I'm new to react and redux world. I have a question regarding react router. Following is my App component.
class App extends React.PureComponent {
render() {
return (
<div>
<Switch>
<Route exact path="/" component={HomePage} />
<Route exact path="/callback" component={CallbackPage} />
<Route exact path="/list" component={List} />
<Route component={NotFoundPage} />
</Switch>
</div>
);
}
}
export default App;
My list class looks like this:
export class List extends React.PureComponent {
constructor(props) {
super(props);
this.state = {
isOpen: false,
};
this.depositHandleToggle = this.depositHandleToggle.bind(this);
}
depositHandleToggle = () => {
this.props.dispatch(push(`${this.props.match.url}/deposit`));
}
render() {
const { match } = this.props;
return (
<div>
<Route path={`${match.url}/deposit`} component={Modal} />
<button onClick={this.depositHandleToggle}>Open Modal</button>
</div>
);
}
}
export default List;
So my question is: when i click the button in List container, why my router can't find this url 'localhost:xxx/list/deposit'? it renders the App component but it never goes back to List component. Is it possible to have the custom routes inside my list container? Am i doing something wrong? Please someone help me with this.
I hope you understand my question. Thanks in advance.
ANSWER:
I found the answer, the issue was in my App component list route. I was having the 'exact' keyword, that's why route inside my list component was not working. Following way is the correct way.
<Route path="/list" component={List} />
I hope this will help someone.
import { Link } from 'react-router-dom';
class App extends React.PureComponent {
render() {
return (
<div>
<Switch>
<Route exact path="/" component={HomePage} />
<Route exact path="/callback" component={CallbackPage} />
<Route exact path="/list" component={List} />
<Route exact path="/list/deposit" component={Modal} />
<Route component={NotFoundPage} />
</Switch>
</div>
);
}
}
export default App;
export class List extends React.PureComponent {
constructor(props) {
super(props);
}
render() {
const { match } = this.props;
return (
<div>
<Link to={'/deposit'}>Open Modal</Link>
);
}
}
export default List;
in that component you should handle modal open close.
Related
I would like to hide a component when another component is routing
for more specific, i have a fixed bottom nav that i want to hide when a component is been route by user, in this case its a comment box
My first option was trying on the parent component with browserhistory and history.listen, and componning a string with math.params for get a match between, and this change the state of parent, witch will hide the bottomnav, and the code wrote was trying through a cyclelife passing props, but nothing, anyone can help me please?
class App extends React.Component {
constructor(props){
super(props);
this.state = {
showBottomNav: true
}
this.hideBottomNav = this.hideBottomNav.bind(this)
}
hideBottomNav= () => {
this.setState({
showBottomNav: false
})
}
render() {
return (
<Router>
<NavBar />
<Switch>
<Route path='/' exact component={Home} />
<Route path='/wars' exact component={Tournament} />
<Route path='/shop' exact component={Shop} />
<Route path='/library' exact component={Library} />
<Route
path='/:id'
exact
render={ props => <ExpandedPost {...props} parentMethod={() => this.hideBottomNav()} />}
/>
</Switch>
<BottomNav />
</Router>
);
}
}
export default App;
And the children Component
export default function PostReview(props) {
const classes = useStyles();
useEffect(() => {
props.parentMethod()
},[props])
return (
<div>....
I am defining the routes in react
Global ones in the app-routes.js file and other in their respective components.
app.js
render() {
return (
<div className="App-wrap">
<AppRoutes/>
</div>
); }
app-route.js
export class AppRoutes extends React.Component {
render() {
return (
<Router>
<Switch>
<Route path="/" component={LayoutComponent} />
</Switch>
</Router>
);
}
}
layout-component.js
I have placed my header here for navigation
export class LayoutComponent extends React.Component {
render() {
return (
<LayoutWrap>
<HeaderComponent> </HeaderComponent>
<LayoutRoutes />
</LayoutWrap>
);
}
}
layout.routing.js
export class LayoutRoutes extends React.Component {
render() {
return (
<Switch>
<Route path="/" exact >
<Redirect to="/users"/>
</Route>
<Route path="/users" name="Users" component={UserComponent} />
<Route path="/permissions" name="Permissions" component={PermissionComponent} />
</Switch>
);
}
}
Now the issue is, when i am defining my child routes, my child routes are dependent on parent
i.e. i have to write parent's previous url in child.
If i change my app-routes.js path from "" to layout my routing will not work.
<Route path="/layout" component={LayoutComponent} />
How to solve the issue?
When you are defining your child Routes, you need to prefix the parent route path before it for these to work. For this you can make use of match.path from props like
export class LayoutRoutes extends React.Component {
render() {
const { match } = this.props;
return (
<Switch>
<Route path={match.path} exact render ={(props) => <Redirect to="/users"/>} />
<Route path=`${match.path}/users` name="Users" component={UserComponent} />
<Route path=`${match.path}/permissions` name="Permissions" component={PermissionComponent} />
</Switch>
);
}
}
Right now I am redirecting to a new page using but I dont know how to pass the data to the new page. This is what I am doing:-
class ShopsCatOptions extends React.Component{
constructor(props){
super(props);
this.state={
shopd: this.props.shop,
redirect:false
};
}
render() {
if (this.state.redirect) {
return <Redirect push to="./shopdetail" data={this.state.redirect}/>;
}
return(
<div class="expndinnerm" onClick={this.handleOnClick}>
{
this.state.shopd
}
</div>
)
}
}
export default ShopsCatOptions
What is the right way to do it?
What i have done to acheive this is by using history prop,
this.props.history.push({
pathname:"/shopdetail",
state:{
key:"value"
}
});
And in the ShopDetail component you can access the object like,
this.props.location.state.key
Edit: To get history in your props, your main component should have ,
import { BrowserRouter, Route } from 'react-router-dom';
...
<BrowserRouter>
<Switch>
<Route path="/home" component={Home} />
<Route path="/user" component={User} />
<Route path="*" component={page404} />
</Switch>
</BrowserRouter>
I am trying to gain access to params in ownProps. Is there a way to solve this?
Current structure is
const Router = () => (
<router>
<Switch>
<Route path='/signup' component={Signup} />
<Route path='/browse' component={Browse}/>
<Route path='/detail/:id' component={Detail} />
</Switch>
</router>
)
i want ownProps to pass on to these pages in Detail
export default class App extends Component {
render() {
return (
<div>
<Info />
<Message/>
</div>
);
}
}
After messing around I found a way which is that I passed the required information as props to nested components.
export default class App extends Component {
render() {
return (
<div>
<Info idInfo={this.props}/>
<Message idInfo={this.props}/>
</div>
);
}
}
after this I got information in ownProps.
I'm pulling my hair out trying to render multiple layouts with React Router v4.
For instance, I'd like pages with the following paths to have layout 1:
exact path="/"
path="/blog"
path="/about"
path="/projects"
and the following paths to have layout 2:
path="/blog/:id
path="/project/:id
Effectively what's being answered here but for v4: Using multiple layouts for react-router components
None of the other answers worked so I came up with the following solution. I used the render prop instead of the traditional component prop at the highest level.
It uses the layoutPicker function to determine the layout based on the path. If that path isn't assigned to a layout then it returns a "bad route" message.
import SimpleLayout from './layouts/simple-layout';
import FullLayout from './layouts/full-layout';
var layoutAssignments = {
'/': FullLayout,
'/pricing': FullLayout,
'/signup': SimpleLayout,
'/login': SimpleLayout
}
var layoutPicker = function(props){
var Layout = layoutAssignments[props.location.pathname];
return Layout ? <Layout/> : <pre>bad route</pre>;
};
class Main extends React.Component {
render(){
return (
<Router>
<Route path="*" render={layoutPicker}/>
</Router>
);
}
}
simple-layout.js and full-layout.js follow this format:
class SimpleLayout extends React.Component {
render(){
return (
<div>
<Route path="/signup" component={SignupPage}/>
<Route path="/login" component={LoginPage}/>
</div>
);
}
}
So, for this you should use render function (https://reacttraining.com/react-router/core/api/Route/render-func)
A really good article that helped me: https://simonsmith.io/reusing-layouts-in-react-router-4/
In the end you will be use something like this:
<Router>
<div>
<DefaultLayout path="/" component={SomeComponent} />
<PostLayout path="/posts/:post" component={PostComponent} />
</div>
</Router>
I solved this problem utilizing a bit of both of your solutions:
My Routes.js file
import BaseWithNav from './layouts/base_with_nav';
import BaseNoNav from './layouts/base_no_nav';
function renderWithLayout(Component, Layout) {
return <Layout><Component /></Layout>
}
export default () => (
<Switch>
{/* Routes with Sidebar Navigation */}
<Route exact path="/" render={() => renderWithLayout(Home, BaseWithNav)} />
{/* Routes without Sidebar Navigation */}
<Route path="/error" render={() => renderWithLayout(AppErrorMsg, BaseNoNav)} />
<Route path="/*" render={() => renderWithLayout(PageNotFound, BaseNoNav)} />
</Switch>
)
Base.js (where routes get imported)
export default class Base extends React.Component {
render() {
return (
<Provider store={store}>
<Router>
<Routes />
</Router>
</Provider>
)
}
}
Layouts
BaseWithNav.js
class BaseWithNav extends Component {
constructor(props) {
super(props);
}
render() {
return <div id="base-no-nav">
<MainNavigation />
<main>
{this.props.children}
</main>
</div>
}
}
export default BaseWithNav;
BaseNoNav.js
class BaseNoNav extends Component {
constructor(props) {
super(props);
}
render() {
let {classes} = this.props;
return <div id="base-no-nav">
<main>
{this.props.children}
</main>
</div>
}
}
export default BaseNoNav;
I hope this helps!
I know i am replying late but it's easy to do that, i hope it will helps to newbie.
i am using React 4
Layout.js
export default props => (
<div>
<NavMenu />
<Container>
{props.children}
</Container>
</div>
);
LoginLayout.js
export default props => (
<div>
<Container>
{props.children}
</Container>
</div>
);
Now finally we have our App
App.js
function renderWithLoginLayout(Component, Layout) {
return <LoginLayout><Component /></LoginLayout>
}
function renderWithLayout(Path, Component, Layout) {
return <Layout><Route path={Path} component={Component} /></Layout>
}
export default () => (
<Switch>
<Route exact path='/' render={() => renderWithLayout(this.path, Home, Layout)} />
<Route path='/counter' render={() => renderWithLayout(this.path, Counter, Layout)} />
<Route path='/fetch-data/:startDateIndex?' render={() => renderWithLayout(this.path, FetchData, Layout)} />
<Route path='/login' render={() => renderWithLoginLayout(Login, LoginLayout)} />
</Switch>
);