batch with a lot of for loops - batch-file

So i made this batch to psarc extract all *.pak files, which will always give *.mbin files that often have the same name. it's then supposed to look for all extracted subfolders and then look for the last created *.mbin file from all of the subfolders and rename it to its current name plus a number. but i get very weird results.
setlocal ENABLEDELAYEDEXPANSION
set number=0
cd /d "C:\Users\storm\Desktop\No Man's Sky\GAMEDATA\PCBANKS\MODS"
for /r %%f in (*.pak=) do (
psarcMBIN.exe extract %%~nxf
set /A number=!number!+1
FOR /F "tokens=" %%a in ('dir /a:d /s') do (
cd /d "%%a"
FOR /F "tokens=" %%G in ('dir /b /a:-d /o:d "*.mbin"') do set newest=%%G
rename "!newest!" "!newest!!number!.mbin"
)
)
pause
The result basically is just:
1. psarc extracted
2. psarc tried to extract next file but cannot overwrite
The other parts of the main for loop are not even shown

Related

Updating Sub folder and File renaming batch script

Need a bit of help with this script
for /d %%D in ("*") do (
for %%F in ("%%D\*.jpg") do (
ren "%%~dpF(*).txt" "(*) %%~nF.*"
)
)
This is the original script and this is what it does
Before
filename.jpg
(1).txt
Result
filename.jpg
(1) filename.txt
it copies the filename from the jpg and adds it to the filename of the txt file
what I have been trying to do is two things
I want to add a controlled Sub folder reader to it, and I would like to the filename to be copied between certain points of the txt files
Before
filename.jpg
(1)(name).txt
Result
filename.jpg
(1) filename (name).txt
I have tried like 10 different ways to make this work and for some reason I can't
tried this
FOR /f "delims=" %%q IN ('dir /b /s /a-d "Ready\(*)(Name).txt"') DO call :label "%%q"
goto :eof
:Label
set "FILE=%~1"
for /d %%D in ("*") do (
for %%F in ("%%D\*.jpg") do (
ren "%%~dpF(*)(Name).txt" "(*) %%~nF (*).*"
)
)
and I removed this as well for /d %%D in ("*") do (
and tried this
FOR /f "delims=" %%q IN ('dir /b /s /a-d "Ready\(*)(Name).txt"') DO call :label "%%q"
goto :eof
:Label
set "FILE=%~1"
for %%F in ("*.jpg") do (
ren "%%~dpF%~1" "(*) %%~nF (*).*"
)
and tried this
for /d %%D in ('dir /b /s /a-d "*"') do (
for %%F in ("%%D\*.jpg") do (
ren "%%~dpF(*)(Name).txt" "(*) %%~nF (*).*"
)
)
Any help would be great
Thank you
#ECHO OFF
SETLOCAL
rem The following setting for the source directory is a name which include spaces to make sure
rem that the process works using such names. These will need to be changed to suit your situation.
SET "sourcedir=u:\your files"
PUSHD "%sourcedir%"
for /d %%B in ("*") do (
for %%E in ("%%B\*.jpg") do (
FOR /f "tokens=1,2delims=()" %%q IN ('dir /b /a-d "%%~dpnxB\(*)(*).txt" 2^>nul') DO (
rem files matching "(*)(*).txt only
REN "%%~dpnxB\(%%q)(%%r).txt" "(%%q) %%~nE (%%r).txt"
)
FOR /f "tokens=1*delims=()" %%q IN ('dir /b /a-d "%%~dpnxB\(*).txt" 2^>nul') DO IF /i "%%r" equ ".txt" (
rem files matching "(*).txt only
REN "%%~dpnxB\(%%q).txt" "(%%q) %%~nE.txt"
)
)
)
popd
GOTO :EOF
Caution : This batch is armed. It will rename files. Always verify against a test directory before applying to real data.
The outer loop on %%B gets the directory names. No surprise there.
The next loop on %%E gets the .jpg names. No surprise there.
The first loop on %%q looks at the .txt files that fit the pattern (*)(*).txt and re-assembles the parts as required for the rename.
The second loop on %%q looks at the .txt files that fit the pattern (*).txt which may include the just-renamed files matching (*)(*).txt now (*) jpgfilename (*).txt, so this time, %%r must be .txt to exclude these newly-renamed files.
I'll repeat
Caution : This batch is armed. It will rename files. Always verify against a test directory before applying to real data.

Piping string with folders in variable to findstr - copy and rename files

I'm trying to pipe a string that contains folder paths to findstr to search for a particular part in the names of the given folders - or at least, that is what I'm planning to do.
I've got a source folder with files that have to be copied into multiple subfolders and after that, one of the copied files has to be renamed corresponding to the destination folder. If there already are files with the same names, they have to be overwritten. I am trying to achieve this via .bat-file using the following commands in my code:
pushd ..\..\destination_folder\
FOR /F "delims=" %%i in ('dir /AD /S /B^| findstr /I "._Modul_X$"') do copy ..\xxx\yyy\ressources\*.* %%i
& ren %%i\xxxx_Modul_X.BAT_TEMPLATE" "%%i_Modul_X.BAT_TEMPLATE
The copy-part seems to work, the rename-part does not and when it comes to overwriting the one file that has to be renamed after copying it (name conflict!), I'm pretty clueless how to do this (IF EXIST & DEL?).
If I understand the process you're attempting, then the following should do as you require, subject to my assumption that xxxx is a sequence of exactly four, digits (directory names), and characters (file names):
#Echo Off
SetLocal EnableExtensions
PushD "..\..\destination_folder" 2>NUL || GoTo :EOF
If Not Exist "..\xxx\yyy\resources\*.*" GoTo :EOF
For /F "Delims=" %%G In (
'Dir /B /S /A:D "????_Modul_X" 2^>NUL ^|%__AppDir__%findstr.exe^
/I /R "\\[0123456789][0123456789][0123456789][0123456789]_Modul_X"'
) Do (
For /F "Delims=" %%H In (
'%__AppDir__%where.exe /F "%%G":"????_Modul_X.BAT_TEMPLATE" 2^>NUL'
) Do Del /A /F %%H
Copy /Y "..\xxx\yyy\resources\*.*" "%%G" 1>NUL
For /F "Delims=" %%I In (
'%__AppDir__%where.exe /F "%%G":"????_Modul_X.BAT_TEMPLATE" 2^>NUL'
) Do If /I Not "%%~nxI" == "%%~nxG%%~xI" Ren %%I "%%~nxG%%~xI"
)
Please note that you will probably need to modify both instances of xxx\yyy\resources, (lines 5 and 14), as nobody really uses names like that, paying special attention to the spelling, I've used resources above, not ressources.

Batch - Returning full path from a dir /b

I am traversing folders on a drive, collecting file names with specific extensions, and building a string which is later used in a command line switch. When I find a qualifying file I need to know its full path as this is what is required by the command line. I currently use "%~dp0%%a\%%b" to build the full path, but I can see that may have limitations later on when the batch becomes more complex (e.g. it digs deeper into sub folders). I am hoping there is a way to replace "%~dp0%%a\%%b" with the path to the located file. Thank you:
#ECHO OFF
for /f "usebackq tokens=*" %%a in (`dir /b /a:d`) do (
pushd %%a
setlocal ENABLEDELAYEDEXPANSION
for /f "delims=" %%b in ('dir /b "*.E01" "*.L01" "*.AD1" 2^>nul') do (
SET EVIDENCE_STR=!EVIDENCE_STR! /e:"%~dp0%%a\%%b"
)
IF DEFINED EVIDENCE_STR (
ECHO !EVIDENCE_STR!
) ELSE (
ECHO No evidence files located in: %%a
)
endlocal
SET EVIDENCE_STR=
popd
)
PAUSE
Why do you need to create 2 loops, each running a dir command to find files? Why not just do for /R loop? Here is an example:
#echo off
set "files=*.E01 *.L01 *.AD"
for /R %%a in (%files%) do echo %%a
Simply use "Sub"-Option: /S of the DIR-Command:
Dir /B /S C:\*.jpg
cause it is that equivalent to:
#echo off
set "DirPath=C:\"
set "files=*.jpg"
for /R %DirPath% %%a in (%files%) do echo %%a
and so you should got the same result in each script.
The Problem: If you don't want any deep of SubDirectorys, you've to filter out these and so you may lose time - in both solutions.

create folders based on string in file name

I need a batch file to create a process for a list of files in a directory.
The filename structure is, for example: 00000_AAA_132144_2012021.txt
I need the batch to:
1 - Create a folder name based on the numbers after the second underscore, as this is the only constant in the naming.
2 - Move the file into the new folder.
In the example of the above the batch would create a folder called 132144 and then move the file 00000_AAA_132144_2012021.txt into the folder
For a similar requirement I used the script Endoro created for me (below). Is it possible to modify this to meet my requirement?
#echo off &setlocal
for /f "delims=" %%i in ('dir /b /a-d *.PDF') do (
set "filename1=%%~i"
setlocal enabledelayedexpansion
set "folder1=!filename1:~11,6!"
mkdir "!folder1!" 2>nul
move "!filename1!" "!folder1!"
endlocal
)
If you know that the filenames will be the same length, you can do the following to get the numbers after the second underscore -
set filename=00000_AAA_132144_2012021.txt
set dirname=%filename:~10,6%
If the spacing may vary - you can do the following -
for /f "delims=_ tokens=3" %%a in ('echo %filename%') do set dirname=%%a
And yes, the script written for you seems to do essentially the same thing as what you're asking - I've edited it to do what you've asked -
#echo off
setlocal enabledelayedexpansion
for /f %%i in ('dir /b /a-d *.txt') do (
set "filename=%%~i"
for /f "delims=_ tokens=3" %%a in ('echo !filename!') do set folder=%%a
mkdir "!folder!" 2>nul
move "!filename!" "!folder!"
)
This will move all *.txt documents to a folder created based on the third section of the text files name. Note that this will cause problems if you have .txt documents in the directory that do not follow the same naming standard.
#ECHO OFF
SETLOCAL
SET "sourcedir=c:\sourcedir"
SET "destdir=c:\destdir"
FOR /f "delims=" %%a IN ('dir /b /a-d "%sourcedir%\*_*_*_*.txt" ') DO (
FOR /f "tokens=3delims=_" %%m IN ("%%a") DO (
ECHO MD "%destdir%\%%m"
ECHO MOVE "%sourcedir%\%%a" "%destdir%\%%m\"
)
)
GOTO :EOF
Endoro's routine selects .pdf files, you've specified .txt
Find filenames matching the mask, find the third _-separated token in the name, make that directory and then move the file.
The required commands are merely ECHOed for testing purposes. After you've verified that the commands are correct, change ECHO MD to MD to actually create the directories and change ECHO MOVE to MOVE to actually move the files.
Append 2>nul to suppress error messages (eg. when the directory already exists)
Append >nul to suppress report messages (eg. 1 file moved)

Batch file that keeps the 7 latest files in a folder

Can anyone help me create a batch file? Basically, my goal is to create a batch file that will keep the LATEST 7 .txt files (in other words, the newest) in the folder and subsequently delete the rest. That's IF there are more than 7 files in the folder.
The problem I'm having right now is the fact that the batch file that I have created deletes most of the files because their date is from a month or two or so. I want to keep the latest 7 files at all times no matter how old they are.
So this is what I have -
#echo off
setlocal enableextensions
rem ********************************************************************************
rem ******************************* LOCAL VARIABLES ******************************
rem ********************************************************************************
SET TargetDirectory="C:\TEMP\test"
SET No_of_fles_to_keep=7
SET count=0
set cnt=0
rem ********************************************************************************
cd /d %TargetDirectory%
REM timeout /T 500
for %%x in (*) do set /a count+=1
for %%A in (*.bat) do set /a cnt+=1
cd /d %TargetDirectory%
REM timeout /T 500
IF %count% gtr %No_of_fles_to_keep% forfiles -p %TargetDirectory% -s -m "*.txt" -d -%No_of_fles_to_keep% -c "cmd /c del #path"
echo %count%
echo File count = %cnt%
Any help is appreciated.
You can use DIR with /O-D to list the text files in descending timestamp order. FOR /F allows you to iterate over each file. SET /A is used to keep track of how many files have been listed so far. Now comes the tricky part.
Within a code block you normally need to use delayed expansion to work with the value of a variable that was set earlier in the same block. But delayed expansion can cause problems in a FOR loop if the FOR variable value contains !, and ! is valid in file names. I get around the problem by using SET /A to intentionally divide by 0 when the 7th file name has been read. This raises an error that causes the conditional code to execute that undefines the KEEP variable. From that point on, all remaining files are deleted.
#echo off
setlocal
set /a cnt=0
set "keep=7"
for /f "eol=: delims=" %%F in ('dir /b /o-d /a-d *.txt') do (
if defined keep (
2>nul set /a "cnt+=1, 1/(keep-cnt)" || set "keep="
) else del "%%F"
)
Update
Oh my goodness, I just realized there is a trivial solution. Just use the FOR /F SKIP option to ignore the first 7 entries after sorting by last modified date, descending.
for /f "skip=7 eol=: delims=" %%F in ('dir /b /o-d /a-d *.txt') do #del "%%F"
You don't even need a batch file. Just change %% to % if run from the command prompt.
The Batch file below use a simpler approach. It use findstr /N "^" command to number each file, then it just compare each number to keep first seven files and delete the rest...
#echo off
for /f "tokens=1* delims=:" %%a in ('dir /b /o-d *.txt ^| findstr /N "^"') do (
if %%a gtr 7 del "%%b"
)
Antonio
If you don't write DOS scripts frequently which I don't, here is a summation of what others noted.
Other examples here will need the batch file in the same folder that you're deleting from.
To delete from another path: (Notice you have to add the path twice to the search and to the delete)
SET targetDir="C:\Test\Files\"
for /f "skip=7 eol=: delims=" %%F in ('dir /b /o-d /a-d %targetDir%*.txt') do #del "%targetDir%""%%F"
Thanks #dbenham, #SmileyFace, #user2924127 and all others who helped bring the answers.
This will keep 7 latest .txt files and remove all other .txt files
Execute below command in same directory from which you want to delete files
On command prompt
for /f "skip=7 eol=: delims=" %F in ('dir /b /o-d /a-d *.txt') do #del "%F"
Inside batch script
for /f "skip=7 eol=: delims=" %%F in ('dir /b /o-d /a-d *.txt') do #del "%%F"

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