Replacing column 2 in original with column 2 in new - file

Question

I have a file containing thousands of original results and a file containing hundreds of new results. Only column 2 of new is different from the original. I also need to keep original results that haven't been changed. How should I go about doing this? Is it possible to create a file3 containing the original results which did not change and the new results? see below for an example.
Original New file3
1:1:1 2:5:2 1:1:1
2:2:2 3:4:3 2:5:2
3:3:3 5:9:5 3:4:3
4:4:4 6:8:6 4:4:4
5:5:5 5:9:5
6:6:6 6:8:6
7:7:7 7:7:7

Answer 1

awk
awk -F':' '{a[$1]=$0}END{for(i in a) print a[i]}' Original_file new_file | sort
Original_file new_file - read both files
for each one of the files read line and:
1) -F':' - use : as separator
2) a[$1]=$0 - create a Hash that it's key is the first column and the value is the all line. if key exists run it over with the new value.
3) for(i in a) print a[i] - print the hash values
4) sort - sort results by order

Answer 2

You can use the diff command between the old file and the new file.
diff -y Original.txt New.txt
Original New
1:1:1 1:1:1
2:2:2 | 2:5:2
3:3:3 | 3:4:3
4:4:4 4:4:4
5:5:5 | 5:9:5
6:6:6 | 6:8:6
7:7:7 7:7:7
For each line, if it contain this character "|" use the command awk to catch the value of new file. Otherwise catch the value of one of both sides, after all both are equals.
Try something how this:
number_of_lines_pipe=$(diff -y Orginal.txt New.txt | grep -e "|" | wc - l)
number_of_lines_without_pipe=$(diff -y Orginal.txt New.txt | grep -v "|" | wc - l)
for ((i = 1; i <= $number_of_lines_pipe; i++))
do
line=$(diff -y Orginal.txt New.txt | grep -e "|" | sed -n $i'p')
echo "$line" | awk -F"|" '{ print $2 }' | sed 's/\t *//' >> File3.log
done
for ((i = 1; i <= $number_of_lines_without_pipe; i++))
do
line=$(diff -y Orginal.txt New.txt | grep -v "|" | sed -n $i'p')
echo "$line" | awk -F" " '{ print $1 }' >> File3.log
done