The requirement for the sample application creating using pthread is given below:
A single thread is created from main using Pthread
Inside thread, Mutex is locked, a counter counts the value and while loop is incremented, While is set to the max count of 10.
after while loop finishes, the mutex is unlocked.
The above requirement I have tried implementing using pthread
Code is shown below:
#include <pthread.h>
#include <stdio.h>
pthread_mutex_t count_mutex;
pthread_cond_t count_threshold_cv;
int samples = 10;
int count = 0;
struct example
{
int i;
int a;
};
void *inc_x(void *x_void_ptr)
{
pthread_mutex_lock(&count_mutex);
printf("Thread is locked \n");
while(count < samples)
{
printf("inside While loop \n");
struct example *E2_ptr;
E2_ptr = (struct example *)x_void_ptr;
printf("inside thread count = %d\n",count);
E2_ptr->a = count;
E2_ptr->i = (count + 1);
count ++;
//pthread_cond_wait(&count_threshold_cv, &count_mutex);
}
pthread_mutex_unlock(&count_mutex);
printf ( "\n Test Successful for Thread\n");
pthread_exit(NULL);
}
int main()
{
int x = 100, y = 0,i = 0;
struct example *E1_ptr;
E1_ptr->a = 0;
E1_ptr->i = 0;
printf("Before\t E1_ptr->a = %d\t, E1_ptr->i = %d\n",E1_ptr->a,E1_ptr->i);
pthread_t inc_x_thread;
if(pthread_create(&inc_x_thread, NULL, inc_x, E1_ptr))
{
printf("Error creating thread\n");
}
if(pthread_join(inc_x_thread, NULL))
{
printf("Error joining thread\n");
}
for(i = 0; i<(samples-1); i++)
{
if(pthread_cond_signal(&count_threshold_cv))
{
printf("Error Signaling thread at sample = %d\n",i);
}
}
printf("after\t E1_ptr->a = %d\t, E1_ptr->i = %d\n",E1_ptr->a,E1_ptr->i);
pthread_mutex_destroy(&count_mutex);
pthread_cond_destroy(&count_threshold_cv);
pthread_exit (NULL);
return 0;
}
Doubt:
In the above code, the thread executes its function properly and exits.
Once the condition is applied, i.e. the below shown code is uncommented then,
pthread_cond_wait(&count_threshold_cv, &count_mutex);
Then the thread is stopped after 1st iteration of while loop as expected.
The signal is generated from main by the code shown below:
for(i = 0; i<(samples-1); i++)
{
if(pthread_cond_signal(&count_threshold_cv))
{
printf("Error Signaling thread at sample = %d\n",i);
}
}
observed that the signal is never sent.
Can someone please guide me, where am I going wrong. I'm a newbie to Pthreads.
Thanks in advance.
count_mutex and count_threshold_cv are not initialized, add:
int main()
{
pthread_mutex_init(&count_mutex, NULL);
pthread_cond_init(&count_threshold_cv, NULL);
//...
E1_ptr is not initialized.
There are many ways to solve it:
You can call malloc to allocate memory:
struct example *E1_ptr = malloc(sizeof(struct example));
E1_ptr->a = 0;
E1_ptr->i = 0;
or holds pointer to local variable:
struct example ex;
struct example *E1_ptr = &ex; //malloc(sizeof(struct example));
E1_ptr->a = 0;
E1_ptr->i = 0;
or
struct example ex;
ex.a = 0;
ex.i = 0;
then create thread with pthread_create(&inc_x_thread, NULL, inc_x, &ex)
pthread_cond_signal function does not wait. If a thread is blocked by condition variable pthread_cond_signal function unblocks this thread, otherwise returns immediately without waiting and does nothing. So your for loop with 10 iterations is executed as soon as possible, without any waiting for pthread_cond_wait is called.
So can rewrite your for loop to infinite loop, calling pthread_cond_signal repeatedly.
if(pthread_create(&inc_x_thread, NULL, inc_x, E1_ptr)) {
printf("Error creating thread\n");
}
while(1) { // INFINITE LOOP
if(pthread_cond_signal(&count_threshold_cv)) {
printf("Error Signaling thread at sample = %d\n",i);
}
if (taskDone) // testing global flag, if 1 break
break; // it means inc_x thread has ended
}
if(pthread_join(inc_x_thread, NULL)) { // it was pointed out in comment
printf("Error joining thread\n"); // you need to join at the end of main function
}
taskDone is global int, with 0 as default value. It is set to 1 before pthread_exit is called in inc_x function. Setting/checking taskDone should be wrapped with some synchronization mechanism, for example by adding new mutex or use count_mutex.
Related
In relation to when producer accesses the shared source, Do I need another condition variable/condition signal? So it does get blocked when the shared resource is locked. I have a condition variable for the consumer, so it does it waits and if it won't try to access if there is nothing there to be added on (to consume)
int pnum; // number updated when producer runs.
int csum; // sum computed using pnum when consumer runs.
int (*pred)(int); // predicate indicating number to be consumed
pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t condc,condp;
int toConsume = 0; // condition varibale counter
int produceT() {
//Start Critical Section
pthread_mutex_lock(&mutex);
scanf("%d",&pnum);
toConsume++;
//End Critical Section
pthread_cond_signal (&condc);
pthread_mutex_unlock(&mutex);
return pnum;
}
void *Produce(void *a) {
int p;
p=1;
while (p) {
printf("producer thinking...\n");
sleep(1);
printf("..done!\n");
p = produceT();
printf("PRODUCED %d\n",p);
}
printf("EXIT-P\n");
pthread_exit(0);
}
int consumeT() {
pthread_mutex_lock(&mutex); //protect buffer
while(toConsume <=0){ // if nothing in buffer then wait
pthread_cond_wait(&condc,&mutex);
}
pthread_mutex_unlock(&mutex); //release buffer
//sleep()
pthread_mutex_lock(&mutex); //protect buffer
if ( pred(pnum) ) { csum += pnum; }
toConsume--;
pthread_mutex_unlock(&mutex);
return pnum;
}
void *Consume(void *a) {
int p;
p=1;
while (p) {
printf("consumer thinking...\n");
sleep(rand()%3);
printf("..done!\n");
p = consumeT();
printf("CONSUMED %d\n",csum);
}
printf("EXIT-C\n");
pthread_exit(0);
}
int main (int argc, const char * argv[]) {
// the current number predicate
static pthread_t prod,cons;
long rc;
pred = &cond1;
if (argc>1) {
if (!strncmp(argv[1],"2",10)) { pred = &cond2; }
else if (!strncmp(argv[1],"3",10)) { pred = &cond3; }
}
pthread_mutex_init(&mutex,NULL);
pthread_cond_init(&condc,NULL);//Initialize consumer condition variable
pthread_cond_init(&condp,NULL);//Initialize producer condition variable
pnum = 999;
csum=0;
srand(time(0));
printf("Creating Producer:\n");
rc = pthread_create(&prod,NULL,Produce,(void *)0);
if (rc) {
printf("ERROR return code from pthread_create(prod): %ld\n",rc);
exit(-1);
}
printf("Creating Consumer:\n");
rc = pthread_create(&cons,NULL,Consume,(void *)0);
if (rc) {
printf("ERROR return code from pthread_create(cons): %ld\n",rc);
exit(-1);
}
pthread_join( prod, NULL);
pthread_join( cons, NULL);
printf("csum=%d.\n",csum);
return 0;
}
A conditional variable is a way of efficiently blocking a thread until a certain condition is verified.
You use a conditional variable in the consumer simply because you dictate you can't consume if there isn't anything to consume -- so you decide to block until there is something to consume. In your case, this happens when toConsume == 0.
You may dictate that the producer must also wait -- that's entirely up to your specification. Some ideas:
You may want to prevent the variable to go over a certain value (e.g. 1000, or INT_MAX to avoid overflow).
If instead of a counter you use a circular buffer to place your things to be consumed, the producer must wait if there are no free slots to place the things in the buffer. This is the most common way of teaching the producers-consumers in textbooks :)
Hi below is my coding snippet
#include <pthread.h>
#include <stdio.h>
#include <unistd.h>
#define TIMEOUT 3
int threadFinished = 0;
pthread_mutex_t g_mutex;
void *threadFunction(void* attr)
{
pthread_mutex_lock(&g_mutex);
char *pData = (char*)attr;
if(pData)
{
printf("data from main thread is : %s\n",pData);
}
sleep(10);
threadFinished = 1;
pthread_mutex_unlock(&g_mutex);
return (void*)"This is thread message !";
}
int main()
{
pthread_t tid;
char *retVal = NULL;
int iTimeOut = TIMEOUT;
int i =0;
pthread_mutex_init(&g_mutex,NULL);
pthread_create(&tid,NULL,threadFunction,"Message from main thread");
//printf("itimeout %d , threadrunning %d\n",iTimeOut,threadRunning);
while(iTimeOut!=0 && !threadFinished)
{
printf("waiting %d\n",++i);
sleep(1);
iTimeOut--;
printf("changing the threadfinish varible\n");
//pthread_mutex_lock(&g_mutex); //statement 1
threadFinished = 1;
//pthread_mutex_unlock(&g_mutex); // statement 2
printf("changed the threadfinish varible\n");
}
if(iTimeOut==0)
{
if(!threadFinished)
{
printf("Timed out so cancelling the thread \n");
pthread_cancel(tid);
}
else
{
printf("thread finished \n");
}
}
else
{
printf("thread finished its job \n");
pthread_join(tid,(void*)&retVal);
}
pthread_mutex_destroy(&g_mutex);
threadFinished = 0;
printf("message from thread is : %s\n",retVal);
return 0;
}
When statement1 & statement2 are commented I am expecting child thread to change my testrunning variable first before main thread but it is working properly only when statement1 and statement2 are uncommented.
My question is why in child thread mutex lock is not locking my testrunning variable . it is allowing main thread to modify testrunning variable.
When accessing a variable concurrently from multiple threads, each thread needs to protect access to it via the same mutex. The main() thread fails to do so.
To correct this you could change main()'s while-loop like this:
while (iTimeOut != 0)
{
{
pthread_mutex_lock(&g_mutex);
int finished = threadFinished;
pthread_mutex_unlock(&g_mutex);
if (finished)
{
break;
}
}
printf("waiting %d\n",++i);
sleep(1);
iTimeOut--;
printf("changing the threadfinish varible\n");
pthread_mutex_lock(&g_mutex); //statement 1
threadFinished = 1;
pthread_mutex_unlock(&g_mutex); // statement 2
printf("changed the threadfinish varible\n");
}
Also you might like to consider narrowing locking to where it is necessary inside the thread-function like this:
void *threadFunction(void* attr)
{
char *pData = attr; /* No need to cast here in C, as opposed to C++. */
if(pData)
{
printf("data from main thread is : %s\n",pData);
}
sleep(10);
pthread_mutex_lock(&g_mutex);
threadFinished = 1;
pthread_mutex_unlock(&g_mutex);
return "This is thread message !"; /* No need to cast here in C, as opposed to C++. */
}
You should added error checking to all library calls in case a failure would influence the remaining execution.
I am trying to wait for all the threads to terminate before the main() process terminates. Here is what I have so far:
void* mapperFunction()
{
printf("Hello\n");
return NULL;
}
int main()
{
int i; // Used in "for" loops.
int N = 3;
pthread_t* mapperThreads = (pthread_t*) malloc(sizeof(pthread_t) * N);
for ( i = 0; i < N; i++)
{ // Creates all the mapper threads.
pthread_create( &mapperThreads[N], NULL, mapperFunction, NULL);
}
for ( i = 0; i < N; i++)
{ // Waits for all the mapper threads to terminate.
pthread_join( mapperThreads[N],NULL);
}
return 0;
}
I get three different outputs when I run this code;
1- Hello\n
2- Helle\nHello\n
3- Hello\nHello\nHello\n
It looks like the main() process does not always wait for all threads to terminate. What am I doing wrong?
You want &mapperThreads[i] instead of &mapperThreads[N] in each case.
Maybe pthread_barrier_wait is what you're looking for ?
Link
I want to finish my threads with a mutex. The first thread won't execute, thread 2 & 3 execute.
Does anyone know what this problem could be? Sometimes thread 1 is executed but then 2 or 3 is not executed. I don't know what the problem is here.
Thread created successfully
Thread created successfully
Thread created successfully
----------------------------------------------------
J:0
NUM_REQUESTS (before function): 0
J:0
----------------------------------------------------
----------------------------------------------------
J:1
Third thread processing done
WRITE DATA TO LIST!
NUM_REQUESTS(function): 1
NUM_REQUESTS (before function): 0
J:1
----------------------------------------------------
----------------------------------------------------
J:2
Second thread processing done
WRITE DATA TO LIST!
NUM_REQUESTS(function): 0
NUM_REQUESTS (before function): 0
J:2
----------------------------------------------------
Program:
#include<stdio.h>
#include<string.h>
#include<pthread.h>
#include<stdlib.h>
#include<unistd.h>
pthread_mutex_t request_mutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t got_request = PTHREAD_COND_INITIALIZER;
pthread_t tid[3];
int thr_id[3];
int ret1,ret2,ret3;
int i = 0;
int err;
int *ptr[2];
int num_requests = 0;
int rc = 0;
This is the function of the threads, the first thread is not executed!
void* doSomeThing(void *arg)
{
unsigned long i = 0;
pthread_t id = pthread_self();
for(i=0; i<1000000;i++);
if(pthread_equal(id,tid[0]))
{
printf("First thread processing done\n");
printf("WRITE DATA TO LIST!\n");
num_requests--;
printf("NUM_REQUESTS(function): %d\n",num_requests);
rc = pthread_mutex_unlock(&request_mutex);
pthread_exit(&tid[0]);
}else if(pthread_equal(id,tid[1])){
printf("Second thread processing done\n");
num_requests--;
printf("WRITE DATA TO LIST!\n");
printf("NUM_REQUESTS(function): %d\n",num_requests);
rc = pthread_mutex_unlock(&request_mutex);
pthread_exit(&tid[1]);
}else if(pthread_equal(id,tid[2])){
printf("Third thread processing done\n");
printf("WRITE DATA TO LIST!\n");
printf("NUM_REQUESTS(function): %d\n",num_requests);
num_requests--;
rc = pthread_mutex_unlock(&request_mutex);
pthread_exit(&tid[2]);
}
return NULL;
}
This is where i create the output of the threads
void add_request(int j,pthread_mutex_t* p_mutex,pthread_cond_t* p_cond_var)
{
printf("----------------------------------------------------\n");
printf("J:%d\n",j);
if(num_requests > 3){
printf("WAIT TILL THREADS ARE FREE!\n");
}else{
rc = pthread_mutex_lock(&request_mutex);
printf("NUM_REQUESTS (before function): %d\n",num_requests);
num_requests++;
rc = pthread_mutex_unlock(&request_mutex);
rc = pthread_mutex_lock(&request_mutex);
rc = pthread_cond_signal(p_cond_var);
printf("J:%d\n",j);
printf("----------------------------------------------------\n");
}
}
In the main i only create the threads and use the add_request function to execute the threads
int main(void)
{
//create 3 threads
while(i < 3)
{
thr_id[i] = i;
err = pthread_create(&(tid[i]), NULL, &doSomeThing, (void*)&thr_id[i]);
if (err != 0)
printf("can't create thread :[%s]", strerror(err));
else
printf("Thread created successfully\n");
i++;
}
int j;
for(j=0;j<3;j++){
add_request(j, &request_mutex, &got_request);
}
return 0;
}
what are you trying to do?
At least one problem I see it that you unlock the mutex without locking it...
When you create a thread it starts spontaneously (more or less) so you can't assume add_request will be called after doSomething().
You can lock and then unlock. Also consider using ptheard_join if you want to wait until the threads finish.
EDIT
this is what you want to do https://computing.llnl.gov/tutorials/pthreads/samples/condvar.c
-taken from https://computing.llnl.gov/tutorials/pthreads/
Good luck
The problem is in following:
I want to write a short program that creates 10 threads and each prints a tread "id" that is passed to thread function by pointer.
Full code of the program is below:
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
struct params {
pthread_mutex_t mutex;
int id;
};
typedef struct params params_t;
void* hello(void* arg){
int id;
pthread_mutex_lock(&(*(params_t*)(arg)).mutex);
id = (*(params_t*)(arg)).id;
pthread_mutex_unlock(&(*(params_t*)(arg)).mutex);
printf("Hello from %d\n", id);
}
int main() {
pthread_t threads[10];
params_t params;
pthread_mutex_init (¶ms.mutex , NULL);
int i;
for(i = 0; i < 10; i++) {
params.id = i;
if(pthread_create(&threads[i], NULL, hello, ¶ms));
}
for(i = 0; i < 10; i++) {
pthread_join(threads[i], NULL);
}
return 0;
}
The supposed output is (not necessary in this order):
Hello from 0
....
Hello from 9
Actual result is:
Hello from 2
Hello from 3
Hello from 3
Hello from 4
Hello from 5
Hello from 6
Hello from 8
Hello from 9
Hello from 9
Hello from 9
I tried to place mutex in different places in hello() function, but it didn't help.
How should I implement thread sync?
EDIT: Supposed result is not necessary 0...9 it can be any combination of these numbers, but each one should appear only one time.
The problem lies in the below code:
for(i = 0; i < 10; i++)
{
params.id = i;
if(pthread_create(&threads[i], NULL, hello, ¶ms));
}
Your params.id value keeps getting updated in the main thread, whereas you are passing the same pointer to all the threads.
Please create seperate memory for params by dynamically allocating it and pass it to different threads to solve the problem.
EDIT1:
Your usage of mutex to protect is also an incorrect idea. Though your mutex if used in main while setting the id also, may make the updation mutually exclusive, but you may not get your desired output. Instead of getting values from 0 .. 9 in different threads, you may get all 9s or still multiple threads may print same values.
So, using thread synchronization is not such a good idea for the output which you are expecting. If you still need to use one param variable between all threads and get output as 0 to 9 from each of the threads, better move the pthread_join into the first loop. This will ensure that each thread gets created, prints the value and then returns before the main spawns the next thread. In this case, you don't need the mutex also.
EDIT2:
As for the updated question, where it is asked that it is not necessary to print the numbers 0..9 in a sequence, the printing can be random, but only once, the problem still remains the same more or less.
Now, let's say, the value of params.id is first 0 and thread 0 got created, now, thread 0 must print it before it is updated in the main thread, else, when thread 0 accessess it, the value of params.id would have become 1 and you will never get your unique set of values. So, how to ensure that thread 0 prints it before it is updated in main, Two ways for it:
Ensure thread 0 completes execution and printing before main updates
the value
Use condition variables & signalling to ensure that main thread waits
for thread 0 to complete printing before it updates the value (Refer
to Arjun's answer below for more details)
In my honest opinion, you have selected the wrong problem for learning synchronization & shared memory. You can try this with some good problems like "Producer-Consumer", where you really need synchronization for things to work.
There are two problems:
A. You're using a lock but main is unaware of this lock.
B. A lock is not enough in this case. What you would want is for threads to cooperate by signalling each other (because you want main to not increment the variable until a thread says that it is done printing it). You can use a pthread_cond_t to achieve this (Look here to learn more about this). This boils down to the following code (basically, I added an appropriate usage of pthread_cond_t to your code, and a bunch of comments explaining what is going on):
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
struct params {
pthread_mutex_t mutex;
pthread_cond_t done;
int id;
};
typedef struct params params_t;
void* hello(void* arg){
int id;
/* Lock. */
pthread_mutex_lock(&(*(params_t*)(arg)).mutex);
/* Work. */
id = (*(params_t*)(arg)).id;
printf("Hello from %d\n", id);
/* Unlock and signal completion. */
pthread_mutex_unlock(&(*(params_t*)(arg)).mutex);
pthread_cond_signal (&(*(params_t*)(arg)).done);
/* After signalling `main`, the thread could actually
go on to do more work in parallel. */
}
int main() {
pthread_t threads[10];
params_t params;
pthread_mutex_init (¶ms.mutex , NULL);
pthread_cond_init (¶ms.done, NULL);
/* Obtain a lock on the parameter. */
pthread_mutex_lock (¶ms.mutex);
int i;
for(i = 0; i < 10; i++) {
/* Change the parameter (I own it). */
params.id = i;
/* Spawn a thread. */
pthread_create(&threads[i], NULL, hello, ¶ms);
/* Give up the lock, wait till thread is 'done',
then reacquire the lock. */
pthread_cond_wait (¶ms.done, ¶ms.mutex);
}
for(i = 0; i < 10; i++) {
pthread_join(threads[i], NULL);
}
/* Destroy all synchronization primitives. */
pthread_mutex_destroy (¶ms.mutex);
pthread_cond_destroy (¶ms.done);
return 0;
}
I see that the example you are trying is a toy program to probably learn about the POSIX thread library. In the real world, as we all know this can be done much faster without even using threads. But you already know this.
The problem is that you are modifying the params.id "unprotected" in main. This modification in main also needs to be mutex protected. You could protect this access by localizing this by creating getId() and setId() functions that would lock the mutex and protect access to the id, as follows. This will most likely still give the problem reported, since depending on when the thread calls getData() it will have one value or another. So to solve this, you could add an incrementId() function and call it from the hello() function.
struct params {
pthread_mutex_t mutex;
int id;
};
typedef struct params params_t;
int getId(params_t *p)
{
int id;
pthread_mutex_lock(&(p->mutex));
id = p->id;
pthread_mutex_unlock(&(p->mutex));
return id;
}
void setId(params_t *p, int val)
{
pthread_mutex_lock(&(p->mutex));
p->id = val;
pthread_mutex_unlock(&(p->mutex));
}
void incrementId(params_t *p)
{
pthread_mutex_lock(&(p->mutex));
p->id++;
pthread_mutex_unlock(&(p->mutex));
}
void* hello(void* arg){
params_t *p = (params_t*)(arg);
incrementId(p);
int id = getId(p);
// This could possibly be quite messy since it
// could print the data for multiple threads at once
printf("Hello from %d\n", id);
}
int main() {
pthread_t threads[10];
params_t params;
params.id = 0;
pthread_mutex_init (¶ms.mutex , NULL);
int i;
for(i = 0; i < 10; i++) {
if(pthread_create(&threads[i], NULL, hello, ¶ms));
}
for(i = 0; i < 10; i++) {
pthread_join(threads[i], NULL);
}
return 0;
}
A better way to get a unique thread id would be to define the hello method as follows:
void* hello(void* arg){
pthread_t threadId = pthread_self();
printf("Hello from %d\n", threadId);
}
And to avoid the problem with all threads trying to print at once, you could do the following:
void* hello(void* arg){
params_t *p = (params_t*)(arg);
pthread_mutex_lock(&(p->mutex));
p->id++;
int id = p->id;
printf("Hello from %d\n", id);
pthread_mutex_unlock(&(p->mutex));
}
Easiest way to get the desired output would be to modify your main function as follows:
int main() {
pthread_t threads[10];
params_t params;
pthread_mutex_init (¶ms.mutex , NULL);
int i;
for(i = 0; i < 10; i++) {
params.id = i;
if(pthread_create(&threads[i], NULL, hello, ¶ms));
pthread_join(threads[i], NULL); //wait for thread to finish
}
/*for(i = 0; i < 10; i++) {
pthread_join(threads[i], NULL);
}*/
return 0;
}
Output would be:
Hello from 0
...
Hello from 9
EDIT: Here's the synchronization for the corrected question:
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
struct params {
pthread_mutex_t* mutex;
int id;
};
typedef struct params params_t;
void* hello(void* arg){
int id = 0;
params_t* params = (params_t*)arg;
if(params != 0)
{
id = params->id;
delete params;
params = 0;
}
printf("Hello from %d\n", id);
}
int main() {
pthread_t threads[10];
params_t* params = 0;
pthread_mutex_t main_mutex;
pthread_mutex_init (&main_mutex , NULL);
int i;
for(i = 0; i < 10; i++) {
params = new params_t(); //create copy of the id to pass to each thread -> each thread will have it's own copy of the id
params->id = i;
params->mutex = &main_mutex;
if(pthread_create(&threads[i], NULL, hello, params));
}
for(i = 0; i < 10; i++) {
pthread_join(threads[i], NULL);
}
return 0;
}
Each thread must have it's own copy of the id so that the other threads do not modify the id before it is printed.
I'm just putting this one here to provide another solution to this problem - this one does not involve mutexes - no synchronization - no conditionals, etc.
The main dfference is that we are using pthread_detach to automatically release the thread's resources upon completion.
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#define NUMTHREADS 10
typedef struct params {
int id;
} params_t;
void* hello(void *arg)
{
params_t *p = (params_t*)arg;
int status;
status = pthread_detach(pthread_self());
if (status !=0 )
{
printf("detaching thread\n");
abort();
}
printf("Hello from %d\n", p->id);
free(p);
return NULL;
}
int main()
{
pthread_t thread;
params_t *par;
int i, status;
for (i=0; i<NUMTHREADS; i++)
{
par = (params_t*)malloc(sizeof(params_t));
if (par == NULL)
{
printf("allocating params_t");
abort();
}
par->id = i;
status = pthread_create(&thread, NULL, hello, par);
if (status != 0)
exit(1);
}
/* DO some more work ...*/
sleep(3);
exit(0);
}