avoid Negative Array Size Exception with try, catch and throw - arrays

Question

The following Java code:
public class SomeClass {
int[] table;
int size;
public SomeClass(int size) {
this.size = size;
table = new int[size];
}
public static void main(String[] args) {
int[] sizes = {5, 3, -2, 2, 6, -4};
SomeClass testInst;
for (int i = 0; i < 6; i++) {
testInst = new SomeClass(sizes[i]);
System.out.println("New example size " + testInst.size);
}
}
}
The first two instances of SomeClass, which have size 5 and 3, will be created without a problem. However, when the constructor SomeClass is called with an argument of -2, a run time error is generated: NegativeArraySizeException.
how can i modify the above code so that it behaves more robustly by using try, catch and throw. The main method should catch this exception and print a warning message then continue execution of the loop.
im a java newbie so would appreciate any help.
thanks

Answer 1

make the class constructor throw the error and catch it in the main class , like this :
public class SomeClass {
int[] table;
int size;
public SomeClass(int size) throws NegativeArraySizeException{
this.size = size;
table = new int[size];
}
public static void main(String[] args) {
int[] sizes = {5, 3, -2, 2, 6, -4};
SomeClass testInst;
for (int i = 0; i < 6; i++) {
try {
testInst = new SomeClass(sizes[i]);
System.out.println("New example size " + testInst.size);
}
catch (NegativeArraySizeException err) {
System.out.println(err.toString());
}
}
}
}
the output would be