Turn character into number and arrange the number in c - c

Question

int T, i;
scanf("%d", &T);
char a[T], b[T], c[T];
int temp[T], temp2[T], temp3[T];
int point1[T], point2[T], point3[T];
for(i=0;i<T; i++){
scanf("%c %c %c", &a[i], &b[i], &c[i]);
switch(a[i]){
case '!':
point1[i] = 5;
break;
case '%':
point1[i] = 4;
break;
case '&':
point1[i] = 3;
break;
case '^':
point1[i] = 2;
break;
case '|':
point1[i] = 1;
break;
default :
point1[i]=10;
}
switch(b[i]){
case '!':
point2[i] = 5;
break;
case '%':
point2[i] = 4;
break;
case '&':
point2[i] = 3;
break;
case '^':
point2[i] =2;
break;
case '|':
point2[i] =1;
break;
default :
point2[i]=10;
}
switch(c[i]){
case '!':
point3[i] = 5;
break;
case '%':
point3[i] = 4;
break;
case '&':
point3[i] = 3;
break;
case '^':
point3[i] =2;
break;
case '|':
point3[i] =1;
break;
default :
point3[i]=10;
}
if(point1[i]<point2[i]) {
temp[i]=point1[i];
point1[i]=point2[i];
point2[i]=temp[i];
}
if(point1[i]<point3[i]){
temp2[i]=point1[i];
point1[i]=point3[i];
point3[i]=temp2[i];
}
if(point2[i]<point3[i]){
temp3[i]=point2[i];
point2[i]=point3[i];
point3[i]=temp3[i];
}
printf("%d %d %d\n", point1[i], point2[i], point3[i]);
}
return 0;
So first of all, i was asked to input certain characters randomly arranged and make them printed arranged from the highest precedence.
The precedence of the operators (from the highest to the lowest) are "!" (logical NOT), "%" (remainder), "&"
(bitwise AND), "^" (bitwise XOR), , "|" (bitwise OR).
So i try to change the characters into numbers and try to arrange the number first then change the number again to the characters.
But when i try to check if the numbers have been correctly arranged, it's not.
Any idea what's wrong with my code?
Or any idea to make my code simpler without having to turn the characters into numbers?
Here's the sample
Sample Input
3
& ^ %
& ^ !
& ^ !
Sampe Output
Case #1: % & ^
Case #2: ! & ^
Case #3: ! & ^

Answer 1

A few issues have already been noted in the comments. Specifically, scanf leaves the trailing newline in the input buffer. You can fix that using the suggestion by #4386427.
You can avoid manually assigning numbers for each character by noting that their ASCII is already in required order. That is, '!' < '%' < '&' < '^' < '|'. So you can simply read them into a char array of the appropriate size and just sort them in ascending order before printing the char array. This will significantly shorten and clean up your code.
#include <stdio.h>
#include <stdlib.h>
int cmpfunc (const void * a, const void * b) {
return (*((char*)a) > *((char*)b)) - (*((char*)a) < *((char*)b));
}
int main(int argc, char *argv[])
{
int T, i, j;
scanf(" %d", &T);
/* TODO: Check if number of chars per line is T or 3. */
char *a = malloc(T * sizeof(char));
for(i = 0; i < T; i++) {
for (j = 0; j < T; j++) {
scanf(" %c", &a[j]);
}
printf("Before sort\n");
for (j = 0; j < T; j++) {
printf("%c ", a[j]);
}
printf("\n");
qsort(a, T, sizeof(a[0]), cmpfunc);
printf("After sort\n");
for (j = 0; j < T; j++) {
printf("%c ", a[j]);
}
printf("\n");
}
free(a);
return 0;
}