Read numbers from txt file second line in a C Array - c

Question

I do have a txt file which looks like this
10
41 220 166 29 151 47 170 60 234 49
How can I read only the numbers from the second row into an array in C?
int nr_of_values = 0;
int* myArray = 0;
FILE *file;
file = fopen("hist.txt", "r+");
if (file == NULL)
{
printf("ERROR Opening File!");
exit(1);
}
else {
fscanf(file, "%d", &nr_of_values);
myArray = new int[nr_of_values];
// push values from second row to this array
}

Answer 1

How can I read only the numbers from the second row into an array in C?
Ignore the first line by reading and discarding it.
You could use something like that:
#include <stddef.h>
#include <stdlib.h>
#include <stdio.h>
int main(void)
{
char const *filename = "test.txt";
FILE *input_file = fopen(filename, "r");
if (!input_file) {
fprintf(stderr, "Couldn't open \"%s\" for reading :(\n\n", filename);
return EXIT_FAILURE;
}
int ch; // ignore first line:
while ((ch = fgetc(input_file)) != EOF && ch != '\n');
int value;
int *numbers = NULL;
size_t num_numbers = 0;
while (fscanf(input_file, "%d", &value) == 1) {
int *new_numbers = realloc(numbers, (num_numbers + 1) * sizeof(*new_numbers));
if (!new_numbers) {
fputs("Out of memory :(\n\n", stderr);
free(numbers);
return EXIT_FAILURE;
}
numbers = new_numbers;
numbers[num_numbers++] = value;
}
fclose(input_file);
for (size_t i = 0; i < num_numbers; ++i)
printf("%d ", numbers[i]);
putchar('\n');
free(numbers);
}