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team1sum / team2sum is supposed to get the sum of each playerWeight1 / playerWeight2 and print it out.
My team1sum and team2sum are printing out wrong numbers.
The right output can be seen here.
#include <stdio.h>
int main() {
int i, howManyPlayers, playerWeight1, playerWeight2,
team1sum = 0, team2sum = 0;
scanf("%d", &howManyPlayers);
for (i = 0; i < howManyPlayers; i++){
scanf("%d", &playerWeight1);
scanf("%d", &playerWeight2);
team1sum = team1sum + playerWeight1;
team2sum = team2sum + playerWeight2;
}
if (team1sum > team2sum){
printf("Team 1 has an advantage\n");
printf("Total weight for team 1: %d\n", &team1sum);
printf("Total weight for team 2: %d", &team2sum);
}
else {
printf("Team 2 has an advantage\n");
printf("Total weight for team 2: %d\n", &team2sum);
printf("Total weight for team 1: ", &team1sum);
}
return 0;
}
Your printf needs the int, not the address of the int, so remove the & operator.
printf("Total weight for team 2: %d\n", team2sum);
printf("Total weight for team 1: %d", team1sum);
That should do the trick.
I ran your code and it seems that the actual sum is being calculated correctly.
By removing the & from the print statements, you should obtain the expected output.
Remember that when you print using printf, the format does matter, and printing a & to an int is not the same thing as printing an int.
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I'm troubleshooting my code right now and I'm trying to get the sum of the first and second score. However, it results to a million value.
#include <stdio.h>
int main ()
{
int points [10], n, i, sum = 0, ave;
float max, average;
printf("Enter number of activities to compute: ");
scanf("%d", &n );
printf("Enter total points possible: ");
scanf("%f", &max);
for(i=0; i < n; ++i){
printf("Enter points earned for each activity %d: ", i+1);
scanf("%d", &points [i]);
sum += points [i];
printf("%d", &sum);
}
}
When running the code this is the result:
Enter number of activities to compute: 2
Enter total points possible: 20
Enter points earned for each activity 1: 10
6618600Enter points earned for each activity 2: 5
6618600
My goal is to make it 15.
Thanks!
You don't need to put & in printf. Adding & will print the address of the variable.
printf("%d", sum);
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I am in C language
Arrays were implemented using input and output functions.
The code is as follows.
#include <stdio.h>
int main()
{
int n;
int arr[1000];
printf("Enter the number of numbers to enter : \n");
scanf("%d", &n);
for(int i = 0; i < n; i++)
{
scanf("%d", &arr[i]);
}
for(int i = n - 1; i >= 0; i--)
{
printf("&d ", arr[i]);
}
return 0;
}
However, after running the compilation, this resulted. Below is the (vscode, gcc) console window.
Enter the number of numbers to enter :
5
1 2 3 4 5
&d &d &d &d &d
I don't understand why the notation like %d %d %d appears here.
Adapted to the windows compiler, I feel pathetic. What is the problem
This line ie causing the issue:
printf("&d ", arr[i]);
You are printing not scanning for inputs, it should be like this:
printf("%d ", arr[i]);
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The program runs fine but keeps giving me an answer of 0.00. I have floated the numbers and answer and it asks for the first and second number but I cannot see where I have gone wrong.
#include <stdio.h>
#include <math.h>
int main()
{
float sub;
float num1 = 18.73;
float num2 = 20.00;
printf("Please enter the total of the meal: \n");
scanf("%f", &num1);
printf("Please enter the amount of money you have: \n");
scanf("%f", &num2);
sub = num2 - num1;
printf("\nYour change is: %.2f\n", &sub);
return 0;
}
You're printing the address of sub:
Do this:
printf("\nYour change is: %.2f\n", sub);
instead of:
printf("\nYour change is: %.2f\n", &sub);
In your code I have found 2 mistakes
Don't assign greater than 0 numbers to variables when you use scanf
float num1 = 0; //use this
float num2 = 0;
When you output a number don't use & in printf. That is the reason you were given 0.
printf("\nYour change is: %.2f\n", sub);
Finally, you don't need to use #include <math.h> in these king of programmes
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It is really very unexpected, I have looked a lot of time where can be the problem but couldn't find it.
Problem is:
Say I've given 7 integers to calculate their average, but it is taking first 6 numbers and calculating their average.
However I give any number more than 6, it will calculate only first 6's
The code is:
#include <stdio.h>
int main()
{
int n,i,total = 0;
int numArr[n];
printf("How many numbers do you want to print? => ");
scanf("%d",&n);
for(i = 0; i < n; i++)
{
scanf("%d",&numArr[i]);
total += numArr[i];
}
printf("--------------------------------\n");
printf("Average of this %d numbers: %d",n,total/n);
}
I'm not sure whether it is compiler problem or problem of my code.
initialize n first and then declare numArr[n]
Modify your code as
int n,i,total = 0;
printf("How many numbers do you want to print? => ");
scanf("%d",&n);
int numArr[n];
then scan the array.
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In the following program when the value of N is less than 100 the program is executing perfectly but for bigger values of N its showing segmentation fault.I sit because of less memory or anything wrong with program??
#include<stdio.h>
int main()
{
int N,iteration,MAX_ITERATONS;
int i,j,k,n,index,boundary1,boundary2;
double h[2][100][100];
int current = 0;
int next = 1;
printf("Enter the number of points\n ");
scanf("%d", &N);
boundary1=0.4*N;
boundary2=(0.6*N);
printf("The boundary is between %d and %d .\n",boundary1,boundary2);
for(k=0;k<2;k++)
{
for(i=0;i<N;i++)
{
for(j=0;j<N;j++)
{
if((i==0)&&(j>=boundary1&&j<boundary2))
h[k][i][j]=100;
else
h[k][i][j]=20;
}
}
}
printf("Initial Values\n");
index = N/10;
for(i=0;i<N;)
{
for(j=0;j<N;)
{
printf("%.2f\t",h[0][i][j]);
j=j+index;
}
i=i+index;
printf("\n");
}
}
When N > 100, h is accessed to an index greater than 100, inside the nested for loop
h[k][i][j]=100;
but h is defined as
double h[2][100][100];
You are going out of bounds for h
If you want N as greater than 100 you need to redefine h or malloc it.