Conditionally reuse a `hasOne` association multiple times inside the same query - cakephp

Question

What I have
In my OrdersTable.php:
$this->hasOne('Total', [
'className' => 'App\Model\Table\TotalsTable',
'foreignKey' => 'order_id',
'propertyName' => 'Total'
]);
Actual totals table:
| id | order_id | type | value |
|----|----------|----------|-------|
| 1 | 1 | total | 100 |
| 2 | 1 | tax | 20 |
| 3 | 1 | shipping | 5 |
The structure and logic come from opencart/opencart and I have no control over that.
What I want
This is a non-functional concept:
$query = $ordersTable->find('all', array(
'contain' => array(
'TotalTax' => [
'associationName' => 'Total',
'conditions' => function($query) {
return $query->where([
'TotalTax.type' => 'tax',
]);
},
],
'TotalShipping' => [
'associationName' => 'Total',
'conditions' => function($query) {
return $query->where([
'TotalShipping.type' => 'shipping',
]);
},
],
),
));
Do you guys think something like this is possible?
UPD: Creating an association for each type isn't an option since there may be too many of them

Answer 1

If this functionality is something that will be reused with your codebase, I would implement this logic at the table level and have two different conditional associations:
In OrdersTable.php
$this->hasOne('TotalTax', [
'className' => 'Totals'
])
->setConditions(['TotalTax.type' => 'tax'])
->setDependent(true);
$this->hasOne('TotalShipping', [
'className' => 'Totals'
])
->setConditions(['TotalShipping.type' => 'shipping'])
->setDependent(true);
Then you can simply contain them in the query:
$query = $ordersTable->find()->contain(['TotalTax', 'TotalShipping'];
An example of this can be found in the CakePHP documentation