How to put an integer in a individual number by arry? - c

Question

I want to input an integer such as 123454321. Then I want to print it in
this form:1 2 3 4 5 4 3 2 1.
Here is my code:
#include <stdio.h>
int main(void)
{
int A[100];
int i, input, current;
printf("Input n:");
scanf("%d",&input);
printf("\n");
for(i=1; i!=0; i++){
A[i]=input%10;
input=input/10;
printf("%d ",A[i]);
current++;
}
return 0;
}

Answer 1

You can put your input into your array like you do and display it, but the input will be reverse.
In case of intput: 12345
Value will be stored like this: A[0] = 5, A[1] = 4, ...
To change that you will have to display A[] from the end to the start. (already answered by chux)
Or you can store your input into A[] from the end to the start and after simply display it:
Example below:
#include <stdio.h>
int main(void)
{
int A[100];
int i, input, len, nb;
printf("Input n:");
scanf("%d",&input);
printf("\n");
nb = input; //I do a save of input.
for(len = 0; nb != 0; len++){ //Calculating the size of the input
nb = nb / 10; //
} //
len--;
for(int z = len; input != 0; z--){ //I copy the input into A.
A[z] = input % 10; //
input = input / 10; //
}
for(i = 0; i <= len; i++) // I display A
printf("%d ",A[i]); //
return 0;
}
EDIT:
By the way your for:
for(i=1; i!=0; i++){
A[i]=input%10;
input=input/10;
printf("%d ",A[i]);
current++;
}
Will infinite loop because i is never equals to 0 and the case A[0] of your array will not be used because ì start at 1.

Answer 2

Determine the values for A[] looping in one direction and then print the values in the other loop direction.
Let us assume input >= 0.
A do loop is useful here to handle the case of input == 0 to print "0".
i = 0;
do {
A[i] = input%10;
input = input/10;
i++;
} while (input);
Now print looping the other way
while (i) {
printf("%d ", A[--i]);
}
printf("\n");