I'm attempting to learn the remove() function in C, and I want to make a program with first gets the environmental variable with getenv() function, then uses it inside the code.
However, I get the error
"too many arguments to function remove()".
#include <stdio.h>
#include <stdlib.h>
int main()
{
char* a = getenv("USERPROFILE");
remove("%s/Desktop/remove.txt", a);
return 0;
}
If you are simply trying to combine them this should work.
I commented out some lines and put a printf so you can run it to see the result.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAXPATH 256
int main()
{
//char* a = getenv("USERPROFILE");
char* a = "userprofile";
char path[MAXPATH];
strcpy(path,a);
strcat(path,"/Desktop/remove.txt");
//remove(path);
printf("PATH: %s",path);
return 0;
}
I am making a game and I have to add some sounds effects and Music.
I Googled it and I found The flowing Code:
#include <conio.h>
#include "inc/fmod.h"
FSOUND_SAMPLE* handle;
int main ()
{
// init FMOD sound system
FSOUND_Init (44100, 32, 0);
// load and play mp3
handle=FSOUND_Sample_Load (0,"my.mp3",0, 0, 0);
FSOUND_PlaySound (0,handle);
// wait until the users hits a key to end the app
while (!_kbhit())
{
}
// clean up
FSOUND_Sample_Free (handle);
FSOUND_Close();
}
But when I compile it I got the flowing error:
➜ Desktop gcc main.c
main.c:1:10: fatal error: 'conio.h' file not found
#include <conio.h>
^~~~~~~~~
1 error generated.
Well, firstly <conio.h> is a C++ library and you're programming in C. It's different!
Then, I remember a C code I wrote years ago, main.c has got the following code (comments are in italian because I am italian):
#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
#include "header.h"
int main(){
register unsigned char x='2';
printf("digitare tasti:\n");
while(1){
while(1){
if(x=='2'){/*blocco2*/ while(x!='1' && x!='3'){x=getch(); scala2(x);}}
if(x=='1'){/*blocco1*/ while(x!='2' && x!='3'){x=getch(); scala1(x);}}
if(x=='3'){/*blocco3*/ while(x!='1' && x!='2'){x=getch(); scala3(x);}}
}
}
system("PAUSE");
return 0;
}
Then, this is the other source file, called file.c:
#include <stdio.h>
#include <stdlib.h>
#include <windows.h>
#include "header.h"
void scala1(unsigned char x){
if(x=='a')beep(131,50);
if(x=='s')beep(147,50);
if(x=='d')beep(165,50);
if(x=='f')beep(175,50);
if(x=='g')beep(196,50);
if(x=='h')beep(220,50);
if(x=='j')beep(247,50);
if(x=='k')beep(262,50);
if(x=='l')beep(294,50);
if(x=='w')beep(139,50);
if(x=='e')beep(156,50);
if(x=='r')beep(185,50);
if(x=='t')beep(208,50);
if(x=='y')beep(233,50);
}
void scala2(unsigned char x){
if(x=='a')beep(262,50);
if(x=='s')beep(294,50);
if(x=='d')beep(330,50);
if(x=='f')beep(349,50);
if(x=='g')beep(392,50);
if(x=='h')beep(440,50);
if(x=='j')beep(494,50);
if(x=='k')beep(523,50);
if(x=='l')beep(587,50);
if(x=='w')beep(277,50);
if(x=='e')beep(311,50);
if(x=='r')beep(370,50);
if(x=='t')beep(415,50);
if(x=='y')beep(466,50);
}
void scala3(unsigned char x){
if(x=='a')beep(523,50);
if(x=='s')beep(587,50);
if(x=='d')beep(659,50);
if(x=='f')beep(698,50);
if(x=='g')beep(784,50);
if(x=='h')beep(880,50);
if(x=='j')beep(988,50);
if(x=='k')beep(1046,50);
if(x=='l')beep(1175,50);
if(x=='w')beep(554,50);
if(x=='e')beep(622,50);
if(x=='r')beep(740,50);
if(x=='t')beep(831,50);
if(x=='y')beep(932,50);
}
The last one, the file header.h. It's code is the following one:
void scala1(unsigned char x);
void scala2(unsigned char x);
void scala3(unsigned char x);
All the source files must be in the same directory. You compile main.c and then, you just need to press a,s,d,..y and 1,2,3. Try! It works, of course if you want to change part of the code, you can do. I hope you enjoy my program, it's funny :)
I have a simple code and argv[1] is "Привет".
#include <stdio.h>
#include <tchar.h>
#include <Windows.h>
#include <locale.h>
int _tmain(int argc, TCHAR* argv[])
{
TCHAR buf[100];
_fgetts(buf, 100, stdin);
_tprintf(TEXT("\nargv[1] %s\n"), argv[1]);
_tprintf(TEXT("%s\n"), buf);
}
In the console, I write "Мир" and have this result:
If I use setlocale(LC_ALL, ""), I have this result:
What should I do to get the correct string in both cases?
Evidently your program works, except it cannot print correctly on the console window. This is because Windows console is not fully compatible with Unicode. Use _setmode for Visual Studio. This should work for Russian but there could be additional problems with some Asian languages. Use WriteConsole for other compilers.
Visual Studio Example:
#include <stdio.h>
#include <io.h> //for _setmode
#include <fcntl.h> //for _O_U16TEXT
int wmain(int argc, wchar_t* argv[])
{
_setmode(_fileno(stdout), _O_U16TEXT);
wprintf(L"%s", L"Привет\n");
return 0;
}
I'm trying to get a wide character string from /dev/urandom but there is nothing or some short strange results on STDOUT. I need to solve this problem today. Please help me! What's wrong with it...
#include <stdio.h>
#include <wchar.h>
#include <locale.h>
int main(){
setlocale(LC_ALL, "");
wchar_t text[100];
FILE *urandom;
int x = 5;
urandom = fopen("/dev/urandom", "r");
while(x--){
fgetws(text, 100, urandom);
fwprintf(stdout, L"%ls\n", text);
//fputws(text, stdout);
}
fclose(urandom);
return 0;
}
EDIT:
THIS IS WHAT I SHOULD GET (using normal char[], fgets, fputs):
THIS IS WHAT I'M GETTING (using wchar_t[], fgetws, fwprintf/fputws):
Hello i wrote my c program which will be run on linux.
I am trying to make my own shell for linux.
I have the following code below...
#include <limits.h>
#include <libgen.h>
#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <signal.h>
#include <string.h>
#include <sys/wait.h>
#include <sys/types.h>
#include <ctype.h>
#include <errno.h>
#include <sys/stat.h>
#include <fcntl.h>
#define MAX_LINE 80 /* 80 chars per line, per command, should be enough. */
int main(void){
int i = 0;
int k = 0;
int argsCount = 0;
char inputBuffer[MAX_LINE]; /*buffer to hold command entered */
int background; /* equals 1 if a command is followed by '&' */
char *args[MAX_LINE/2 + 1]; /*command line arguments */
pid_t tpid ;
pid_t child_pid;
int child_status;
char path[PATH_MAX+1];
char *progpath = strdup(args[0]);
char *prog = basename(progpath);
char temp[MAX_LINE];
}
It'is compiling well but when i try to run the code it gives me segmentation fault error
How can i fix it and why i take this error?
Your main has a wrong signature. You want
int main(int argsCount, char**args) {
and of course you should remove the internal declaration of argCount & args inside your main.
Perhaps you want instead your args & argCount to contain the parsed arguments of your own shell (but you still have to give a good signature to your main, conventionally and very often int main(int argc, char**argv).... you probably want your shell to accept the -c argument as most shells do, this would ease debugging with simplistic test cases). Then you should initialize them, and you should read some line (probably with getline) in a loop.
As I commented, you should compile with all warnings & debug info:
gcc -Wall -Wextra -g yoursource.c -o yourprog
Then use gdb ./yourprog to debug your program (see GDB documentation). valgrind should also be helpful. Of course, be sure to develop on a Linux system!
BTW, your program is not a convincing start for a shell. Use strace on some existing shell to understand what a shell needs to do. Study the source code of some existing free software shell (e.g. sash, fish, GNU bash ...). Read Advanced Linux Programming