dynamically initialize a 3D character array in c [duplicate] - c

Question

This question already has answers here:
Correctly allocating multi-dimensional arrays
(2 answers)
Closed 4 years ago.
I am trying to initialize a 3D character array, but couldn't. when i execute the program crashes.
I need to store 'T' sets of 'N[i]' no.of words in the ***word.characters in each word are less than 20.
"The program executes when static initialized."
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
#include<string.h>
#include<math.h>
int main()
{
int i,j,k,T,sum=0;
printf("\nEnter the no of test cases");
scanf("%d",&T);
int *N;
N=(int*)malloc(T*sizeof(int));
int **t;
t=(int**)malloc(T*sizeof(int*));
for(i=0;i<T;i++)
{
t[T]=(int*)malloc(N[i]*sizeof(int));
}
char ***word;
word = (char ***)malloc(T*sizeof(char**));
for (i = 0; i< T; i++)
{
word[T] = (char **) malloc(N[i]*sizeof(char *));
for (j = 0; j < N[i]; j++) {
word[T][N[i]] = (char *)malloc(20*sizeof(char));
}
}

Answer 1

In this line:
t[T]=(int*)malloc(N[i]*sizeof(int));
N[i] is uninitialized.
The same apply 3 times here:
word[T] = (char **) malloc(N[i]*sizeof(char *));
for (j = 0; j < N[i]; j++) {
word[T][N[i]] = (char *)malloc(20*sizeof(char));
}
So after
N=(int*)malloc(T*sizeof(int));
you should add some initialization like:
for(i=0;i<T;i++)
{
N(i) = 10 + i; // or whatever dimension you need
}
BTW: You don't need all the casting of malloc