Compare similar values from hashtable with loop in Powershell - arrays

Question

I have 2 hash tables :
[hashtable]$Localisation = #{
"Macdo" = "OU=France,OU=Paris";
"BurgerKing" = "OU=USA,OU=LA";
"Quick" = "OU=Japan,OU=Tokyo";
}
[hashtable]$Profil = #{
"Big Mac" = "Macdo";
"Whooper" = "BurgerKing";
"Burger" = "Quick, BurgerKing, Macdo";
"Fries" = "BurgerKing, Macdo";
"Coke" = "Quick, Macdo";
"HappyMeal" = "Macdo";
}
I need to get this kind of result:
"Big Mac" = "OU=France,OU=Paris"
"Whooper" = "OU=USA,OU=LA";
"Burger" = "OU=Japan,OU=Tokyo, OU=USA,OU=LA, OU=France,OU=Paris"
"Fries" = "OU=USA,OU=LA, OU=France,OU=Paris";
"Coke" = "OU=Japan,OU=Tokyo, OU=France,OU=Paris";
"HappyMeal" = "OU=France,OU=Paris";
or
Big Mac = OU=France,OU=Paris
Whooper = OU=USA,OU=LA
Burger = OU=Japan,OU=Tokyo,
OU=USA,OU=LA,
OU=France,OU=Paris
Fries = OU=USA,OU=LA,
OU=France,OU=Paris
Coke = OU=Japan,OU=Tokyo,
OU=France,OU=Paris
HappyMeal = OU=France,OU=Paris
I tried :
$tempLoca = #()
foreach ($value in $Profil.values) {
if($Localisation.Contains($value)) {
$tempLoca = $Localisation.Contains($value),$Profil.key
}
}
But I get :
$tempLoca
OU=France,OU=Paris
With my code I have only the last value. I don't know if I need to put my values in array or in hashtable (because they are multiple similar values).
Do you have an idea? Thanks

Answer 1

Try this:
[hashtable]$Localisation = #{
"Macdo" = "OU=France,OU=Paris";
"BurgerKing" = "OU=USA,OU=LA";
"Quick" = "OU=Japan,OU=Tokyo";
}
[hashtable]$Profil = #{
"Big Mac" = "Macdo";
"Whooper" = "BurgerKing";
"Burger" = "Quick, BurgerKing, Macdo";
"Fries" = "BurgerKing, Macdo";
"Coke" = "Quick, Macdo";
"HappyMeal" = "Macdo";
}
$tempLoca = #()
foreach ($key in $Profil.Keys) {
$locals = ($Profil.$key -split ',') | ForEach-Object { $_.Trim() }
$result = #()
foreach ($item in $locals) {
if($Localisation.ContainsKey($item)) {
$result += $Localisation.$item
}
}
$tempLoca += '"{0}" = "{1}"' -f $key, ($result -join '; ')
}
$temploca
It will output
"Big Mac" = "OU=France,OU=Paris"
"HappyMeal" = "OU=France,OU=Paris"
"Burger" = "OU=Japan,OU=Tokyo; OU=USA,OU=LA; OU=France,OU=Paris"
"Whooper" = "OU=USA,OU=LA"
"Fries" = "OU=USA,OU=LA; OU=France,OU=Paris"
"Coke" = "OU=Japan,OU=Tokyo; OU=France,OU=Paris"
Note that I combine the OU values from the $Localisation hash with a semicolon ; to distinct them from the values themselves. If that is not what you want, just replace ($result -join '; ') with ($result -join ', ')

Answer 2

An IMO more PowerShell like way, building a PSCustomObject and grouping it:
$ProfileLocalisation = ForEach ($key in $Profil.Keys) {
ForEach ($local in ($Profil.$key -split ',').Trim() ) {
[PSCustomObject]#{
Profile = $key
Localisation = $Localisation.$local
}
}
}
$ProfileLocalisation
Sample output:
Profile Localisation
------- ------------
Big Mac OU=France,OU=Paris
HappyMeal OU=France,OU=Paris
Burger OU=Japan,OU=Tokyo
Burger OU=USA,OU=LA
Burger OU=France,OU=Paris
Whooper OU=USA,OU=LA
Fries OU=USA,OU=LA
Fries OU=France,OU=Paris
Coke OU=Japan,OU=Tokyo
Coke OU=France,OU=Paris
And grouped:
$ProfileLocalisation | Group-Object Profile | ForEach-Object {
[PSCustomObject]#{
Profile = $_.Name
Localisations = ($_.Group.Localisation -join ';')
}
}
Profile Localisations
------- -------------
Big Mac OU=France,OU=Paris
HappyMeal OU=France,OU=Paris
Burger OU=Japan,OU=Tokyo;OU=USA,OU=LA;OU=France,OU=Paris
Whooper OU=USA,OU=LA
Fries OU=USA,OU=LA;OU=France,OU=Paris
Coke OU=Japan,OU=Tokyo;OU=France,OU=Paris