strcpy() only storing last string - c

Question

I want to store elements of an array containing strings to make it accessible via a shared memory segment. I am currently using strcpy(), but it is obviously only storing the last string in the array. How would I make it store all 4 strings in the array? Currently I can only choose which line I would like to send (e.g. the first line with the two loops below:
Here is my loop in the server program:
for(int j = 0; j < 1;j++){
strcpy(mem,words);
}
and the client program:
for(int i = 0; i < 1; i++){
printf("%s\n",mem);
}
here is the full server program:
int main() {
const key_t key = 12345678;
FILE *ptr_fp;
char words[600][600];
char *mem;
int i = 0;
ptr_fp = fopen("words.txt","r");
int shmid = shmget(key, sizeof(float)*8, 0644 | IPC_CREAT);
if (shmid < 0) {
perror("shmget");
exit(1);
}
if (ptr_fp != NULL){
while(fgets(words[i],600,ptr_fp )&& i <600){
i++;
}
}
mem = (char *)shmat(shmid,NULL,0);
if(mem == (char *)-1){
perror("shmat error\n");
exit(1);
} else {
for(int j = 0; j < 1;j++){
strcpy(mem,words);
}
printf("Memory is attached\n");
}
return 0;
}

Answer 1

This looks like a copy-paste mistake.
In this while loop, i gets updated.
while(fgets(words[i],600,ptr_fp )&& i <600) {
i++;
}
In the for loop, j should be compared to i in the controlling expression, instead it is compared with 1
for(int j = 0; j < 1; j++) {
strcpy(mem,words);
}
I think the above should be changed to:
for(int j = 0, k = 0; j < i; j++) {
strcpy((mem + k),words[j]);
k = k+ strlen(words[j]);
}