I have a table that logs all updates made to an application. I want to query the table and return the last update by [Timestamp] and the update before that for a different value [ITEM]. I'm struggling to figure out how to get what i need. I'm returning more than one record for each ID and don't want that.
;WITH cte AS
(
SELECT
ID,
LAG(ITEM) OVER (PARTITION BY ID ORDER BY timestamp DESC) AS ITEM,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY timestamp DESC) RN
FROM
MyLoggingTable
WHERE
accountid = 1234
)
SELECT
cte.ID,
dl.ITEM,
DL.timestamp
FROM
cte
JOIN
MyLoggingTable DL ON cte.ID = DL.ID
WHERE
rn = 1
AND cte.ID IN ('id here | Sub select :( ..')
Is ID unique? Because if it is, your code shouldn't return duplicates. If it isn't, you will get duplicates because you are joining back to the MyLoggingTable which isn't needed. You should just move those columns (dl.Item & dl.timestamp) into the cte and return them from the cte like you did cte.ID.
I removed the LAG since you didn't return that column in your final query.
;WITH cte AS
(
SELECT
ID,
ITEM,
[timestamp],
--LAG(ITEM) OVER (PARTITION BY ID ORDER BY timestamp DESC) AS ITEM,
ROW_NUMBER() OVER (PARTITION BY ID ORDER BY timestamp DESC) RN
FROM
MyLoggingTable
WHERE
accountid = 1234
)
SELECT
cte.ID,
cte.ITEM,
cte.timestamp
FROM
cte
WHERE
rn = 1
AND cte.ID IN ('id here | Sub select :( ..')
Note, if you wanted the second to the last item, as you stated in your comments, make rn=2
Related
I have two tables:
Customer which has an Id column representing the customer Id.
CustomerDonation that contains CustomerId (FK), Amount and DatePayed
I'd like have all the customers together with their latest donation and the amount of that donation.
I am receiving duplicate values on my query so I will not paste it here.
You could also use the WITH TIES option
Select Top 1 With Ties *
From YourTable
Order By Row_Number() over (Partition By CustomerId Order By DatePayed Desc)
WITH
SortedDonation AS
(
SELECT
ROW_NUMBER() OVER (PARTITION BY CustomerId ORDER BY DatePayed DESC) AS SeqID,
*
FROM
CustomerDonation
)
SELECT
*
FROM
Customer
LEFT JOIN
SortedDonation
ON SortedDonation.CustomerId = Customer.Id
AND SortedDonation.SeqId = 1
If the same customer can make multiple donations with the same DatePayed, then this will arbitrarily pick just one of them.
If you add additional fields to the ORDER BY you can deterministically pick which one you want.
Or, if you want all of them use DENSE_RANK() instead of ROW_NUMBER()
Use Row_Number() Analytic function .
Select * from (
Select customerId,Amount,DatePayed, row_number() over (partition by CustomerId order by DatePayed desc) as rowN)
as tab where rowN = 1
You only need the CustomerDonation table for this. You can join with the Customer table if you want other information of the customer.
WITH cte AS (
SELECT
CustomerId
, MAX(DatePayed) AS LastDate
FROM
CustomerDonation
)
SELECT
cd.CustomerId
, cd.Amount
, cd.DatePayed
FROM
CustomerDonation cd
JOIN cte ON cd.CustomerId = cte.CustomerId
AND cd.DatePayed = cte.LastDate
i have this Table Chips:
im looking to find the max for each ID but
the code im using is just not correct i need the new table to be
select *
from
(
max (numchips) over (partition by Id)
from #chips
)
You can use ROW_NUMBER:
SELECT Id, numchips
FROM (
SELECT Id, numchips,
ROW_NUMBER() OVER (PARTITION BY Id
ORDER BY numchips DESC) as rn
FROM #chips
) t
WHERE rn = 1
rn is equal to 1 for the record having the highest numchips value within each Id partition.
Using ROW_NUMBER() makes sense only if you have some additional columns in Chips table that you also want to retrieve.
Why can't you just do?:
SELECT
MAX(c.numchips),
c.Id
FROM
#chips as c
GROUP BY
c.Id
does anyone know how can I subtract top two rows from one column only using one id? Here's my sample query:
SELECT top 2 a.consumption,
coalesce(a.consumption -
(SELECT b.consumption
FROM tbl_t_billing b
WHERE b.id = a.id + 1), a.consumption) AS diff
FROM tbl_t_billing a
WHERE a.customerId = '5'
ORDER BY a.dateCreated DESC
I want to know how to get the difference between the top 2 rows using one id from the consumption column using the customerId #5. I've tried but I can't get the right query for that. Can somebody help me please? Thanks!
try this:
;with cte as
(
select consumption, customerId,
row_number() over (partiton by customerid order by datecreated desc) rn
from tbl_t_billing where customerId = '5'
)
select a.customerId, a.consumption,
coalesce((a.consumption - b.consumption), a.consumption) consumption_diff
from cte a left outer join cte b on a.rn + 1 = b.rn
where a.rn = 1
declare #tbl_t_billing table(consumption int, customerId int, datecreated datetime)
insert into #tbl_t_billing
values
(10,5,'20100101'),
(7,5,'20000101'),
(9,4,'20100101'),
(5,4,'20000101'),
(8,3,'20100101'),
(3,3,'20000101'),
(7,2,'20100101'),
(3,2,'20000101'),
(4,1,'20100101'),
(2,1,'20000101')
-- get the difference between the last two consumption values for each customerId
select
customerId,
sum(consumption) diff
from(
select
customerId,
consumption *
case row_number() over(partition by customerId order by datecreated desc)
when 1 then 1 when 2 then -1
end consumption
from #tbl_t_billing
) t
group by customerId
When I run the code below the ROWID is always 1.
I need to the ID to start at 1 for each item with the same Credit Value.
;WITH CTETotal AS (SELECT
TranRegion
,TranCustomer
,TranDocNo
,SUM(TranSale) 'CreditValue'
FROM dbo.Transactions
LEFT JOIN customers AS C
ON custregion = tranregion
AND custnumber = trancustomer
LEFT JOIN products AS P
ON prodcode = tranprodcode
GROUP BY
TranRegion
,TranCustomer
,TranDocNo)
SELECT
r.RegionDesc
,suppcodedesc
,t.tranreason as [Reason]
,t.trandocno as [Document Number]
,sum(tranqty) as Qty
,sum(tranmass) as Mass
,sum(transale) as Sale
,cte.CreditValue AS 'Credit Value'
,RANK() OVER (PARTITION BY cte.CreditValue ORDER BY cte.CreditValue)AS ROWID
FROM transactions t
LEFT JOIN dbo.Regions AS r
ON r.RegionCode = TranRegion
LEFT JOIN CTETotal AS cte
ON cte.TranRegion = t.TranRegion
AND cte.TranCustomer = t.TranCustomer
AND cte.TranDocNo = t.TranDocNo
GROUP BY
r.RegionDesc
,suppcodedesc
,t.tranreason
,t.trandocno
,cte.CreditValue
ORDER BY CreditValue ASC
EDIT
All the credit values with 400 must have the ROWID set to 1. And all the credit values with 200 must have the ROWID set to 2. And so on and so on.
Do you need something like this?
with cte (item,CreditValue)
as
(
select 'a',8 as CreditValue union all
select 'b',18 union all
select 'a',8 union all
select 'b',18 union all
select 'a',8
)
select CreditValue,dense_rank() OVER (ORDER BY item)AS ROWID from cte
Result
CreditValue ROWID
----------- --------------------
8 1
8 1
8 1
18 2
18 2
In your code replace
,RANK() OVER (PARTITION BY cte.CreditValue ORDER BY cte.CreditValue)AS ROWID
by
,DENSE_RANK() OVER (ORDER BY cte.CreditValue)AS ROWID
You just don't have to use PARTITION, just DENSE_RANK() OVER (ORDER BY cte.CreditValue)
I think the problem is with the RANK() OVER (PARTITION BY clause
you have to partition it by item not by CreditValue
Try this
RANK() OVER (PARTITION BY cte.CreditValue ORDER BY cte.RegionDesc)AS ROWID
Edit: The issue here isn't actually the nesting of the subquery, it's potentially based on partition by having columns that truly make each row unique (or 1)
Rather than ranking within your complex query like this
select
rank() over(partition by...),
*
from
data_source
join table1
join table2
join table3
join table4
order by
some_column
Try rank() or row_number() on the resulting data set, not within it.
For example, using the query above, remove rank() and implement it this way:
select
rank() over(partition by...),
results.*
from (
select
*
from
data_source
join table1
join table2
join table3
join table4
order by
some_column
) as results
I have a table :
EventLog (
EventID (INT),
UserID (VARCHAR(50),
Event (NTEXT),
EventDate(DateTime),
DocuvmentID(INT)
)
I need to write a query to get the latest event, datetime for a bunch of userId which will be
WHERE UserID IN ( 'john','tom'...etc)
How can I do that?
SELECT y.UserID, y.Event, y.EventDate
FROM (SELECT UserId, MAX(EventDate) AS MaxDate
FROM YourTable
WHERE UserId IN ('john','tom',...)
GROUP BY UserId) t
INNER JOIN YourTable y
ON t.UserId = y.UserId
AND t.MaxDate = y.EventDate
With a simple CTE:
;WITH LatestDates AS
(SELECT
EventID, UserID,
Event, EventDate,
DocumentID,
ROW_NUMBER() OVER(PARTITION BY UserID ORDER BY EventDate DESC) AS 'RowNum'
)
SELECT *
FROM LatestDates
WHERE RowNum = 1 AND UserID IN (........)
This partitions your data by some criteria (I picked UserID as an option - might be something else for you), then numbers each group sequentially starting at 1, ordered by another criteria (here: EventDate DESC) - so the most recent event for each "partition" has RowNum = 1 which is what I select from that CTE
select
UserID,
MAX(EventDate) AS LatestEventDate
from
EventLog
where
UserID in ('john','tom')
group by
UserID