I'm doing an exercise from KNKings book "C Programming: A modern approach" which involves converting a phone number in alphabetic form, entered by the user, into numeric form. When the program encounters non-alphabetic characters (digits or punctuations, for example), it should leave them unchanged. I may assume that the user only enters upper-case letters.
However, my program seems to produce garbage, to say the least.
#include <stdio.h>
#define MAX_SIZE 50
int main(void)
{
char alphabetic[MAX_SIZE], ch;
int num_elements = 0;
printf("Enter phone number: ");
int i;
for (i = 0; i < MAX_SIZE && ((ch = getchar()) != '\n'); i++){
alphabetic[i] = ch;
num_elements++;
}
for (i = 0; i <= num_elements; i++){
switch (alphabetic[i]){
case 'A': case 'B': case 'C': alphabetic[i] = '2'; break;
case 'D': case 'E': case 'F': alphabetic[i] = '3'; break;
case 'G': case 'H': case 'I': alphabetic[i] = '4'; break;
case 'J': case 'K': case 'L': alphabetic[i] = '5'; break;
case 'M': case 'N': case 'O': alphabetic[i] = '6'; break;
case 'P': case 'R': case 'S': alphabetic[i] = '7'; break;
case 'T': case 'U': case 'V': alphabetic[i] = '8'; break;
case 'W': case 'X': case 'Y': alphabetic[i] = '9'; break;
default: break;
}
}
printf("%s\n", alphabetic);
return 0;
}
In particular, I enter: COLLECT-800.
It outputs something like this: u░#■ ║k ╩
What did I do wrong?
You have the right idea, but there are two things missing in your program:
Most importantly, the null terminator at the end of the string. After your for loop in which you read the number, add the line:
alphabetic[i] = '\0';
If the user enters lowercase letters, they are ignored in the switch statement. To get around this, include <ctype.h> and change the switch quantity from alphabetic[i] to toupper(alphabetic[i]). Calling toupper on an already upper case letter is benign.
You're not putting a null-terminator anywhere so it's undefined behavior when you read the string regardless of whether you modified it afterwards. Put this line:
alphabetic[num_elements] = 0;
After your for (i = 0; i < MAX_SIZE &&... loop.
Personally, I wouldn't do the getchar loop and instead read in the string like this:
scanf("%49s", alphabetic); // reads in a string up to 50 characters
for (i = 0; alphabetic[i]; i++) { ...
Related
So i was trying to type this program but its keep failing , can anyone help with me ?
Write a function to return a nonzero if the character is a vowel(a, e, i, o, u – upper or lower case), or zero if it is not a vowel. Test the function in a program that allows input of string and a single character output of the characters in the string with the vowels enclosed with angle brackets as shown.
Sample Output
Enter a name: Aloysius
Result: [A]l[o]ys[i][u]s
Note: Bold text above is the input
#include <stdio.h>//Question 1
#include <string.h>
int check_vowel();
char string[300];
int idx;
int length,status;
int main(void) {
printf("Enter a word: ");;
scanf("%s",string);
length=strlen(string)-1;
for(idx=0;idx<=length;idx++)
{
status=check_vowel();
if(status==1)
printf("<%c>",string[idx]);
else
printf("%c",string[idx]);
}
return 0;
}
int check_vowel()
{
length=strlen(string)-1;
for(idx=0;idx<=length;idx++)
{
switch(string[idx])
{
case 'A': return 1; break;
case 'a': return 1; break;
case 'e': return 1; break;
case 'E': return 1; break;
case 'I': return 1; break;
case 'i': return 1; break;
case 'o': return 1; break;
case 'O': return 1; break;
case 'u': return 1; break;
case 'U': return 1; break;
}
}
return 0;
}
Remove the for loop from check_vowel. Have it take a single argument, a char:
int check_vowel(char c)
{
int is_vowel;
switch(c)
{
case 'a':
case 'A':
case 'e':
case 'E':
case 'i':
case 'I':
case 'o':
case 'O':
case 'u':
case 'U':
is_vowel = 1;
break;
default:
is_vowel = 0;
break;
}
return is_vowel;
}
Call check_vowel from main in a for loop for every char in string:
for(idx = 0; idx <= strlen(string); idx++)
{
status = check_vowel(string[idx]);
...
}
how to write a program to check whether there is vowel, if yes , make the vowel character with two angle bracket like <A> <E> <i> ..... etc . if without vowel leave it , so the display should look like this <A> l <o> y s <i> <u> s. The function should return a nonzero if the character is a vowel(a, e, i, o, u – upper or lower case), or zero if it is not a vowel
The function you created will check if the string contains any vowel.
Part of my project, where we have to take an input file with hex numbers and convert them to MIPS code, I want to convert the hex into binary so it'd be easier for me to convert it into MIPS. However, when I run the code, it crashes and quits when it reaches the part where it calls the converter function. GDB says its a critical error c0000374. How do I fix this?
I have tried giving the target string more space and it doesn't seem to have any effect. I have also tried using malloc to no avail.
char* convertBinary (int hex)
{
char* hexdec = calloc(9, sizeof(char));
char* bin = calloc(SIZE+1, sizeof(char));
snprintf(hexdec, SIZE, "%08X", hex);
long int i;
for (i = 0; hexdec[i]; ++i)
{
switch (hexdec[i])
{
case '0':
strcat(bin, "0000");
break;
case '1':
strcat(bin, "0001");
break;
case '2':
strcat(bin, "0010");
break;
case '3':
strcat(bin, "0011");
break;
case '4':
strcat(bin, "0100");
break;
case '5':
strcat(bin, "0101");
break;
case '6':
strcat(bin, "0110");
break;
case '7':
strcat(bin, "0111");
break;
case '8':
strcat(bin, "1000");
break;
case '9':
strcat(bin, "1001");
break;
case 'A':
case 'a':
strcat(bin, "1010");
break;
case 'B':
case 'b':
strcat(bin, "1011");
break;
case 'C':
case 'c':
strcat(bin, "1100");
break;
case 'D':
case 'd':
strcat(bin, "1101");
break;
case 'E':
case 'e':
strcat(bin, "1110");
break;
case 'F':
case 'f':
strcat(bin, "1111");
break;
default:
printf("\nInvalid hexadecimal digit %c",
hexdec[i]);
}
}
return bin;
}
Also, in case it helps, here is the main function where I call this function
int main ()
{
int command = 10010100; //This is in hex
char* binaryString = convertBinary(command);
printf("The coverted binary is: %s\n", binaryString);
}
I expect the function to return a string of the binary numbers that have been converted from an 8 digit hex number. However, the program just quits and doesn't output anything. When debugged with GDB, it lays out a warning saying,
warning: Critical error detected c0000374
There are multiple problems in your code:
You do not check the for memory allocation failure.
Since you allocate 9 bytes for hexdec, snprintf(hexdec, SIZE, "%08X", hex); should be
snprintf(hexdec, 9, "%08X", hex);
The definition of SIZE is missing, as well as the #include lines. Post the complete source of the program exhibiting the offending behavior.
There is no need to loop until the end of the string hexdec: since you convert the hex value with %08X, just loop with:
for (i = 0; i < 8; ++i)
You should free(hexdec) before leaving the convertBinary function.
The code and comment do not agree in int command = 10010100; //This is in hex, which one is wrong? Probably both.
There is no need to use long type for i, int will suffice. Conversely, the argument hex should have unsigned int type.
Here is a simplified version of your code:
#include <stdio.h>
#include <stdlib.h>
char *convertBinary(unsigned int hex) {
char *bin = calloc(33, 1);
int i;
if (bin) {
for (i = 32; i-- > 0;) {
bin[i] = '0' + (hex & 1);
hex >>= 1;
}
}
return bin;
}
int main() {
int command = 0x10010100; //This is in hex
char *binaryString = convertBinary(command);
if (binaryString == NULL) {
printf("Memory allocation failure\n");
} else {
printf("The converted binary is: %s\n", binaryString);
free(binaryString);
}
return 0;
}
Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 4 years ago.
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I'm getting output of a - 0000520 when I input a while i should get 0001010 as per the code I've assigned. Also the default runs every time (tested using a printf statement) for unexplained reason. My code is here:
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int splitWord(char* word, int count);
int sunCode(char letter);
int main()
{
char inputString[100];
char splitStrings[10][10];
int i, j, count;
printf("Enter the message.\n");
fgets(inputString, 100, stdin);
j = count = 0;
for (i = 0; i <= (strlen(inputString)); i++) {
if (inputString[i] == ' ' || inputString[i] == '\0') {
splitStrings[count][j] = '\0';
count++;
j = 0;
}
else {
splitStrings[count][j] = inputString[i];
j++;
}
}
printf("\nOriginal String is: %s\n", inputString);
for (i = 0; i < count; i++) {
/*for(j=0;j<=strlen(splitStrings[i]);j++){
printf("%s",splitStrings[i][j]);
}*/
splitWord(splitStrings[i], count);
}
return 0;
}
int splitWord(char* word, int count)
{
int i;
int strLength = strlen(word);
for (i = 0; i <= strLength; i++) {
sunCode(word[i]);
// printf("%c\n",word[i]);
}
return 0;
}
int sunCode(char letter)
{
char letr = tolower(letter);
int code = 0;
switch (letr) {
case '0':
code = 0000000;
break;
case '1':
code = 0000001;
break;
case '2':
code = 0000010;
break;
case '3':
code = 0000011;
break;
case '4':
code = 0000100;
break;
case '5':
code = 0000101;
break;
case '6':
code = 0000110;
break;
case '7':
code = 0000111;
break;
case '8':
code = 0001000;
break;
case '9':
code = 0001001;
break;
case 'a':
code = 0001010;
break;
case 'b':
code = 0001011;
break;
case 'c':
code = 0001100;
break;
case 'd':
code = 0001101;
break;
case 'e':
code = 0001110;
break;
case 'f':
code = 0001111;
break;
case 'g':
code = 0010000;
break;
case 'h':
code = 0010001;
break;
case 'i':
code = 0010010;
break;
case 'j':
code = 0010011;
break;
case 'k':
code = 0010100;
break;
case 'l':
code = 0010101;
break;
case 'm':
code = 0010110;
break;
case 'n':
code = 0010111;
break;
case 'o':
code = 0011000;
break;
case 'p':
code = 0011001;
break;
case 'q':
code = 0011010;
break;
case 'r':
code = 0011011;
break;
case 's':
code = 0011100;
break;
case 't':
code = 0011101;
break;
case 'u':
code = 0011110;
break;
case 'v':
code = 0011111;
break;
case 'w':
code = -010000;
break;
case 'x':
code = 010001;
break;
case 'y':
code = 010010;
break;
case 'z':
code = 010011;
break;
case ' ':
code = 45;
printf("\nis space\n");
break;
default:
break;
}
printf("%c - %07d\n", letr, code);
}
I tried to see if it's giving ASCII values (it isn't)
the letter is being passed properly in the sunCode function (it is)
I do not understand why it is behaving like this, verified the syntax and conditions of switch too.
I am using gcc 7.3.0 on Ubuntu.
Leading zeros indicate that the number is expressed in octal, or base 8; thus, 010 = 8.
https://stackoverflow.com/a/1661378/10479742
0001010 in octal is 520 in decimal, and that's why you get that result. Either remove leading zeros, or change code to string.
In the following program, I need to change the initial and final characters to their respective characters as mentioned below in case but this is giving me an infinite loop. What should I do to fix it?
int main(void)
{
char state ='t';
char word[20]="aaabbccaaaaccbbb";
int initiallength = strlen(word)-1; strcat(word,"a");
while(strlen(word)-1 >initiallength)
{
switch(state)
{
case 't':
switch(word[strlen(word)-1])
{
case 'a':
word[strlen(word)-1]='b'; break;
case 'b':
word[strlen(word)-1]='c'; break;
case 'c':
word[strlen(word)-1]='d'; break;
case 'd':
word[strlen(word)-1]='\0'; break;
}
switch(word[0])
{
case 'a':
word[0]='b'; break;
case 'b':
word[0]='c'; break;
case 'c':
word[0]='d'; break;
case 'd':
word[0]='\0'; break;
}
}
}
}
If I understand correctly what you want to do is swap the first and last characters in the given string. If that's the case first your code is way too complicated and second the reason you're getting an infinite loop is because the condition strlen(word)-1 >initiallength is always true.
Test if word is empty
int main(void){
char state ='t';
char word[20]="aaabbccaaaaccbbb";
int initiallength = strlen(word)-1;
strcat(word,"a");
while(strlen(word)-1 >initiallength && strlen(word) >= 0){
printf("%d %d\n", strlen(word)-1, initiallength);
printf("%d len %s\n", strlen(word), word);
switch(state){
case 't':
switch(word[strlen(word)-1]){
case 'a':
case 'b':
case 'c':
word[strlen(word)-1]++;
break;
case 'd':
word[strlen(word)-1] = '\0';
break;
}
switch(word[0]){
case 'a':
case 'b':
case 'c':
word[0]++;
break;
case 'd':
word[0] = '\0';
break;
}
}
}
}
I am trying to make a switch statement that takes in a word into an array and then throws each letter through a switch statement and allocates a point to each letter depending on which letter it is and giving a final point value for the word, and I can't seem to get the array part right. Any help would be appreciated!
int main(){
int letter_points = 0;
char word[7];
int word_length = 7;
int i;
printf("Enter a Word\n");
scanf("%s", word);
for(i = 0; i < word_length; i++){
switch(word){
//1 point
case 'A':
case 'E':
case 'I':
case 'L':
case 'N':
case 'O':
case 'R':
case 'S':
case 'T':
case 'U':
letter_points++;
break;
//2 points
case 'D':
case 'G':
letter_points += 2;
break;
//3 points
case 'B':
case 'C':
case 'M':
case 'P':
letter_points += 3;
break;
//4 points
case 'F':
case 'H':
case 'V':
case 'W':
case 'Y':
letter_points += 4;
break;
//5 points
case 'K':
letter_points += 5;
break;
//8 points
case 'J':
case 'X':
letter_points += 8;
break;
//10 points
case 'Q':
case 'Z':
letter_points += 10;
break;
}
}
printf("%d\n", letter_points);
return;
}
It would probably be faster to have a lookup array:
int const letter_score[26] = { 1, 2, 1, 3, ..., 10 };
/* key: A B C D Z */
score += letter_score[c - 'A']; // or "toupper(word[i]) - 'A'"
Caveat: this requires an encoding in which the upper-case letters are arranged contiguously, such as Unicode or ASCII.
Try using this
switch(word[i]){
in the switch statement. As it stands, you are not testing each element in your array even though you are iterating over the range of the array. Having said that I would go for the approach suggested by Kerrek SB in the other answer. This is much neater and more compact.
The variable word is an array, but you want to switch on each character. Thus, you need:
switch(word[i])
In C, you cannot use arrays in switch (and expressions for case). Also, the type passed to switch() and types specified in each case must match. So the most you can do is switch on a character. You almost got it right though, except that you are passing the whole array into switch. Use index to reference a character instead. For example:
switch (word[i]) {
...
}
You have word as an array of size7, you cannot switch on the array, you have to swicth on each character of the array so use:
switch(word[i])