Minimum and Maximum of an array using pthreads in C - c

I'm having an issue with my code. Disclaimer btw, I'm new to C. Trying to learn it on my own. Anyways, I'm trying to get the minimum and maximum of an array. I broke the array into 4 parts to make 4 separate arrays and then used those 4 to pass in one of the parameters of each thread. With that being said, I'm only able to get the maximum for each part of the array and not the minimum and I don't understand why.

I think we can simplify your code, avoid all these unnecessary malloc calls, and simplify your algorithm for finding a min/max pair in an array.
Start by having a thread function that takes as input the following: an array (represented by a pointer), an index into the array from where to start searching on, and an index in the array on where to stop. Further, this function will need two output parameters - smallest and largest integer found in the array subset found.
Start with the parameter declaration. Similar to your MaxMin, but has both input and output parameters:
struct ThreadParameters
{
// input
int* array;
int start;
int end;
// output
int smallest;
int largest;
};
And then a thread function that scans from array[start] all the way up to (but not including) array[end]. And it puts the results of its scan into the smallest and largest member of the above struct:
void* find_min_max(void* args)
{
struct ThreadParameters* params = (struct ThreadParameters*)args;
int *array = params->array;
int start = params->start;
int end = params->end;
int smallest = array[start];
int largest = array[start];
for (int i = start; i < end; i++)
{
if (array[i] < smallest)
{
smallest = array[i];
}
if (array[i] > largest)
{
largest = array[i];
}
}
// write the result back to the parameter structure
params->smallest = smallest;
params->largest = largest;
return NULL;
}
And while we are at it, use capitol letters for your macros:
#define THREAD_COUNT 4
Now you can keep with your "4 separate arrays" design. But there's no reason to since the thread function can scan any range of any array. So let's declare a single global array as follows:
#define ARRAY_SIZE 400
int arr[ARRAY_SIZE];
The capitol letter syntax is preferred for macros.
fillArray becomes simpler:
void fillArray()
{
for (int i = 0; i < ARRAY_SIZE; i++)
{
arr[i] = rand() % 1000 + 1;
}
}
Now main, becomes a whole lot simpler by doing these techniques.:
We'll leverage the stack to allocate our thread parameter structure (no malloc and free)
We'll simply start 4 threads - passing each thread a pointer to a ThreadParameter struct. Since the thread won't outlive main, this is safe.
After starting each thread, we just wait for each thread to finish)
Then we scan the list of thread parameters to get the final smallest and largest.
main becomes much easier to manage:
int main()
{
int smallest;
int largest;
// declare an array of threads and associated parameter instances
pthread_t threads[THREAD_COUNT] = {0};
struct ThreadParameters thread_parameters[THREAD_COUNT] = {0};
// intialize the array
fillArray();
// smallest and largest needs to be set to something
smallest = arr[0];
largest = arr[0];
// start all the threads
for (int i = 0; i < THREAD_COUNT; i++)
{
thread_parameters[i].array = arr;
thread_parameters[i].start = i * (ARRAY_SIZE / THREAD_COUNT);
thread_parameters[i].end = (i+1) * (ARRAY_SIZE / THREAD_COUNT);
thread_parameters[i].largest = 0;
pthread_create(&threads[i], NULL, find_min_max, &thread_parameters[i]);
}
// wait for all the threads to complete
for (int i = 0; i < THREAD_COUNT; i++)
{
pthread_join(threads[i], NULL);
}
// Now aggregate the "smallest" and "largest" results from all thread runs
for (int i = 0; i < THREAD_COUNT; i++)
{
if (thread_parameters[i].smallest < smallest)
{
smallest = thread_parameters[i].smallest;
}
if (thread_parameters[i].largest > largest)
{
largest = thread_parameters[i].largest;
}
}
printf("Smallest is %d\n", smallest);
printf("Largest is %d\n", largest);
}

Related

Find the most frequent elements in an array of Integers

I have to find all of the elements which have the maximum frequency. For example, if array a={1,2,3,1,2,4}, I have to print as 1, also 2. My code prints only 2. How to print the second one?
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define n 6
int main(){
int a[n]={1,2,3,1,2,4};
int counter=0,mostFreq=-1,maxcnt=0;
for(int i=0;i<n;i++){
for(int j=i+1;j<n;j++){
if(a[i]==a[j]){
counter++;
}
}
if(counter>maxcnt){
maxcnt=counter;
mostFreq=a[i];
}
}
printf("The most frequent element is: %d",mostFreq);
}
How to print the second one?
The goal it not only to print a potential 2nd one, but all the all of the elements which have the maximum frequency.
OP already has code that determines the maximum frequency. Let us build on that. Save it as int target = mostFreq;.
Instead of printing mostFreq, a simple (still O(n*n)) approach would perform the same 2-nested for() loops again. Replace this 2nd:
if(counter>maxcnt){
maxcnt=counter;
mostFreq=a[i];
}
With:
if(counter == target){
; // TBD code: print the a[i] and counter.
}
For large n, a more efficient approach would sort a[] (research qsort()). Then walk the sorted a[] twice, first time finding the maximum frequency and the 2nd time printing values that match this frequency.
This is O(n* log n) in time and O(n) in memory (if a copy of the original array needed to preserve the original). If also works well with negative values or if we change the type of a[] from int to long long, double, etc.
The standard student solution to such problems would be this:
Make a second array called frequency, of the same size as the maximum value occurring in your data.
Init this array to zero.
Each time you encounter a value in the data, use that value as an index to access the frequency array, then increment the corresponding frequency by 1. For example freq[value]++;.
When done, search through the frequency array for the largest number(s). Optionally, you could sort it.
We can (potentially) save some effort in an approach with unsorted data by creating an array of boolean flags to determine whether we need to count an element at all.
For the array {1, 2, 3, 1, 2, 4} we do have nested for loops, so O(n) complexity, but we can avoid the inner loop entirely for repeated numbers.
#include <stdio.h>
#include <stdbool.h>
int main(void) {
int arr[] = {1, 2, 3, 1, 2, 4};
size_t arr_size = sizeof(arr) / sizeof(*arr);
bool checked[arr_size];
for (size_t i = 0; i < arr_size; i++) checked[i] = false;
unsigned int counts[arr_size];
for (size_t i = 0; i < arr_size; i++) counts[i] = 0;
for (size_t i = 0; i < arr_size; i++) {
if (!checked[i]) {
checked[i] = true;
counts[i]++;
for (size_t j = i+1; j < arr_size; j++) {
if (arr[i] == arr[j]) {
checked[j] = true;
counts[i]++;
}
}
}
}
unsigned int max = 0;
for (size_t i = 0; i < arr_size; i++) {
if (counts[i] > max) max = counts[i];
}
for (size_t i = 0; i < arr_size; i++) {
if (counts[i] == max)
printf("%d\n", arr[i]);
}
return 0;
}

How to print the sum of a passing a int array as a parameter

#include <stdio.h>
int sumofArrayNum(int numList[]);
int main(){
int result,numList[]={23,32,54,23,54,32,3,35};
result = sumofArrayNum(numList);
printf("sum= %d", result);
return 0;
}
int sumofArrayNum(int numList[]){
int sum = 0;
for(int i = 0; i < 10; ++i){
sum += numList[i];
}
return sum;
}
Output is different each time I build and run it.
E.g. output is sum = 1032918821
Expected output I would like is sum = 256
Parameters like int numList[] is the same as int* numList, compiler will not know elements count of it if it was not explicitly defined. By the way, int numList[8] is also the same as int* numList. C language does not check the range of array.
There are some ways to get and check the array size.
size/count parameter
int sumofArrayNum(int numList[], int listSize){
int sum = 0;
for(int i = 0; i < listSize; ++i){
sum += numList[i];
}
return sum;
}
Here listSize should be the count of elements.
And you can use macro to hide the count parameter:
#define sumofArray(array) sumofArrayNum((array), sizeof(array)/sizeof(*array))
point to the whole array
int sumofArrayNum(int (*numList)[8]){
int sum = 0;
for(int i = 0; i < sizeof(*numList)/sizeof(**numList); ++i){
sum += (*numList)[i];
}
return sum;
}
Call it by sending pointer of array:
result = sumofArrayNum(&numList);
Compiler(such as gcc) can do a weak check for this: give a warning if you send an array which are not int (*)[8].
Note that you have to ensure validity of array, and array size must be constant.
Besides,
Output is different each time I build and run it.
It is because only 8 elements has been defined, index range is 0〜7. numList[8] and numList[9] is undefined, mean any value is possible. Maybe used, changed by other process, random and dangerous.
In numlist there are 8 element that means for loop must execute code 8 times.
Your code must be:
for(int i = 0; i < 8; ++i)
{
sum += numList[i];
}
This code iterate until i=7, when i=8 it will end the loop.
Information on for loop

Issue with dynamic memory allocation in C

I am trying to implement a sort function (counting sort, it is probably wrong):
void countingsortmm(int* numbers, int len, int min, int max) {
printf("Sorting %d integers with the min: %d and max: %d\n",len,min,max);
int countLen = max-min+1;
/* create an array to store counts for the occurences of a number. */
int* countingArray = (int*)malloc(countLen);
/* init all values to 0 */
for(int i = 0; i < countLen; i++) countingArray[i] = 0;
/* increment at indexes where a number occurs */
for(int i = 0; i < len; i++) countingArray[numbers[i]]++;
/* add previous indexes */
for(int i = 1; i < countLen; i++) countingArray[i] += countingArray[i-1];
/* Array where numbers will be places in a sorted order. */
int* sortedArray = (int*)malloc(len);
/* put numbers in proper place in new array and decrement */
for(int i = len-1; i >= 0; i--) sortedArray[countingArray[numbers[i]]--] = numbers[i];
/* copy contents of new sorted array to the numbers parameter. */
for(int i = 0; i < len-1; i++) numbers[i] = sortedArray[i];
free(sortedArray);
free(countingArray);
}
But I get the following error:
malloc: *** error for object 0x7f8728404b88: incorrect checksum for freed object - object was probably modified after being freed.
I get a break-point at int* sortedArray = (int*)malloc(len);.
I use malloc() twice to create two different arrays within the function and I free() them both at the end of the function when they are no longer needed. I do not explicitly modify or access their contents afterwards.
So what is causing this problem?
It means you're corrupting your heap. Perhaps you meant malloc(countLen * sizeof(int)); and malloc(len * sizeof(int));? malloc takes its size in bytes.

issue with a sort method (C)

I'm having issues with a sort method I wrote. It is supposed to find the max value, and replace the last value in the array with the max (and move that value to where the last value was).
I've ran gdb, and it looks like the if statement always executes, and for some reason max = values[0] always sets max to 0. Granted I am very new to C so I might be wrong about what is going on.
/**
* Sorts array of n values.
*/
void sort(int values[], int n)
{
// TODO: implement an O(n^2) sorting algorithm
int max; //hold the max value through the iteration
int replaced; //to hold the value at the end of the array
int replacedhash; //to hold the location of the max value
do
{
replaced = values[n];
max = values[0]; //reset max to 0 for new iteration
for(int i = 0; i<n ; i++)
{
//check if the next value is larger,
//then update max and replacedhash if it is
if (max < values[i])
{
max = values[i];
replacedhash = i;
}
}
values[replacedhash] = replaced; //next three lines swap the values
n--;
values[n] = max;
} while (n!=0);
}
And I would use this by running:
int main() {
int test[] = {3,5,2,5,6,100,4,46};
sort(test, 8);
printarray(test, 8);
}
Error 1: replaced = values[n-1];
Your example in the problem statement is:
int test[] = {3,5,2,5,6,100,4,46};
sort(test, 8);
So you'll then look at test[8], which is undefined behavior
Error 2: replacedhash
replacedhash will be uninitialized if the first element of the array is the max. And it will probably have an incorrect value on later loops when the first element is the max.
My thoughts:
It appears to me that you've overcomplicating the code. You probably should just find the index in the array that has the maximum value, and then do the swap. It'll be simpler.
void sort(int values[], int n) {
do {
// Find index of maximum value
int max = 0;
for(int i=0; i<n; i++)
if (values[max] < values[i])
max = i;
// Swap
int temp = values[max];
values[max] = values[n-1];
values[n-1] = temp;
n--;
} while (n != 0);
}

C Max Numbers In An Array Algorithm

So, I'm just working on C code, particularly a function which accepts 3 arguments: an array, the size of the array, and the number of max elements you want returned.
Here's my code:
int* findMaxElements(int base_array[],int size_of_base_array, int number_of_elements_to_find);
int main( void )
{
printf("Find Max Values in an Array\n\n");
// Set up array
int kinch[6] = {1,2,3,4,5,6};
// Pass to function and get a pointer to new array filled with only the max elements
int *given = findMaxElements(kinch,6,3);
for(int i = 0; i < 3; i++)
{
printf("\nMax Value = %d\n", *(given + i));
}
return 0;
}
int* findMaxElements(int base_array[],int size_of_base_array, int number_of_elements_to_find)
{
// Set up all initial variables
int i,k,c,position;
int maximum = 0;
int returnArray[100];
/*Actual Algorythm */
for(i = 0; i < number_of_elements_to_find; i++)
{
// Get the max value in the base array
for(k = 0; k < size_of_base_array; k++)
{
if(base_array[k] > maximum)
{
maximum = base_array[k];
}
}
// Find the position of the max value
for(position = 0; position < size_of_base_array; position++)
{
if(base_array[position] == maximum)
{
break;
}
}
// Delete the maximum value from the array and shift everything
for(c = position - 1; c < size_of_base_array - 1; c++)
{
base_array[c] = base_array[c+1];
}
// Reduce the size of the array
size_of_base_array -= 1;
// Push max value into return array
returnArray[i] = maximum;
// Reset max value
maximum = 0;
}
return returnArray;
}
I have a feeling somewhere in the function something goes wrong.
// Set up array
int kinch[6] = {1,2,3,4,5,6};
// Pass to function and get a pointer to new array filled with only the max elements
int *given = findMaxElements(kinch,6,3);
for(int i = 0; i < 3; i++)
{
printf("\nMax Value = %d\n", *(given + i));
}
This should output the numbers 6, 5, and 4, because they are the three largest in the array, however the output I get is always 6, 6, and 6. What's wrong with it?
This may not be your only problem, but in the lines
for(c = position - 1; c < size_of_base_array - 1; c++)
{
base_array[c] = base_array[c+1];
}
You copy the element at [c+1] (which is the maximum) to [c] - so you keep finding the max...
You should start the loop with c = position, not c = position - 1.
And add keyword static in front of the array you use to store the return values, so they remain valid (this is one way to address the issue that Jonathan Leffler identified).
One problem is that you are returning a pointer to a local variable, returnArray, in the function. You can't do that reliably — it leads to undefined behaviour.
There may well be other problems too, but that's enough to be a show-stopper on its own.
The whole approach to find the Kth largest element is not efficient and elegant. I will suggest you to modify your algorithm, although with above suggestions it will work fine, but it's not good way to solve this problem.
I will suggest you to look into below link to modify your algorithm
http://www.geeksforgeeks.org/k-largestor-smallest-elements-in-an-array/

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