Trouble Including Externally Declared Enumeration - C Code - c

Question

Update: The issue is resolved. Here is code that compiles properly.
---instruction.h---
#ifndef INSTRUCTION_H
#define INSTRUCTION_H
typedef enum OPCODE {ADD = 0x20,ADDI = 0x8,SUB = 0x22,MULT = 0x18,BEQ = 0x4,LW = 0x23,SW = 0x2B} opcode;
/*opcode is OPCODEs alias*/
typedef struct INSTRUCTION {
opcode op;
int rs;
int rt;
int rd;
int Imm;
} inst;
/*inst is INSTRUCTIONs alias*/
#endif // INSTRUCTION_H
---parser.c---
#include <stdio.h>
#include "instruction.h"
void parser(char *instruction)
{
/*Parse character string into instruction components*/
inst set1 = {LW,0,1,2,0};
printf("parsing");
};
int main()
{
char *instruction;
instruction = NULL;
parser(instruction);
};
/*pass in pointer for instruction being passed in*/
/*pointing to address of instruction being passed in*/
/*Parser return type is struct inst*/
I cannot seem to get my enumeration type "opcode" to be recognized in my main c file. I included the header file. I am fairly new to C, so haven't made much ground on the issue for some time now and wanted to see if anyone knew why I was getting the error messages below. My guess is the linking the header file is not working properly. Any help is much appreciated.
---instruction.h----
#ifndef INSTRUCTION_H
#define INSTRUCTION_H
typedef enum {add = 32,addi = 8,sub = 34,mult = 24,beq = 4,lw = 35,sw = 43}opcode;
extern opcode oper;
typedef struct {
opcode op;
int rs;
int rt;
int rd;
int Imm;
}inst;
#endif // INSTRUCTION_H
---Parser.c---
#include <stdio.h>
#include "instruction.h"
void parser(char *inst)
{
/*Parse character string into instruction components*/
struct inst{lw,0,1,2,0};
};
int main()
{
char *instruction;
instruction = NULL;
parser(instruction);
};

Answer 1

struct inst{lw,0,1,2,0};
This looks like it's supposed to be a variable declaration, but I don't see a name for the variable. Try:
struct inst name_of_the_variable = {lw,0,1,2,0};
As a side note, enum values are global constants, so it's probably not a good idea to give them names like lw that can be confused for variables. Standard practice would be to use all-caps for the names and give them a prefix… say, OPCODE_ADD, OPCODE_LW, etc.

Answer 2

This is not a valid variable definition:
struct inst{lw,0,1,2,0};
There's no struct inst defined, only inst, there's no variable name, and you need = to use an initializer. To create a variable of this type an initialize it, you need:
inst myinst = {lw,0,1,2,0};
Also, your function has a parameter named inst which masks the type inst. You need to give it a different name:
void parser(char *instruction)