = i;
return;
}
}
*x = -1;
}
input of b2 should print 1,1 which is correct in function (readCoordinate) but wrong in Main.
The part
char str[2];
scanf("%s",&str);
is wrong because
&str has type char(*)[2], but %s in scanf expects char*. Passing data having the wrong type like this invokes undefined behavior.
char str[2]; is too short to store 2-character strings like b2 because there is no room for the terminating null character. You have to allocate enough elements.
You should specify the maximum length to read (the length of buffer minus one) to prevent buffer overrun.
It should be:
char str[3];
scanf("%2s",str);

pointer to dynamic array of pointers to dynamic array of pointer that points to strings

i have a problem with the initialization of the values inside the first dynamic array of pointers
#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char*** GetIndexes()
{
int n = 0;
char ***index;
printf("please insert the number of words you want to add to dictionary\n");
scanf("%d", &n);
index = (char***)calloc(n, sizeof(char));
if (index == NULL)
{
printf("allocation Failed");
return;
}
return index;
}
char** GetDefinitions()
{
int n = 0;
char **definition;
printf("please insert the number of defintions you want to add to the word\n");
scanf("%d", &n);
definition = (char**)calloc(n+1, sizeof(char));
if (definition == NULL)
{
printf("allocation failed");
return;
}
return definition;
}
int main()
{
char *** dptr = GetIndexes();
if (dptr == NULL)
{
printf("memory Allocation failed");
}
int indexcount = sizeof(dptr) / sizeof(char),i;
for (i = 0; i < indexcount; i++)
{
printf("word number %d\n", i + 1);
*dptr[i] = GetDefinitions();
}
printf("%p",dptr);
}
i tried running the debugger in VS2013 and after i enter the number of defintions i want it crashed with this message:
Unhandled exception at 0x01103FB0 in ConsoleApplication1.exe: 0xC0000005: Access violation writing location 0x00000000.
i missed an allocation of something but i cant quite figure out what i missed,
thanks in advance
Your program is very broken
You allocate n char ***s but only request space for n chars and also do it for char **, to prevent this kind of mistake you may use the sizeof operator this way
char ***index;
index = calloc(n, sizeof(*index));
and
char **definition;
definition = calloc(n, sizeof(*definition));
and as you see casting calloc makes it harder and it's not necessary.
You have a return statement that doesn't return anything an GetIndexes() as well as one in GetDefinitions.
They should return NULL if you want to handle failure in the caller function
return NULL;
You erroneously use the sizeof operator to determine the number of char *** pointer allocated in
int indexcount = sizeof(dptr) / sizeof(char)
this will be either 4 or 8 depending on the architecture i.e. the size of a pointer divided by 1 sizeof(char) == 1 always.
You can't compute that value, you simply have to keep track of it. The size
You dereference the triple pointer twice and try to assign a double pointer to it
*dptr[i] = GetDefinitions();
here the operator precedence is also an issue, but regardless of that, this is wrong, may be what you meant was
dptr[i] = GetDefinitions();
This is not going to make your program crash, but it's certainly important to free all malloced pointers before exiting the program.
Here is a suggestion for your code to work, ignore it's purpose since it's not clear what you are trying to do
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char ***GetIndexes(unsigned int *count)
{
char ***index;
printf("please insert the number of words you want to add to dictionary > ");
scanf("%u", count);
index = calloc(*count, sizeof(*index));
if (index == NULL)
{
printf("allocation Failed");
return NULL;
}
return index;
}
char **GetDefinitions(unsigned int *count)
{
char **definition;
printf("please insert the number of defintions you want to add to the word > ");
scanf("%u", count);
definition = calloc(*count + 1, sizeof(*definition));
if (definition == NULL)
{
printf("allocation failed");
return NULL;
}
return definition;
}
int main()
{
unsigned int indexCount, i;
char ***dptr = GetIndexes(&indexCount);
if (dptr == NULL)
{
printf("memory Allocation failed");
}
for (i = 0; i < indexCount; i++)
{
unsigned int definitionsCount;
printf("Word number %u\n", i + 1);
dptr[i] = GetDefinitions(&definitionsCount);
if (dptr[i] != NULL)
{
/* use dptr[i] here or maybe somewhere else, but when you finish */
free(dptr[i]);
}
}
printf("%p", dptr);
/* now if you are done using dptr */
free(dptr);
return 0;
}
As already mentioned in the comment this is a very bad idea and just using double pointers is good here. But the below fixes should be done if you want to use pointers to allocate memory
index = calloc(n, sizeof(char));
should be
index = calloc(n, sizeof(char **));
and
definition = calloc(n+1, sizeof(char));
should be
definition = calloc(n+1, sizeof(char *));

How to replace the last index of a string using C language?

The code below tries to increment the last index in a string, eg: if label = "1_1_9", find_next_label (label ) will return "1_1_10".
This works. However, I also want to alter the original label, increment it as well. eg: if label = "1_1_9", find_next_label(label) will return "1_1_10" and during this procedure, label also becomes "1_1_10".
This code below is unable to do this. The result from main() function shows that label is still "1_1_9".
Could anyone help find where the problem is?
char * find_next_lable(char * label)
{
int length = strlen(label);
char * last_index = label + length - 1;
int num = atoi(last_index);
num = num + 1;
char * next_lable = malloc(sizeof(label));
strncpy(next_label, label, length-1);
*(next_label + length - 1) = '\0';
sprintf(next_label, "%s%d", next_label, num);
label = next_label;
return label;
}
int main()
{
char * s = malloc(6);
strcpy(s, "1_1_9");
char * n = find_next_label(s);
printf("%s\n", s);
printf("%s\n", n);
return 0;
}
The last_index() and atoi() code block assumes that the final number is only one digit long; clearly this is not very general. You could search for the last underscore instead, and convert a number from the character following that. Use strrchr() to look for the last underscore.
Also you must think a lot about buffer sizes and overruns, you should probably make the function accept the available buffer size as an additional argument especially if you want to modify the input. If you want that, there's of course no point in allocating additional space either, just return the input.
If you don't need to create a new string you can just do:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_LEN 20
int main()
{
char *s = malloc(MAX_LEN); /* You must have enough memory if the number of chars grows! */
char *n;
int i;
strcpy(s, "1_1_9");
printf("%s\n", s);
n = strrchr(s, '_'); /* find the last '_' */
n++; /* and move to the number */
i = atoi(n);
sprintf(n, "%d", i+1); /* write the new value instead of the old one */
printf("%s\n", s);
free(s);
return 0;
}
else you can have the function:
char * find_next_lable(char *label)
{
char *n, *next_lable = malloc(sizeof(MAX_LEN));
int i;
strcpy(next_lable, label);
n = strrchr(next_lable, '_');
n++;
i = atoi(n);
sprintf(n, "%d", i+1);
return next_lable;
}
The result from main() function shows that lable is still 1_1_9.
That's because you are not changing the dynamically allocated array pointed to by s in main. Instead, you allocate new memory in the function find_next_lable. Also,
sprintf(next_lable, "%s%d", next_lable, num);
won't work since %s conversion specifier means that sprintf will read from the buffer pointed to by next_lable till and including the terminating null byte.
You must allocate enough memory so as to contain the incremented integer part.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
// make sure MAX is large enough to
// contain the modified string
#define MAX 20
void find_next_lable(char *label);
int main(void)
{
char *s = malloc(MAX);
strcpy(s, "1_1_90");
printf("%s\n", s);
find_next_lable(s);
printf("%s\n", s); // prints 1_1_91
free(s);
return 0;
}
void find_next_lable(char *label)
{
// strrchr returns a pointer to the last
// occurrence of the character _ in label
char *last_index = strrchr(label, '_');
if(last_index == NULL)
{
last_index = label;
}
else
{
last_index++;
}
int num = atoi(last_index);
num = num + 1;
sprintf(last_index, "%d", num);
}

String (array) capacity via pointer

I am tring to create a sub-routine that inserts a string into another string. I want to check that the host string is going to have enough capacity to hold all the characters and if not return an error integer. This requires using something like sizeof but that can be called using a pointer. My code is below and I would be very gateful for any help.
#include<stdio.h>
#include<conio.h>
//#include "string.h"
int string_into_string(char* host_string, char* guest_string, int insertion_point);
int main(void) {
char string_one[21] = "Hello mother"; //12 characters
char string_two[21] = "dearest "; //8 characters
int c;
c = string_into_string(string_one, string_two, 6);
printf("Sub-routine string_into_string returned %d and creates the string: %s\n", c, string_one);
getch();
return 0;
}
int string_into_string(char* host_string, char* guest_string, int insertion_point) {
int i, starting_length_of_host_string;
//check host_string is long enough
if(strlen(host_string) + strlen(guest_string) >= sizeof(host_string) + 1) {
//host_string is too short
sprintf(host_string, "String too short(%d)!", sizeof(host_string));
return -1;
}
starting_length_of_host_string = strlen(host_string);
for(i = starting_length_of_host_string; i >= insertion_point; i--) { //make room
host_string[i + strlen(guest_string)] = host_string[i];
}
//i++;
//host_string[i] = '\0';
for(i = 1; i <= strlen(guest_string); i++) { //insert
host_string[i + insertion_point - 1] = guest_string[i - 1];
}
i = strlen(guest_string) + starting_length_of_host_string;
host_string[i] = '\0';
return strlen(host_string);
}
C does not allow you to pass arrays as function arguments, so all arrays of type T[N] decay to pointers of type T*. You must pass the size information manually. However, you can use sizeof at the call site to determine the size of an array:
int string_into_string(char * dst, size_t dstlen, char const * src, size_t srclen, size_t offset, size_t len);
char string_one[21] = "Hello mother";
char string_two[21] = "dearest ";
string_into_string(string_one, sizeof string_one, // gives 21
string_two, strlen(string_two), // gives 8
6, strlen(string_two));
If you are creating dynamic arrays with malloc, you have to store the size information somewhere separately anyway, so this idiom will still fit.
(Beware that sizeof(T[N]) == N * sizeof(T), and I've used the fact that sizeof(char) == 1 to simplify the code.)
This code needs a whole lot more error handling but should do what you need without needing any obscure loops. To speed it up, you could also pass the size of the source string as parameter, so the function does not need to calculate it in runtime.
#include <string.h>
#include <stdlib.h>
#include <stdio.h>
signed int string_into_string (char* dest_buf,
int dest_size,
const char* source_str,
int insert_index)
{
int source_str_size;
char* dest_buf_backup;
if (insert_index >= dest_size) // sanity check of parameters
{
return -1;
}
// save data from the original buffer into temporary backup buffer
dest_buf_backup = malloc (dest_size - insert_index);
memcpy (dest_buf_backup,
&dest_buf[insert_index],
dest_size - insert_index);
source_str_size = strlen(source_str);
// copy new data into the destination buffer
strncpy (&dest_buf[insert_index],
source_str,
source_str_size);
// restore old data at the end
strcpy(&dest_buf[insert_index + source_str_size],
dest_buf_backup);
// delete temporary buffer
free(dest_buf_backup);
}
int main()
{
char string_one[21] = "Hello mother"; //12 characters
char string_two[21] = "dearest "; //8 characters
(void) string_into_string (string_one,
sizeof(string_one),
string_two,
6);
puts(string_one);
return 0;
}
I tried using a macro and changing string_into_string to include the requirement for a size argument, but I still strike out when I call the function from within another function. I tried using the following Macro:
#define STRING_INTO_STRING( a, b, c) (string_into_string2(a, sizeof(a), b, c))
The other function which causes failure is below. This fails because string has already become the pointer and therefore has size 4:
int string_replace(char* string, char* string_remove, char* string_add) {
int start_point;
int c;
start_point = string_find_and_remove(string, string_remove);
if(start_point < 0) {
printf("string not found: %s\n ABORTING!\n", string_remove);
while(1);
}
c = STRING_INTO_STRING(string, string_add, start_point);
return c;
}
Looks like this function will have to proceed at risk. looking at strcat it also proceeds at risk, in that it doesn't check that the string you are appending to is large enough to hold its intended contents (perhaps for the very same reason).
Thanks for everyone's help.

Copying a file line by line into a char array with strncpy

So i am trying to read a text file line by line and save each line into a char array.
From my printout in the loop I can tell it is counting the lines and the number of characters per line properly but I am having problems with strncpy. When I try to print the data array it only displays 2 strange characters. I have never worked with strncpy so I feel my issue may have something to do with null-termination.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char* argv[])
{
FILE *f = fopen("/home/tgarvin/yes", "rb");
fseek(f, 0, SEEK_END);
long pos = ftell(f);
fseek(f, 0, SEEK_SET);
char *bytes = malloc(pos); fread(bytes, pos, 1, f);
int i = 0;
int counter = 0;
char* data[counter];
int length;
int len=strlen(data);
int start = 0;
int end = 0;
for(; i<pos; i++)
{
if(*(bytes+i)=='\n'){
end = i;
length=end-start;
data[counter]=(char*)malloc(sizeof(char)*(length)+1);
strncpy(data[counter], bytes+start, length);
printf("%d\n", counter);
printf("%d\n", length);
start=end+1;
counter=counter+1;
}
}
printf("%s\n", data);
return 0;
}
Your "data[]" array is declared as an array of pointers to characters of size 0. When you assign pointers to it there is no space for them. This could cause no end of trouble.
The simplest fix would be to make a pass over the array to determine the number of lines and then do something like "char **data = malloc(number_of_lines * sizeof(char *))". Then doing assignments of "data[counter]" will work.
You're right that strncpy() is a problem -- it won't '\0' terminate the string if it copies the maximum number of bytes. After the strncpy() add "data[counter][length ] = '\0';"
The printf() at the end is wrong. To print all the lines use "for (i = 0; i < counter; i++) printf("%s\n", data[counter]);"
Several instances of bad juju, the most pertinent one being:
int counter = 0;
char* data[counter];
You've just declared data as a variable-length array with zero elements. Despite their name, VLAs are not truly variable; you cannot change the length of the array after allocating it. So when you execute the lines
data[counter]=(char*)malloc(sizeof(char)*(length)+1);
strncpy(data[counter], bytes+start, length);
data[counter] is referring to memory you don't own, so you're invoking undefined behavior.
Since you don't know how many lines you're reading from the file beforehand, you need to create a structure that can be extended dynamically. Here's an example:
/**
* Initial allocation of data array (array of pointer to char)
*/
char **dataAlloc(size_t initialSize)
{
char **data= malloc(sizeof *data * initialSize);
return data;
}
/**
* Extend data array; each extension doubles the length
* of the array. If the extension succeeds, the function
* will return 1; if not, the function returns 0, and the
* values of data and length are unchanged.
*/
int dataExtend(char ***data, size_t *length)
{
int r = 0;
char **tmp = realloc(*data, sizeof *tmp * 2 * *length);
if (tmp)
{
*length= 2 * *length;
*data = tmp;
r = 1;
}
return r;
}
Then in your main program, you would declare data as
char **data;
with a separate variable to track the size:
size_t dataLength = SOME_INITIAL_SIZE_GREATER_THAN_0;
You would allocate the array as
data = dataAlloc(dataLength);
initially. Then in your loop, you would compare your counter against the current array size and extend the array when they compare equal, like so:
if (counter == dataLength)
{
if (!dataExtend(&data, &dataLength))
{
/* Could not extend data array; treat as a fatal error */
fprintf(stderr, "Could not extend data array; exiting\n");
exit(EXIT_FAILURE);
}
}
data[counter] = malloc(sizeof *data[counter] * length + 1);
if (data[counter])
{
strncpy(data[counter], bytes+start, length);
data[counter][length] = 0; // add the 0 terminator
}
else
{
/* malloc failed; treat as a fatal error */
fprintf(stderr, "Could not allocate memory for string; exiting\n");
exit(EXIT_FAILURE);
}
counter++;
You are trying to print data with a format specifier %s, while your data is a array of pointer s to char.
Now talking about copying a string with giving size:
As far as I like it, I would suggest you to use
strlcpy() instead of strncpy()
size_t strlcpy( char *dst, const char *src, size_t siz);
as strncpy wont terminate the string with NULL,
strlcpy() solves this issue.
strings copied by strlcpy are always NULL terminated.
Allocate proper memory to the variable data[counter]. In your case counter is set to 0. Hence it will give segmentation fault if you try to access data[1] etc.
Declaring a variable like data[counter] is a bad practice. Even if counter changes in the subsequent flow of the program it wont be useful to allocate memory to the array data.
Hence use a double char pointer as stated above.
You can use your existing loop to find the number of lines first.
The last printf is wrong. You will be printing just the first line with it.
Iterate over the loop once you fix the above issue.
Change
int counter = 0;
char* data[counter];
...
int len=strlen(data);
...
for(; i<pos; i++)
...
strncpy(data[counter], bytes+start, length);
...
to
int counter = 0;
#define MAX_DATA_LINES 1024
char* data[MAX_DATA_LINES]; //1
...
for(; i<pos && counter < MAX_DATA_LINES ; i++) //2
...
strncpy(data[counter], bytes+start, length);
...
//1: to prepare valid memory storage for pointers to lines (e.g. data[0] to data[MAX_DATA_LINES]). Without doing this, you may hit into 'segmentation fault' error, if you do not, you are lucky.
//2: Just to ensure that if the total number of lines in the file are < MAX_DATA_LINES. You do not run into 'segmentation fault' error, because the memory storage for pointer to line data[>MAX_DATA_LINES] is no more valid.
I think that this might be a quicker implementation as you won't have to copy the contents of all the strings from the bytes array to a secondary array. You will of course lose your '\n' characters though.
It also takes into account files that don't end with a new line character and as pos is defined as long the array index used for bytes[] and also the length should be long.
#include <stdio.h>
#include <stdlib.h>
#define DEFAULT_LINE_ARRAY_DIM 100
int main(int argc, char* argv[])
{
FILE *f = fopen("test.c", "rb");
fseek(f, 0, SEEK_END);
long pos = ftell(f);
fseek(f, 0, SEEK_SET);
char *bytes = malloc(pos+1); /* include an extra byte incase file isn't '\n' terminated */
fread(bytes, pos, 1, f);
if (bytes[pos-1]!='\n')
{
bytes[pos++] = '\n';
}
long i;
long length = 0;
int counter = 0;
size_t size=DEFAULT_LINE_ARRAY_DIM;
char** data=malloc(size*sizeof(char*));
data[0]=bytes;
for(i=0; i<pos; i++)
{
if (bytes[i]=='\n') {
bytes[i]='\0';
counter++;
if (counter>=size) {
size+=DEFAULT_LINE_ARRAY_DIM;
data=realloc(data,size*sizeof(char*));
if (data==NULL) {
fprintf(stderr,"Couldn't allocate enough memory!\n");
exit(1);
}
}
data[counter]=&bytes[i+1];
length = data[counter] - data[counter - 1] - 1;
printf("%d\n", counter);
printf("%ld\n", length);
}
}
for (i=0;i<counter;i++)
printf("%s\n", data[i]);
return 0;
}

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