I have this query from mysql
SELECT *
FROM table
LIMIT 100, 200
Now how do I write similar query in SQL Server 2008. Basically I'm using php and SQL Server as backend and need to display records in range (1-100 then 100-200)
Try this:
SELECT *
FROM
(SELECT
SomeColumn, ...,
ROW_NUMBER() OVER (ORDER BY SomeColumn) AS RowNumber
FROM
table) Aux
WHERE
RowNumber >= #start AND RowNumber < (#start + #length)
Notes: You need mandatory order by a column and also you have to make a subquery to get access to RowNumber in the WHERE clause
You can try this approach:
SELECT ID, ItemID, ItemName, UnitCost, UnitPrice
FROM
(
SELECT ID, ItemID, ItemName, UnitCost, UnitPrice,
ROW_NUMBER() OVER (ORDER BY UnitCost) AS Seq
FROM dbo.Inventory
)t
WHERE Seq BETWEEN 100 AND 200
you will basically use row_number to fetch they information that you need.
Related
Priority is the output column.
The group contains duplicate content.
how can I fix this using SQL query?.
enter image description here
One way to achieve the desired result with this data is to use Dense_rank() function like below:
select *, dense_rank() over (order by [Group]) as Priority
from tab
order by No
For any value, please try the following
;with cte as
(
select [Group], ROW_NUMBER() over (order by No_min) as rn
from
(
select [Group], min([No]) No_min
from tab
group by [Group]
)t
)
select t.*, x.rn as [Priority]
from cte x
join tab t on t.[Group] = x.[Group]
order by 1
Please find the db<>fiddle here.
How can I get only the last run of each SSIS job using a T-SQL query?
Please check the image. These details are stored in a single Table XYZ. Can anyone help me by providing a T-SQL query?
I am using this query:
select Job_Name, Start_Date, Finish_Time, Remarks
from #XYZ
order by Job_Name
You can use row_number()
select x.*
from (select x.*,
row_number() over (partition by job_name order by try_convert(datetime, Finish_Time) desc) as seq
from #XYZ x
) x
where x.seq = 1;
You can do this by adding a row_number to sort the data and then filtering to where a 1 is returned:
select cols
from(select cols
,row_number() over (partition by Job_Name order by Start_Date desc) as rn
from table
) as t
where rn = 1
Would anybody be able to help me with this exercise. I am used to querying on postgresql and not t-sql and I am running into trouble with how some of my data aggregates
My assignment requires me to:
Create a query that returns the number of comments made on each day for each post from the top 50 most commented on posts in the past year.
For example, this query below is giving me a non aggregated result set:
select cast(creationdate as date),
postid,
count(id)
from comments
where postid = 17654496
group by creationdate, postid
The schema is all here
https://data.stackexchange.com/stackoverflow/query/edit/898297
You can try to use CTE get the count by date.
then use window function with ROW_NUMBER make row number order by count amount desc.
;with CTE as (
select cast(creationdate as date) dt,
postid,
count(id) cnt
from comments
WHERE creationdate between dateadd(year,-1,getdate()) and getdate()
group by cast(creationdate as date), postid
), CTE2 AS (
select *,ROW_NUMBER() OVER (order by cnt desc) rn
from CTE
)
SELECT *
FROM CTE2
WHERE rn <=50
https://data.stackexchange.com/stackoverflow/query/898322/test
We have a data structure with four columns:
ContractoreName, ProjectCode, InvoiceID, OrderID
We want to group the data by both ContractoreName and ProjectCode columns, and then get the InvoiceID of the row for each group with MAX(OrderID).
You could use ROW_NUMBER:
SELECT ContractorName, ProjectName, OrderId, InvoiceId
FROM (SELECT *, ROW_NUMBER() OVER(PARTITION BY ContractorName, ProjectName
ORDER BY OrderId DESC) AS rn
FROM tab
) AS sub
WHERE rn = 1;
ROW_NUMBER() is what I would call the canonical solution. In many cases, an old-fashioned solution has better performance:
select t.*
from t
where t.orderid = (select max(t2.orderid)
from t t2
where t2.contractorname = t.contractorname and
t2.projectname = t.projectname
);
This is especially true if there is an index on (contractorname, projectname, orderid).
Why is this faster? Basically, SQL Server can scan the table doing a lookup in an index. The lookup is really fast because the index is designed for it, so the scan is just a little faster than a full table scan.
When using row_number(), SQL Server has to scan the table to calculate the row number (and that can use the index, so it might be fast). But then it has to go back to the table to fetch the columns and apply the where clause. So, even if it uses an index, it is doing more work.
EDIT:
I should also point out that this can be done without a subquery:
select distinct contractorname, projectname,
max(orderid) over (partition by contractorname, projectname) as lastest_order,
first_value(invoiceid) partition by (order by contractorname, projectname order by orderid desc) as lastest_invoice
from t;
Unfortunately, SQL Server doesn't offer first_value() as an aggregation function, but you can use select distinct and get the same effect.
I have a table which has around 300,000 rows. 225 Rows are being added to this table daily since March 16,2015 till July 09,2015
My problem is that, from last 1 week or so, some duplicate rows are being entered in the table (i.e more than 225 per day)
Now I want to select (and ultimately delete!) all the duplicate rows from the table that have more than 1 siteID+ reportID combination existing against one Date column .
Example is attached in the screenshot:
When Row_Number() is used with Partition By clause, it can provide the SQL developer to select duplicate rows in a table
Please check the SQL tutorial on how to delete duplicate rows in SQL table
Below query is what is copied from that article and applied to your requirement:
;WITH DUPLICATES AS
(
SELECT *,
RN = ROW_NUMBER() OVER (PARTITION BY siteID, ReportID ORDER BY Date)
FROM myTable
)
DELETE FROM DUPLICATES WHERE RN > 1
I hope it helps,
When you want to filter duplicated rows I suggest you this type of query:
SELECT *
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY Col1, Col2 ORDER BY Col3) As seq
FROM yourTable) dt
WHERE (seq > 1)
Like this:
SELECT *
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY siteID, reportID, [Date] ORDER BY ID) As seq
FROM yourTable) dt
WHERE (seq > 1)