Reading words from the keyboard and puting them in a Matrix - c

I have to read 5 words from the keyboard and put them in a matrix. For example if I have the word RED, the letters will be split between the columns of the first row. R E D and so on.
This is my code but it exits after I scanf 5 letters
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
int main()
{
char mat[3][3];
for(int i=0; i<2; i++)
for(int j=0;j<2;j++)
{
scanf("%s", &mat[i][j]);
}
for(int i=0; i<2; i++)
for(int j=0;j<2;j++)
{
printf("%s\t",mat[i][j]);
}
return 0;
}

Since you haven't specified any size for the strings... I will presume they are of arbitrary length...
// Takes input using the 'stdin' stream...
char* read_input(void)
{
char ch;
size_t len = 0;
size_t size = len + 2;
char* str = realloc(NULL, size);
if (!str)
return str;
while ((ch = fgetc(stdin)) != -1 && ch != '\n')
{
str[len++] = ch;
if (len == size)
{
str = realloc(str, size += 2);
if (!str)
return str;
}
}
str[len++] = '\0';
return realloc(str, len);
}
This function will read the input, now we also need a function for checking if the string is a valid word... i.e, it contains only alphabets...
// Checks whether the specified string is alphabetic or not...
int is_alpha_string(char* str, char* err_msg)
{
for (unsigned i = 0u; i < strlen(str); i++)
if (!isalpha(str[i]))
{
fprintf(stderr, err_msg);
return 0;
}
return 1;
}
After this, just do:
// The 'main()' function...
int main(void)
{
char* matrix[5];
for (unsigned i = 0u; i < 5u; i++)
{
printf("Enter your word here: ");
matrix[i] = read_input();
i -= !is_alpha_string(matrix[i], "Error! Entered text is not a valid word!\n\n");
}
for (int i = 0; i < 5; i++)
printf("%s\n", matrix[i]);
return 0;
}
Edit: And don't forget to add these includes at the top:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>

Related

Unique character count function does not take into consideration all lines (C)

My goal is to write a function, that calculates the number of all the unique characters from a redirected text file (meaning until EOF is reached). The code I wrote:
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#define ASCII_VALS 128
int strLen (char inp[])
{
int len = 0;
for(int i = 0; inp[i] != '\0'; i++){
len++;
}
return len;
}
int countUniqueChars (char inp[])
{
int everyCharValArr[ASCII_VALS] = {0};
int i, j = 0;
for(i = 0; i < strLen(inp); i++){
int convToInt = inp[i] - '0';
everyCharValArr[convToInt] = 1;
}
for (i = 0; i < ASCII_VALS; i++) {
j += everyCharValArr[i];
}
return j;
}
works for one string entered via scanf() like so:
int main ()
{
char inp[100];
printf("Enter a string: \n");
scanf("%99s", inp);
printf("%d\n", countUniqueChars(inp));
return 0;
}
But after I change the main function to read a redirected text file, like so:
int main ()
{
char inp[100];
int total = 0;
while(fgets(inp, 100, stdin)){
total += countUniqueChars(inp);
}
printf("%d\n", total);
return 0;
}
and runinng the program (./binary <input.txt) on a input.txt file with contents below:
Toydolls
Flies
trees
rocks
things
the value becomes 26, which is correct (1. word = 6 unique chars, 2. word = 5 unique chars, 3. word = 4 unique chars, 4. word = 5, 5. word = 6 unique chars), but it obviously does not take into consideration chars that appear on more lines, which should not be counted as unique chars at all. My question is How do I fix the function to accomplish this?
Try something like that: Note that I've added a mechanism not to count a duplicate uppercase letter and its lower case letter as unique.
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <ctype.h>
#define ASCII_VALS 128
int everyCharValArr[ASCII_VALS] = {0};
int strLen (char inp[])
{
int len = 0;
for(int i = 0; inp[i] != '\0'; i++){
len++;
}
return len;
}
void FindUniqueChars (char inp[])
{
int i;
for(i = 0; i < strLen(inp); i++){
if (inp[i] > ' ' && inp[i] != (char)127)
{
if (inp[i] >= 'A' && inp[i] <='Z')
{
inp[i] = tolower(inp[i]);
}
everyCharValArr[(int)inp[i]] = 1;
}
}
}
int CountUniqueChars( void )
{
int i, j = 0;
for (i = 0; i < ASCII_VALS; i++) {
j += everyCharValArr[i];
}
return j;
}
int main ()
{
char inp[100];
while(fgets(inp, 100, stdin)){
FindUniqueChars(inp);
}
printf("%d\n", CountUniqueChars());
return 0;
}

A dynamic 2d char array

I have a question about the C code for a dynamic 2d char array: malloc buffer overflow. The program idea is to initialize a global 2d char array, when the program is running, type some words, and save them into that 2d char array. I'm not familiar with the realloc function. What is wrong here?
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
char **array_history;
int count = 0;
#define MAX_LINE_CHARS 1024
int main (void){
array_history = malloc(sizeof(char *));
while (1) {
char line[MAX_LINE_CHARS];
if (fgets(line, MAX_LINE_CHARS, stdin) == NULL)
break;
array_history = realloc(array_history, sizeof(char*)*(count + 1));
int len_size = strlen(line) + 1;
array_history[count] = malloc(len_size*sizeof(char));
for (int i = 0; line[i] != '\0'; i++) {
array_history[count][i] = line[i];
// printf("%c", line[i]);
}
// printf("%s", array_history[0]);
// for (int i = 0; history[i] != NULL; i++) {
// printf("%s\n", history[i]);
// }
count++;
}
for (int i = 0; array_history[i] != NULL; i++) {
printf("%s", array_history[i]);
}
return 0;
}
You have some errors in your code.
You fail to terminate your strings and you fail to add the sentinel value that you are using when printing your string.
A fixed version could look like this:
(You should add more error checking for malloc etc.)
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#define MAX_LINE_CHARS 1024
int main (void){
char **array_history;
int count = 0;
array_history = malloc(sizeof(char *)*(count+1));
// TODO: Check for NULL
array_history[0] = NULL; // Terminate the array.
while (1) {
char line[MAX_LINE_CHARS];
if (fgets(line, MAX_LINE_CHARS, stdin) == NULL)
break;
void *temp_ptr = realloc(array_history, sizeof(char*)*(count + 2));
// TODO: Check for NULL
array_history = temp_ptr;
int len_size = strlen(line) + 1;
array_history[count] = malloc(len_size*sizeof(char));
array_history[count + 1] = NULL; // Add sentinel for your array
int i;
for (i = 0; line[i] != '\0'; i++) {
array_history[count][i] = line[i];
// printf("%c", line[i]);
}
array_history[count][i]=0; // Terminate the new string.
// Or simply use strcpy(array_history[count],line);
// printf("%s", array_history[0]);
// for (int i = 0; history[i] != NULL; i++) {
// printf("%s\n", history[i]);
// }
count++;
}
// Instead of terminating NULL value you could just use condition `i<count`
for (int i = 0; array_history[i] != NULL; i++) {
printf("%s", array_history[i]);
}
return 0;
}

how do i remove the similar word in strings?

I have program to remove the similar words from string but this program only removing at once word not a repeating words.
For example input:
sabunkerasmaskera kera
and should an output:
sabunmas
This my code:
#include <stdio.h>
#include <string.h>
void remove(char x[100], char y[100][100], char words[100]) {
int i = 0, j = 0, k = 0;
for (i = 0; x[i] != '\0'; i++) {
if (x[i] == ' ') {
y[k][j] = '\0';
k++;
j = 0;
} else {
y[k][j] = x[i];
j++;
}
}
y[k][j] = '\0';
j = 0;
for (i = 0; i < k + 1; i++) {
if (strcmp(y[i], kata) == 0) {
y[i][j] = '\0';
}
}
j = 0;
for (i = 0; i < k + 1; i++) {
if (y[i][j] == '\0')
continue;
else
printf("%s ", y[i]);
}
printf ("\n");
}
int main() {
char x[100], y[100][100], kata[100];
printf ("Enter word:\n");
gets(x);
printf("Enter word to remove:\n");
gets(words);
remove(x, y, words);
return 0;
}
My program output its:
sabunkerasmaskerara
and that should not be the case. Maybe I need your opinion to fixed this program and also I need help to make it better.
Your solution does not work because it uses strcmp to compare the string portions, which only works if the substring is at the end of the string, as this makes it null-terminated.
You should instead use strstr to locate the matches and use memmove to shift the string contents.
There are other issues in your code:
do not use gets()
y is unnecessary for this task.
words is not defined
Here is a modified version:
#include <stdio.h>
#include <string.h>
char *remove_all(char *str, const char *word) {
size_t len = strlen(word);
if (len != 0) {
char *p = str;
while ((p = strstr(p, word)) != NULL) {
memmove(p, p + len, strlen(p + len) + 1);
}
}
return str;
}
int main() {
char str[100], word[100];
printf ("Enter string:\n");
if (!fgets(str, sizeof str, stdin))
return 1;
printf("Enter word to remove:\n");
if (!fgets(word, sizeof word, stdin))
return 1;
word[strcspn(word, "\n")] = '\0'; // strip the trailing newline if any
remove_all(str, word);
fputs(str, stdout);
return 0;
}

split a string by a character without strtok in c

I need to write code that reads a string of characters such as jasf#fjaf#afsj to a single dimension string and then ask for a separation character (eg: #) so it will get an output in two dimensions and for every line, it will be the words between the separation character like:
jasf
fjaf
afsj
I tried:
#include <stdio.h>
#include <string.h>
void main {
int s, k, b;
printf("please enter a long string\n");
gets(longstring);
s = strlen(longstring);
printf("please choose seperationg charcter\n");
scanf("%c", &ch);
if ((ch < 'A') || ((ch > 'Z') && (ch < 'a')) || (ch > 'z')) {
for (k = 0; k < s; k++) {
for (b = 0; longstring[k] == ch; ++b) {
strcpy(mat[b], longstring);
}
}
puts(mat[b]);
}
Your code is incomplete: the function definition for main lacks its argument list, which is not optional in C, longstring is not defined, etc.
Futhermore, your method is too complicated: you do not need to test for letters if the goal is just to output one line for each part of the string between separators.
Here is a simple solution:
#include <stdio.h>
#include <string.h>
int main() {
char longstring[256];
int i, len;
char sep;
printf("please enter a long string\n");
if (fgets(longstring, sizeof longstring, stdin)) {
len = strlen(longstring);
printf("please choose a separationg character: ");
if (scanf("%c", &sep) != 1)
return 1;
for (i = 0; i < len; i++) {
if (longstring[i] == sep)
putchar('\n');
else
putchar(longstring[i]);
}
}
return 0;
}
since your code is not complete , let me add what is missing to achieve the task :
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <assert.h>
char** str_split(char* a_str, const char a_delim)
{
char** result = 0;
size_t count = 0;
char* tmp = a_str;
char* last_comma = 0;
char delim[2];
delim[0] = a_delim;
delim[1] = 0;
/* Count how many elements will be extracted. */
while (*tmp)
{
if (a_delim == *tmp)
{
count++;
last_comma = tmp;
}
tmp++;
}
/* Add space for trailing token. */
count += last_comma < (a_str + strlen(a_str) - 1);
/* Add space for terminating null string so caller
knows where the list of returned strings ends. */
count++;
result = (char**) malloc(sizeof(char*) * count);
if (result)
{
size_t idx = 0;
char* token = strtok(a_str, delim);
while (token)
{
assert(idx < count);
*(result + idx++) = strdup(token);
token = strtok(0, delim);
}
assert(idx == count - 1);
*(result + idx) = 0;
}
return result;
}
int main()
{
char longstring[1024];
char** tokens;
char ch;
unsigned long s;
printf("please enter a long string\n");
gets(longstring);
s = strlen(longstring);
printf("please choose seperationg charcter\n");
scanf("%c", &ch);
if ((ch<'A') || ((ch>'Z') && (ch<'a')) || (ch>'z'))
{
tokens = str_split(longstring, ch);
if (tokens)
{
int i;
for (i = 0; *(tokens + i); i++)
{
printf("%s\n", *(tokens + i));
free(*(tokens + i));
}
printf("\n");
free(tokens);
}
}
return 0;
}

String array prints out trash values

So I have an assignment where I should delete a character if it has duplicates in a string. Right now it does that but also prints out trash values at the end. Im not sure why it does that, so any help would be nice.
Also im not sure how I should print out the length of the new string.
This is my main.c file:
#include <stdio.h>
#include <string.h>
#include "functions.h"
int main() {
char string[256];
int length;
printf("Enter char array size of string(counting with backslash 0): \n");
/*
Example: The word aabc will get a size of 5.
a = 0
a = 1
b = 2
c = 3
/0 = 4
Total 5 slots to allocate */
scanf("%d", &length);
printf("Enter string you wish to remove duplicates from: \n");
for (int i = 0; i < length; i++)
{
scanf("%c", &string[i]);
}
deleteDuplicates(string, length);
//String output after removing duplicates. Prints out trash values!
for (int i = 0; i < length; i++) {
printf("%c", string[i]);
}
//Length of new string. The length is also wrong!
printf("\tLength: %d\n", length);
printf("\n\n");
getchar();
return 0;
}
The output from the printf("%c", string[i]); prints out trash values at the end of the string which is not correct.
The deleteDuplicates function looks like this in the functions.c file:
void deleteDuplicates(char string[], int length)
{
for (int i = 0; i < length; i++)
{
for (int j = i + 1; j < length;)
{
if (string[j] == string[i])
{
for (int k = j; k < length; k++)
{
string[k] = string[k + 1];
}
length--;
}
else
{
j++;
}
}
}
}
There is a more efficent and secure way to do the exercise:
#include <stdio.h>
#include <string.h>
void deleteDuplicates(char string[], int *length)
{
int p = 1; //current
int f = 0; //flag found
for (int i = 1; i < *length; i++)
{
f = 0;
for (int j = 0; j < i; j++)
{
if (string[j] == string[i])
{
f = 1;
break;
}
}
if (!f)
string[p++] = string[i];
}
string[p] = '\0';
*length = p;
}
int main() {
char aux[100] = "asdñkzzcvjhasdkljjh";
int l = strlen(aux);
deleteDuplicates(aux, &l);
printf("result: %s -> %d", aux, l);
}
You can see the results here:
http://codepad.org/wECjIonL
Or even a more refined way can be found here:
http://codepad.org/BXksElIG
Functions in C are pass by value by default, not pass by reference. So your deleteDuplicates function is not modifying the length in your main function. If you modify your function to pass by reference, your length will be modified.
Here's an example using your code.
The function call would be:
deleteDuplicates(string, &length);
The function would be:
void deleteDuplicates(char string[], int *length)
{
for (int i = 0; i < *length; i++)
{
for (int j = i + 1; j < *length;)
{
if (string[j] == string[i])
{
for (int k = j; k < *length; k++)
{
string[k] = string[k + 1];
}
*length--;
}
else
{
j++;
}
}
}
}
You can achieve an O(n) solution by hashing the characters in an array.
However, the other answers posted will help you solve your current problem in your code. I decided to show you a more efficient way to do this.
You can create a hash array like this:
int hashing[256] = {0};
Which sets all the values to be 0 in the array. Then you can check if the slot has a 0, which means that the character has not been visited. Everytime 0 is found, add the character to the string, and mark that slot as 1. This guarantees that no duplicate characters can be added, as they are only added if a 0 is found.
This is a common algorithm that is used everywhere, and it will help make your code more efficient.
Also it is better to use fgets for reading input from user, instead of scanf().
Here is some modified code I wrote a while ago which shows this idea of hashing:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>
#define NUMCHAR 256
char *remove_dups(char *string);
int main(void) {
char string[NUMCHAR], temp;
char *result;
size_t len, i;
int ch;
printf("Enter char array size of string(counting with backslash 0): \n");
if (scanf("%zu", &len) != 1) {
printf("invalid length entered\n");
exit(EXIT_FAILURE);
}
ch = getchar();
while (ch != '\n' && ch != EOF);
if (len >= NUMCHAR) {
printf("Length specified is longer than buffer size of %d\n", NUMCHAR);
exit(EXIT_FAILURE);
}
printf("Enter string you wish to remove duplicates from: \n");
for (i = 0; i < len; i++) {
if (scanf("%c", &temp) != 1) {
printf("invalid character entered\n");
exit(EXIT_FAILURE);
}
if (isspace(temp)) {
break;
}
string[i] = temp;
}
string[i] = '\0';
printf("Original string: %s Length: %zu\n", string, strlen(string));
result = remove_dups(string);
printf("Duplicates removed: %s Length: %zu\n", result, strlen(result));
return 0;
}
char *remove_dups(char *str) {
int hash[NUMCHAR] = {0};
size_t count = 0, i;
char temp;
for (i = 0; str[i]; i++) {
temp = str[i];
if (hash[(unsigned char)temp] == 0) {
hash[(unsigned char)temp] = 1;
str[count++] = str[i];
}
}
str[count] = '\0';
return str;
}
Example input:
Enter char array size of string(counting with backslash 0):
20
Enter string you wish to remove duplicates from:
hellotherefriend
Output:
Original string: hellotherefriend Length: 16
Duplicates removed: helotrfind Length: 10

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