I want to create a function to find a DateTime format of string type.
For Example: -
I have a string as '07/09/2016 12:00 AM' and want it in DateTime format of this string and it should be like : - MM/dd/yyyy hh:mm tt format.
So, when I pass the DateTime as string to this function then function returns me a DateTime format using SQL function.
We can try using TRY_CONVERT to convert your date string into a bona fide datetime. Then, we can use FORMAT to display the datetime in the format you want to see.
SELECT FORMAT(TRY_CONVERT(datetime, '07/09/2016 12:00 AM'),
'MM/dd/yyyy hh:mm tt', 'en-US')
07/09/2016 12:00 AM
Demo
Try this i hope this will work for you
SELECT CAST(GETDATE() AS VARCHAR(19))
Also try this
SELECT CONVERT(VARCHAR(10),GETDATE(), 101) + right(CONVERT(VARCHAR(32),GETDATE(),100),8)
Related
I have string date 19-feb-01 wherein the 19 is the year 2019, that I need to convert to format yyyy-mm-dd (2019-02-01) but I am struggling with the formatting.
DECLARE #Date_str VARCHAR(50) = '19-feb-01';
SELECT CAST ('20' + #Date_str AS DATE) AS Date
I want a datetime string till minute from Datetime in sql server. Means I want to extract string after minute from Datetime from sql server.
Like: 2011-11-02 13:35:14.613
and I want this from above datetime string -
2011-11-02 13:35
Try this, will give you the date in format yyyy-mm-dd hh:mm as a string.
SELECT CONVERT(CHAR(16),'2011-11-02 13:35:14.613',120)
You can use your column name instead of the static date.
Your problem is a bit tricky, because the default formats which CONVERT() offers do not match your expected output. However, format style 120 has the following format:
yyyy-mm-dd hh:mm:ss
This is almost what you want, minus the :ss at the end. To get rid of that, you can just SUBSTRING() it off after calling CONVERT():
SELECT SUBSTRING(CONVERT(VARCHAR, yourDateColumn, 120), 1, 16)
I have a column which is of datetime type.
I want to separate date and time for which i used left() & right() enclosed by cast() or convert() like below :
Select BATCH,
LEFT( CAST(S_DATE AS VARCHAR(20)),12) AS ST_DATE,
RIGHT( CAST(S_DATE AS VARCHAR(20)),8) AS ST_TIME,
LEFT( CAST(E_DATE AS VARCHAR(20)),12) AS E_DATE,
RIGHT( CAST(E_DATE AS VARCHAR(20)),8) AS E_TIME
INTO CRYST2
From Z_BATCH;
this is my actual format for datetime column :-
2015-10-01 14:00:00.000
But the problem is that it is separating the date and time accurately but it isn't returning the output in string form, as the output itself turns to date & time format respectively in their respective columns.
Following is the output I am getting:-
1 Oct 1 2015 2:00PM Oct 1 2015 2:30PM
As you can clearly see the columns I separated after date-time to string conversion is still giving me output in some date-time format only.
please help regarding it.
this is my actual format for datetime column :
2015-10-01 14:00:00.000
No, it's not. A datetime value doesn't have a format at all, it only represents a point in time. It only gets a format when you convert it to a string.
You are not specifying any format at all when you convert the datetime values, so it will be using the default format (0). You can use the format that you saw the datetime values displayed as (121) to get the desired result:
Select BATCH,
LEFT( CAST(S_DATE AS VARCHAR(19),121),10) AS ST_DATE,
RIGHT( CAST(S_DATE AS VARCHAR(19),121),8) AS ST_TIME,
LEFT( CAST(E_DATE AS VARCHAR(19),121),10) AS E_DATE,
RIGHT( CAST(E_DATE AS VARCHAR(19),121),8) AS E_TIME
INTO CRYST2
From Z_BATCH;
Cast The date and the Time in the exact format like:
CAST(S_DATE AS Time) AS ST_TIME
CAST(S_DATE AS Date) AS ST_Date
will return:
14:00:00
2015-10-01
Use CONVERT with format 120 to get the desired result, it always return the format yyyy-MM-dd hh:mm:ss
CONVERT(varchar(20), S_DATE, 120)
You can try this, if you want to get results in string format:
select convert(varchar(11),cast(S_DATE as date),106)
select convert(varchar(11),cast(S_DATE as time),100)
If you try to get answers in date and time format, try this:
CAST(S_DATE AS Time) AS ST_TIME
CAST(S_DATE AS Date) AS ST_Date
I'm trying to convert a varchar field to datetime. The data in the varchar field looks like this dd/mm/yyyy hh.mm AM/PM.
I'm actually trying to extract the date part & time part and convert them to date and time respectively.
And I use the below query to extract the date part from the varchar and convert it to date.
SELECT DISTINCT LEFT([Start Date], 10)
,CASE WHEN ISDATE(LEFT([Start Date], 10)) = 1
THEN CONVERT(DATETIME, LEFT([Start Date], 10), 120)
END
,ISDATE(LEFT([Start Date], 10))
FROM [dbo].[TestTable]
I have timestamp in the format mentioned above for entire August.
But the query gives me the result in yyyy-dd-mm format and the date are converted to date format only till 12 Aug'15. Date after 12 of Aug is null. I know it's because, in the case statement they are returned 0. How can I convert those values also to date?
Any suggestions to convert all the values to yyyy-mm-dd hh:mm:ss will be very helpful.
Thanks in advance.
You could use SET DATEFORMAT as lad2025 suggested.
SET DATEFORMAT dmy
Or you can use the following in your CONVERT()
DECLARE #date VARCHAR(16) = '13/08/2015 11:13';
SELECT CONVERT(DATETIME, #date, 103)
103 is the code for dd/mm/yyyy.
How to turn DD/MM/YYYY 00:00:0000 to MM/YYYY and keep it as date format and not string in MS SQL
i have tried many options but still did not find the right one.
Simply you cannot keep date as mm/yyyy as a date/datetime. But you could keep it as a string and also convert when needed back to a date as below.
Sql-Server Fiddle Example
declare #dt datetime = getdate(),
#mmyyyy varchar(7)
--To format as mm/yyyy
select #mmyyyy = right(convert(varchar(10), #dt, 103),7)
--To convert back to datetime type from mm/yyyy varchar
select #mmyyyy [mm/yyyy],
convert(datetime,'01/'+ #mmyyyy,103) back_To_Date