Remove all '\' from a string in C - c

Question

I am trying to get rid of all \ characters in a string in C. For example, if a string is co\din\g it should convert the string to coding.
So far I have the code
for(i = 0; i < strlen(string); ++i){
if(string[i] == '\'){
}
}
That looks to see if there is a backslash. I don't know how I would do to remove the backslash, however. My only idea is to set the next character equal to the current character, however, I don't know how changing the length of the string would work with memory.

Answer 1

like this:
#include <stdio.h>
int main(){
char st[] = "co\\din\\g";
int k = 0;
for (int i = 0; st[i] != '\0'; ++i)
if (st[i] != '\\')
st[k++] = st[i];
st[k] = '\0';
fputs(st, stdout);
return 0;
}

Answer 2

This works. Since you're only deleting characters, you can write back into the same string. At the end, the termination '\0' will move to a lower index, and the rest of the array will simply be ignored by printf. Also, \ is the escape character, so to pass the \ itself you must write \\.
#include <stdio.h>
void nukechar(char s[], char c)
{
size_t j = 0;
for (size_t i = 0; s[i] != '\0'; ++i) {
if (s[i] != c) {
s[j] = s[i];
++j;
}
}
s[j] = '\0';
}
int main(void)
{
char s[200];
while (fgets(s, 200, stdin) != NULL) {
nukechar(s,'\\');
printf("%s", s);
}
return 0;
}

Answer 3

The simplest solution would be to use a second string for the result:
#include <stdio.h>
#include <string.h>
int main(void)
{
char result[100] = {'\0'}, string[] = "co\\din\\g";
for(int i = 0, j = 0; i < strlen(string); i++)
{
if(string[i] != '\\')
result[j++] = string[i];
}
printf("%s %s\n", result, string);
return 0;
}
Result
$ gcc main.c -o main.exe; ./main.exe;
coding co\din\g
Note
It is necessary to use double backslashes, \\, so the character following the backslash is not interpreted as an escape sequence.