Error : Wrong comparison between pointer and integer - c

Question

My code seems fine, but I get this warning (warning: comparison between pointer and integer), what is the best solution to solve this problem?
I have already used double notation marks for (char exit = "E"), also used the same thing with while but the same problem.
#include <stdio.h>
int main()
{
char c[1];
char exit = 'E';
while (c != exit)
{
printf("Enter a character\n\n");
scanf("%s", c);
printf("your character is : %s\n-------------------\n", c);
}
}

Answer 1

#include <stdio.h>
int main()
{
char c[1];
char exit = 'E';
while (c != exit) // here ...
{
printf("Enter a character\n\n");
scanf("%s", c);
printf("your character is : %s\n-------------------\n", c);
}
}
you are trying to compare a char to the pointer the array c decays to. What you perhaps wanted to do is to compare the first character of the array to the character exit:
while (c[0] != exit)
But that still doesn't make much sense since c is uninitialized and the user not yet had a chance to make any input. Better use a do ... while-loop:
#include <stdio.h>
int main()
{
char c[1];
char exit = 'E';
do {
printf("Enter a character\n\n");
scanf("%s", c);
printf("your character is : %s\n-------------------\n", c);
} while (c[0] != exit);
}
Next thing is, that scanf("%s", c); could fail (yes unlikely, but possible). And the user could enter more characters than there is room for in the array c. You should never use scanf() whithout checking the return value nor "%s" without specifying a WIDTH for the conversion specifier to limit the characters put into the array.
When reading a string you need memory for WIDTH characters + a terminating '\0'. So if you want to read a string of one character, the array has to have at least 2 elements:
#include <stdlib.h
#include <stdio.h>
int main()
{
char c[2];
char exit = 'E';
do {
printf("Enter a character\n\n");
while (scanf("%1s", c) != 1 ) {
fputs("Input error!\n");
return EXIT_FAILURE;
}
printf("your character is : %s\n-------------------\n", c);
} while (c[0] != exit);
}
But if you only want to read one character you are better off with getchar():
#include <stdio.h>
{
int ch;
while (printf("Enter a character\n\n"),
(ch = getchar()) != EOF && ch != 'E')
{
printf("your character is: %c\n-------------------\n", (char) ch);
}
}

Answer 2

i believe this is what you are trying to do.
warning is because you have not initialzed your character and also you were comparing address of character to character value.
#include <stdio.h>
int main()
{
char c[1];
char exit = 'E';
while ((c[0]=getchar()) != exit)
{
if(c[0]==EOF)break;
printf("your character is : %c\n",c[0]) ;
}
printf("ended");
}