C: 2-Dimensional String Array Segmentation Fault - c

Question

Trying to make a small program that separates words within a big string and stores each word (of the big string) in a string (i.e pointer) in an array of strings (i.e pointers); forming a 2-dimensional string array.
The word separator is simply a whitespace (32 in ASCII); the big string is:
"Showbizzes Oxygenized Equalizing Liquidized Jaywalking"
Note:
the words are all 10 characters in length
the total length of the string is 54 characters (spaces included)
the total size of the buffer is 55 bytes ('\0' included)
One more thing, the last pointer in the array of pointers must hold a 0 (i.e 1 character: '\0') (this is completely arbitrary).
Here is the program, nothing special, but ...
#include <stdio.h>
#include <stdlib.h>
int main(void) {
// The string that we need to break down into individual words
char str[] = "Showbizzes Oxygenized Equalizing Liquidized Jaywalking";
// Allocate memory for 6 char pointers (i.e 6 strings) (5 of which will contain words)
// the last one will just hold 0 ('\0')
char **array; array = malloc(sizeof(char *) * 6);
// i: index for where we are in 'str'
// r: index for rows of array
// c: index for columns of array
int i, r, c;
// Allocate 10 + 1 bytes for each pointer in the array of pointers (i.e array of strings)
// +1 for the '\0' character
for (i = 0; i < 6; i++)
array[i] = malloc(sizeof(char)*11);
// Until we reach the end of the big string (i.e until str[i] == '\0');
for (i = 0, c = 0, r = 0; str[i]; i++) {
// Word seperator is a whitespace: ' ' (32 in ASCII)
if (str[i] == ' ') {
array[c][r] = '\0'; // cut/end the current word
r++; // go to next row (i.e pointer)
c = 0; // reset index of column/letter in word
}
// Copy character from 'str', increment index of column/letter in word
else { array[c][r] = str[i]; c++; }
}
// cut/end the last word (which is the current word)
array[c][r] = '\0';
// go to next row (i.e pointer)
r++;
// point it to 0 ('\0')
array[r] = 0;
// Print the array of strings in a grid - - - - - - - - - - - - - -
printf(" ---------------------------------------\n");
for (r = 0; r < 6; r++) {
printf("Word %i --> ", r);
for (c = 0; array[c][r]; c++)
printf("| %c ", array[c][r]);
printf("|");printf("\n");
printf(" ---------------------------------------");
printf("\n");
}
// - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
return 0;
}
.. there's something wrong and I don't understand how to fix it.
For some reason it copies into the first string (i.e pointer), in the array of strings (i.e pointers), the first 6 characters of the big string, then on the 7th it gives a segmentation fault. I've allocated 6 pointers each with 11 bytes.. at least thats what I think the code is doing, so really I have NO clue why this is happening...
Hope someone can help.

Answer 1

Replace all ocurrences of array[c][r] with array[r][c]
The first dimension is the row.
Next time you can check this using a debugger:
Program received signal SIGSEGV, Segmentation fault.
0x00000000004007ea in main () at demo.c:37
37 array[c][r] = str[i];