Why isn't this bash array populating? I believe I've done them like this in the past. Echoing ${#XECOMMAND[#]} shows no data..
DIR=$1
TEMPFILE=/tmp/dir.tmp
ls -l $DIR | tail -n +2 | sed 's/\s\+/ /g' | cut -d" " -f5,9 > $TEMPFILE
i=0
cat $TEMPFILE | while read line ;do
if [[ $(echo $line | cut -d" " -f1) == 0 ]]; then
XECOMMAND[$i]="$(echo "$line" | cut -d" " -f2)"
(( i++ ))
fi
done
When you run the while loop like
somecommand | while read ...
then the while loop is executed in sub-shell, i.e. a different process than the main script. Thus, all variable assignments that happen in the loop, will not be reflected in the main process. The workaround is to use input redirection and/or command substitution, so that the loop executes in the current process. For example if you want to read from a file you do
while read ....
do
# do stuff
done < "$filename"
or if you wan't the output of a process you can do
while read ....
do
# do stuff
done < <(some command)
Finally, in bash 4.2 and above, you can set shopt -s lastpipe, which causes the last command in the pipeline to be executed in the current process.
I think you're trying to construct an array consisting of the names of all zero-length files and directories in $DIR. If so, you can do it like this:
mapfile -t ZERO_LENGTH < <(find "$DIR" -maxdepth 1 -size 0)
(Add -type f to the find command if you're only interested in regular files.)
This sort of solution is almost always better than trying to parse ls output.
The use of process substitution (< <(...)) rather than piping (... |) is important, because it means that the shell variable will be set in the current shell, not in an ephimeral subshell.
The below script:
#!/bin/bash
otscurrent="
AAA,33854,4528,38382,12
BBB,83917,12296,96213,13
CCC,20399,5396,25795,21
DDD,27198,4884,32082,15
EEE,2472,981,3453,28
FFF,3207,851,4058,21
GGG,30621,4595,35216,13
HHH,8450,1504,9954,15
III,4963,2157,7120,30
JJJ,51,59,110,54
KKK,87,123,210,59
LLL,573,144,717,20
MMM,617,1841,2458,75
NNN,234,76,310,25
OOO,12433,1908,14341,13
PPP,10627,1428,12055,12
QQQ,510,514,1024,50
RRR,1361,687,2048,34
SSS,1,24,25,96
TTT,0,5,5,100
UUU,294,1606,1900,85
"
IFS="," array1=(${otscurrent})
echo ${array1[4]}
Prints:
$ ./test.sh
12
BBB
I'm trying to get it to just print 12... And I am not even sure how to make it just print row 5 column 4
The variable is an output of a sqlquery that has been parsed with several sed commands to change the formatting to csv.
otscurrent="$(sqlplus64 user/password#dbserverip/db as sysdba #query.sql |
sed '1,11d; /^-/d; s/[[:space:]]\{1,\}/,/g; $d' |
sed '$d'|sed '$d'|sed '$d' | sed '$d' |
sed 's/Used,MB/Used MB/g' |
sed 's/Free,MB/Free MB/g' |
sed 's/Total,MB/Total MB/g' |
sed 's/Pct.,Free/Pct. Free/g' |
sed '1b;/^Name/d' |
sed '/^$/d'
)"
Ultimately I would like to be able to call on a row and column and run statements on the values.
Initially i was piping that into :
awk -F "," 'NR>1{ if($5 < 10) { printf "%-30s%-10s%-10s%-10s%-10s\n", $1,$2,$3,$4,$5"%"; } else { echo "Nothing to do" } }')"
Which works but I couldn't run commands from if else ... or atleaste I didn't know how.
If you have bash 4.0 or newer, an associative array is an appropriate way to store data in this kind of form.
otscurrent=${otscurrent#$'\n'} # strip leading newline present in your sample data
declare -A data=( )
row=0
while IFS=, read -r -a line; do
for idx in "${!line[#]}"; do
data["$row,$idx"]=${line[$idx]}
done
(( row += 1 ))
done <<<"$otscurrent"
This lets you access each individual item:
echo "${data[0,0]}" # first field of first line
echo "${data[9,0]}" # first field of tenth line
echo "${data[9,1]}" # second field of tenth line
"I'm trying to get it to just print 12..."
The issue is that IFS="," splits on commas and there is no comma between 12 and BBB. If you want those to be separate elements, add a newline to IFS. Thus, replace:
IFS="," array1=(${otscurrent})
With:
IFS=$',\n' array1=(${otscurrent})
Output:
$ bash test.sh
12
All you need to print the value of the 4th column on the 5th row is:
$ awk -F, 'NR==5{print $4}' <<< "$otscurrent"
3453
and just remember that in awk row (record) and column (field) numbers start at 1, not 0. Some more examples:
$ awk -F, 'NR==1{print $5}' <<< "$otscurrent"
12
$ awk -F, 'NR==2{print $1}' <<< "$otscurrent"
BBB
$ awk -F, '$5 > 50' <<< "$otscurrent"
JJJ,51,59,110,54
KKK,87,123,210,59
MMM,617,1841,2458,75
SSS,1,24,25,96
TTT,0,5,5,100
UUU,294,1606,1900,85
If you'd like to avoid all of the complexity and simply parse your SQL output to produce what you want without 20 sed commands in between, post a new question showing the raw sqlplus output as the input and what you want finally output and someone will post a brief, clear, simple, efficient awk script to do it all at one time, or maybe 2 commands if you still want an intermediate CSV for some reason.
I am very new to Unix shell script and trying to get some knowledge in shell scripting. Please check my requirement and my approach.
I have a input file having data
ABC = A:3 E:3 PS:6
PQR = B:5 S:5 AS:2 N:2
I am trying to parse the data and get the result as
ABC
A=3
E=3
PS=6
PQR
B=5
S=5
AS=2
N=2
The values can be added horizontally and vertically so I am trying to use an array. I am trying something like this:
myarr=(main.conf | awk -F"=" 'NR!=1 {print $1}'))
echo ${myarr[1]}
# Or loop through every element in the array
for i in "${myarr[#]}"
do
:
echo $i
done
or
awk -F"=" 'NR!=1 {
print $1"\n"
STR=$2
IFS=':' read -r -a array <<< "$STR"
for i in "${!array[#]}"
do
echo "$i=>${array[i]}"
done
}' main.conf
But when I add this code to a .sh file and try to run it, I get syntax errors as
$ awk -F"=" 'NR!=1 {
> print $1"\n"
> STR=$2
> FS= read -r -a array <<< "$STR"
> for i in "${!array[#]}"
> do
> echo "$i=>${array[i]}"
> done
>
> }' main.conf
awk: cmd. line:4: FS= read -r -a array <<< "$STR"
awk: cmd. line:4: ^ syntax error
awk: cmd. line:5: for i in "${!array[#]}"
awk: cmd. line:5: ^ syntax error
awk: cmd. line:8: done
awk: cmd. line:8: ^ syntax error
How can I complete the above expectations?
This is the awk code to do what you want:
$ cat tst.awk
BEGIN { FS="[ =:]+"; OFS="=" }
{
print $1
for (i=2;i<NF;i+=2) {
print $i, $(i+1)
}
print ""
}
and this is the shell script (yes, all a shell script does to manipulate text is call awk):
$ awk -f tst.awk file
ABC
A=3
E=3
PS=6
PQR
B=5
S=5
AS=2
N=2
A UNIX shell is an environment from which to call UNIX tools (find, sort, sed, grep, awk, tr, cut, etc.). It has its own language for manipulating (e.g. creating/destroying) files and processes and sequencing calls to tools but it is NOT intended to be used to manipulate text. The guys who invented shell also invented awk for shell to call to manipulate text.
Read https://unix.stackexchange.com/questions/169716/why-is-using-a-shell-loop-to-process-text-considered-bad-practice and the book Effective Awk Programming, 4th Edition, by Arnold Robbins.
First off, a command that does what you want:
$ sed 's/ = /\n/;y/: /=\n/' main.conf
ABC
A=3
E=3
PS=6
PQR
B=5
S=5
AS=2
N=2
This replaces, on each line, the first (and only) occurrence of = with a newline (the s command), then turns all : into = and all spaces into newlines (the y command). Notice that
this works only because there is a space at the end of the first line (otherwise it would be a bit more involved to get the empty line between the blocks) and
this works only with GNU sed because it substitutes newlines; see this fantastic answer for all the details and how to get it to work with BSD sed.
As for what you tried, there is almost too much wrong with it to try and fix it piece by piece: from the wild mixing of awk and Bash to syntax errors all over the place. I recommend you read good tutorials for both, for example:
The BashGuide
Effective AWK Programming
A Bash solution
Here is a way to solve the same in Bash; I didn't use any arrays.
#!/bin/bash
# Read line by line into the 'line' variable. Setting 'IFS' to the empty string
# preserves leading and trailing whitespace; '-r' prevents interpretation of
# backslash escapes
while IFS= read -r line; do
# Three parameter expansions:
# Replace ' = ' by newline (escape backslash)
line="${line/ = /\\n}"
# Replace ':' by '='
line="${line//:/=}"
# Replace spaces by newlines (escape backslash)
line="${line// /\\n}"
# Print the modified input line; '%b' expands backslash escapes
printf "%b" "$line"
done < "$1"
Output:
$ ./SO.sh main.conf
ABC
A=3
E=3
PS=6
PQR
B=5
S=5
AS=2
N=2
I have a log file I am trying to comment out lines that do not match my array. I did successfully learn how to create an array and I can echo out the array items but I am having trouble taking anything that doesn't match my array and adding something in front of it. Here is my code, if you have suggestions on another path or ways I can make it better:
for itsSaturday in $(find "$LOCATION" -mindepth 1 -maxdepth 1 -name "*.log" ); do
TEMPFILE="$itsSaturday.$$"
declare -a someArray=( "breakfast" "scrambled eggs" "Bloody Mary" )
theCall='some_additional_text_'
commentOn="## You_need_"
for arrayItem in "${someArray[#]}"; do
merged="$theCall$arrayItem"
if ! grep -q "$merged" "$itsSaturday"; then
sed -e '/$merged/! s:$commentOn$theCall::g' "$itsSaturday" > $TEMPFILE && mv $TEMPFILE "$itsSaturday"
fi
done
done
file:
some_additional_text_breakfast
some_additional_text_bacon
some_additional_text_scrambled eggs
some_additional_text_Bloody Mary
some_additional_text_orange juice
some_additional_text_breakfast
file into:
some_additional_text_breakfast
## You_need_some_additional_text_bacon
some_additional_text_scrambled eggs
some_additional_text_Bloody Mary
## You_need_some_additional_text_orange juice
some_additional_text_breakfast
How can I add a variable before items that do not match my array?
I don't like doing this using bash and sed, but I think the following might be enough:
#! /bin/bash
declare -a someArray=( "breakfast" "scrambled eggs" "Bloody Mary" )
theCall='some_additional_text_'
commentOn="## You_need_"
OIFS="$IFS"
IFS='|' mergedLines="${someArray[*]/#/$theCall}"
IFS="$OIFS"
for i in *.txt
do
TEMPFILE="$i.$$"
sed -r "/$mergedLines/!s/^/$commentOn/" "$i" >> "$TEMPFILE"
done
I shifted the array and other constants out of the loop.
"${someArray[*]/#/$theCall}" uses bash string substitution to append the contents of $theCall to every element in the array.
IFS='|' mergedLines="${someArray[*]} is a convenient trick to combine the elements of an array into a pipe-separated string.
Combined, (2) and (3) get me
some_additional_text_breakfast|some_additional_text_scrambled eggs|some_additional_text_Bloody Mary
in mergedLines.
Then it's just a matter of using extended regular expressions in sed (for |) and replacing non-matching lines.
Your sed pattern used single quotes, so the variables within were not expanded.
Try replacing the inner for-loop with:
PROG=$(printf '%s\n' "${COMMENT[#]}" | while read comment ; do
/bin/echo -n '$0 !~ /'"$comment"'$/ && '
done
echo '1 { printf commentOn } ; { print }')
awk -v commentOn="$commentOn" "$PROG" $itsSaturday > $TEMPFILE && mv $TEMPFILE $itsSaturday
On each file, this creates an awk program that does the work.
First let me say I followed questions on stackoverflow.com that relate to my question and it seems the rules are not applying. Let me show you.
The following script:
#!/bin/bash
OUTPUT_DIR=/share/es-ops/Build_Farm_Reports/WorkSpace_Reports
TODAY=`date +"%m-%d-%y"`
HOSTNAME=`hostname`
WORKSPACES=( "bob" "mel" "sideshow-ws2" )
if ! [ -f $OUTPUT_DIR/$HOSTNAME.csv ] && [ $HOSTNAME == "sideshow" ]; then
echo "$TODAY","$HOSTNAME" > $OUTPUT_DIR/$HOSTNAME.csv
echo "${WORKSPACES[0]}," >> $OUTPUT_DIR/$HOSTNAME.csv
sed -i "/^'"${WORKSPACES[0]}"'/$/'"${WORKSPACES[1]}"'/" $OUTPUT_DIR/$HOSTNAME.csv
sed -i "/^'"${WORKSPACES[1]}"'/$/${WORKSPACES[2]}"'/" $OUTPUT_DIR/$HOSTNAME.csv
fi
I want the output to look like:
09-20-14,sideshow
bob,mel,sideshow-ws2
the sed statements are supposed to append successive array elements to preceding ones on the same line. Now I know there's a simpler way to do this like:
echo "${WORKSPACES[0]},${WORKSPACES[1]},${WORKSPACES[2]}" >> $OUTPUT_DIR/$HOSTNAME.csv
But let's say I had 30 elements in the array and I wanted to appended them one after the other on the same line? Can you show me how to loop through the elements in an array and append them one after the other on the same line?
Also let's say I had the output of a command like:
df -m /export/ws/$ws | awk '{if (NR!=1) {print $3}}'
and I wanted to append that to the end of the same line.
But when I run it I get:
+ OUTPUT_DIR=/share/es-ops/Build_Farm_Reports/WorkSpace_Reports
++ date +%m-%d-%y
+ TODAY=09-20-14
++ hostname
+ HOSTNAME=sideshow
+ WORKSPACES=("bob" "mel" "sideshow-ws2")
+ '[' -f /share/es-ops/Build_Farm_Reports/WorkSpace_Reports/sideshow.csv ']'
And the file right now looks like:
09-20-14,sideshow
bob,
I am happy to report that user syme solved this (see below) but then I realized I need the date in the first column:
09-7-14,bob,mel,sideshow-ws2
Can I do this using syme's for loop?
Okay user syme solved this too he said "Just add $TODAY to the for loop" like this:
for v in "$TODAY" "${WORKSPACES[#]}"
Okay now the output looks like this I changed the elements in the array btw:
sideshow
09-20-14,bob_avail,bob_used,mel_avail,mel_used,sideshow-ws2_avail,sideshow-ws2_used
Now below that the next line will be populated by a , in the first column skipping the date and then:
df -m /export/ws/$v | awk '{if (NR!=1) {print $3}}
which equals the value of available space on bob in the first iteration
and then:
df -m /export/ws/$v | awk '{if (NR!=1) {print $2}}
which equals the value of used space on bob in the 2nd iteration
and then we just move on to the next value in ${WORKSPACE[#]}
which will be mel and do the available and used as we did with bob or $v above.
I know you geniuses on here will make child's play out of this.
I solved my own last question on this thread:
WORKSPACES2=( "bob" "mel" "sideshow-ws2" )
separator="," # defined empty for the first value
for v in "${WORKSPACES2[#]}"
do
available=`df -m /export/ws/$v | awk '{if (NR!=1) {print $3}}'`
used=`df -m /export/ws/$v | awk '{if (NR!=1) {print $2}}'`
echo -n "$separator$available$separator$used" >> $OUTPUT_DIR/$HOSTNAME.csv # append, concatenated, the separator and the value to the file
done
produces:
sideshow
09-20-14,bob_avail,bob_used,mel_avail,mel_used,sideshow-ws2_avail,sideshow-ws2_used
,470400,1032124,661826,1032124,43443,1032108
echo -n permits to print text without the linebreak.
To loop over the values of the array, you can use a for-loop:
echo "$TODAY,$HOSTNAME" > $OUTPUT_DIR/$HOSTNAME.csv # with a linebreak
separator="" # defined empty for the first value
for v in "${WORKSPACES[#]}"
do
echo -n "$separator$v" >> $OUTPUT_DIR/$HOSTNAME.csv # append, concatenated, the separator and the value to the file
separator="," # comma for the next values
done
echo >> $OUTPUT_DIR/$HOSTNAME.csv # add a linebreak (if you want it)