How to print string into an array after used the isdigit? - c

Question

I'm very new to isdigit and the string. I really need help from you guys. I want to print string into an array 'food[f]'.But can you guys help me to check where is my problem ? Here is my code.
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main()
{
char foo[20];
float price;
int number=1;
int f=0,i=0;
char *food[f];
adding_food :
food[f] = (char*)malloc(25);
printf("Adding food into Menu (0 to Main Menu): ");
scanf("%s", foo);
{
if(isdigit(foo[0])== 0)
{
foo[i] = *food[f]; //something wrong here
printf("Enter price (RM) : ");
scanf("%f",&price);
printf("\n%-16d%-19s%6.2f\n\n",number,foo,price);
printf("\n%-16d%-19s%6.2f\n\n",number,food[f],price);
number++;
i++;
f++;
goto adding_food;
}
else
return 0;
}
}
I would like my output be like this
Adding food into Menu (0 to Main Menu) : Cake
Enter price (RM) : 10
1 Cake 10 //foo[0]
1 Cake 10 //food[0]

Answer 1

There are several mistakes in your code. Example:
char *food[f];
is similar to
char *food[0];
as f is zero. That makes no sense.
Also the use of goto is not considered good style.
So let me show you another approach. Something like:
// Make a type that can hold both a name and a price
struct item
{
char name[25];
float price;
};
#define MAX_ITEMS 100
struct item* addItems(int* n)
{
*n = 0;
struct item* items = malloc(MAX_ITEMS * sizeof *items);
if (items == NULL) return NULL;
while (*n != MAX_ITEMS)
{
scanf("%24s", items[*n].name);
if (items[*n].name[0] == '0') break;
scanf("%f", &items[*n].price);
*n += 1;
}
return items;
}
void print_all(struct item* my_items, int num_items)
{
for (int i = 0; i < num_items; ++i)
printf("%s %f\n", my_items[i].name, my_items[i].price);
}
int main()
{
int num_items;
struct item* my_items = addItems(&num_items);
print_all(my_items, num_items);
free(my_items);
}