Define a `static const` SIMD Variable within a `C` Function - c

Question

I have a function in this form (From Fastest Implementation of Exponential Function Using SSE):
__m128 FastExpSse(__m128 x)
{
static __m128 const a = _mm_set1_ps(12102203.2f); // (1 << 23) / ln(2)
static __m128i const b = _mm_set1_epi32(127 * (1 << 23) - 486411);
static __m128 const m87 = _mm_set1_ps(-87);
// fast exponential function, x should be in [-87, 87]
__m128 mask = _mm_cmpge_ps(x, m87);
__m128i tmp = _mm_add_epi32(_mm_cvtps_epi32(_mm_mul_ps(a, x)), b);
return _mm_and_ps(_mm_castsi128_ps(tmp), mask);
}
I want to make it C compatible.
Yet the compiler doesn't accept the form static __m128i const b = _mm_set1_epi32(127 * (1 << 23) - 486411); when I use C compiler.
Yet I don't want the first 3 values to be recalculated in each function call.
One solution is to inline it (But sometimes the compilers reject that).
Is there a C style to achieve it in case the function isn't inlined?
Thank You.

Answer 1

Remove static and const.
Also remove them from the C++ version. const is OK, but static is horrible, introducing guard variables that are checked every time, and a very expensive initialization the first time.
__m128 a = _mm_set1_ps(12102203.2f); is not a function call, it's just a way to express a vector constant. No time can be saved by "doing it only once" - it normally happens zero times, with the constant vector being prepared in the data segment of the program and simply being loaded at runtime, without the junk around it that static introduces.
Check the asm to be sure, without static this is what happens: (from godbolt)
FastExpSse(float __vector(4)):
movaps xmm1, XMMWORD PTR .LC0[rip]
cmpleps xmm1, xmm0
mulps xmm0, XMMWORD PTR .LC1[rip]
cvtps2dq xmm0, xmm0
paddd xmm0, XMMWORD PTR .LC2[rip]
andps xmm0, xmm1
ret
.LC0:
.long 3266183168
.long 3266183168
.long 3266183168
.long 3266183168
.LC1:
.long 1262004795
.long 1262004795
.long 1262004795
.long 1262004795
.LC2:
.long 1064866805
.long 1064866805
.long 1064866805
.long 1064866805

Answer 2

_mm_set1_ps(-87); or any other _mm_set intrinsic is not a valid static initializer with current compilers, because it's not treated as a constant expression.
In C++, it compiles to runtime initialization of the static storage location (copying from a vector literal somewhere else). And if it's a static __m128 inside a function, there's a guard variable to protect it.
In C, it simply refuses to compile, because C doesn't support non-constant initializers / constructors. _mm_set is not like a braced initializer for the underlying GNU C native vector, like #benjarobin's answer shows.
This is really dumb, and seems to be a missed-optimization in all 4 mainstream x86 C++ compilers (gcc/clang/ICC/MSVC). Even if it somehow matters that each static const __m128 var have a distinct address, the compiler could achieve that by using initialized read-only storage instead of copying at runtime.
So it seems like constant propagation fails to go all the way to turning _mm_set into a constant initializer even when optimization is enabled.
Never use static const __m128 var = _mm_set... even in C++; it's inefficient.
Inside a function is even worse, but global scope is still bad.
Instead, avoid static. You can still use const to stop yourself from accidentally assigning something else, and to tell human readers that it's a constant. Without static, it has no effect on where/how your variable is stored. const on automatic storage just does compile-time checking that you don't modify the object.
const __m128 var = _mm_set1_ps(-87); // not static
Compilers are good at this, and will optimize the case where multiple functions use the same vector constant, the same way they de-duplicate string literals and put them in read-only memory.
Defining constants this way inside small helper functions is fine: compilers will hoist the constant-setup out of a loop after inlining the function.
It also lets compilers optimize away the full 16 bytes of storage, and load it with vbroadcastss xmm0, dword [mem], or stuff like that.

Answer 3

This solution is clearly not portable, it's working with GCC 8 (only tested with this compiler):
#include <stdio.h>
#include <stdint.h>
#include <emmintrin.h>
#include <string.h>
#define INIT_M128(vFloat) {(vFloat), (vFloat), (vFloat), (vFloat)}
#define INIT_M128I(vU32) {((uint64_t)(vU32) | (uint64_t)(vU32) << 32u), ((uint64_t)(vU32) | (uint64_t)(vU32) << 32u)}
static void print128(const void *p)
{
unsigned char buf[16];
memcpy(buf, p, 16);
for (int i = 0; i < 16; ++i)
{
printf("%02X ", buf[i]);
}
printf("\n");
}
int main(void)
{
static __m128 const glob_a = INIT_M128(12102203.2f);
static __m128i const glob_b = INIT_M128I(127 * (1 << 23) - 486411);
static __m128 const glob_m87 = INIT_M128(-87.0f);
__m128 a = _mm_set1_ps(12102203.2f);
__m128i b = _mm_set1_epi32(127 * (1 << 23) - 486411);
__m128 m87 = _mm_set1_ps(-87);
print128(&a);
print128(&glob_a);
print128(&b);
print128(&glob_b);
print128(&m87);
print128(&glob_m87);
return 0;
}
As explained in the answer of #harold (in C only), the following code (build with or without WITHSTATIC) produces exactly the same code.
#include <stdio.h>
#include <stdint.h>
#include <emmintrin.h>
#include <string.h>
#define INIT_M128(vFloat) {(vFloat), (vFloat), (vFloat), (vFloat)}
#define INIT_M128I(vU32) {((uint64_t)(vU32) | (uint64_t)(vU32) << 32u), ((uint64_t)(vU32) | (uint64_t)(vU32) << 32u)}
__m128 FastExpSse2(__m128 x)
{
#ifdef WITHSTATIC
static __m128 const a = INIT_M128(12102203.2f);
static __m128i const b = INIT_M128I(127 * (1 << 23) - 486411);
static __m128 const m87 = INIT_M128(-87.0f);
#else
__m128 a = _mm_set1_ps(12102203.2f);
__m128i b = _mm_set1_epi32(127 * (1 << 23) - 486411);
__m128 m87 = _mm_set1_ps(-87);
#endif
__m128 mask = _mm_cmpge_ps(x, m87);
__m128i tmp = _mm_add_epi32(_mm_cvtps_epi32(_mm_mul_ps(a, x)), b);
return _mm_and_ps(_mm_castsi128_ps(tmp), mask);
}
So in summary it's better to remove static and const keywords (better and simpler code in C++, and in C the code is portable since with my proposed hack the code is not really portable)