I have written a code in drupal that after hitting node edit a delete query will run and unselect the radio button to display an alert each time. The query is working fine but the radio button got unchecked after second time reload. I want to uncheck that just after user click "Edit"
function debtcc_manage_node_prepare($node)
{
$nid = $node->nid;
if ($nid != null) {
//field_cache_clear();
$query = db_delete('field_data_field_change_updation_date')
->condition('entity_id',$nid)->execute();
field_cache_clear();
}
}
How can I achieve that? Is there any function in drupal to refresh the page automatically or other way?
Do a form alter and set default state for your field as uncheked:
function YOUR_MODULE_form_alter(&$form, &$form_state, $form_id) {
if ($form_id == 'YOUR_FORM_ID' && $form['nid']['#value'] != NULL) {
$form['YOURFIELD'][LANGUAGE_NONE]['#default_value'] = 0;
}
}
Upon clicking on edit checkbox will be unchecked and you already taken care of the database.
Related
My purpose is to translate interactively a checkbox action into a couple of values "0001" or "".
I placed this method on a table whose name is Notification.
// BP Deviation Documented
edit NoYesId provenWarranty (boolean _set = false, NoYesId _provenWarranty = NoYes::No)
{
NoYesId provenWarr;
;
// set value
if (_set)
{
if (_provenWarranty)
this.Func_Status = '0001';
else
this.Func_Status = '';
return _provenWarranty;
}
// read value
if (this.Func_Status == '0001')
return NoYes::Yes;
else
return NoYes::No;
}
This method is used by a Checkbox in a Form with this Table as a Datasource.
This method has been cached in the Notification datasource init() method.
Notification_ds.cacheAddMethod(tablemethodstr(Notification, provenWarranty));
My problem is that the Checkbox is constantly flickering, is there a way to avoid that ?
Update
The flickering appears inside the Checkbox design, but without
toggling it between checked or not.
This problem appears even if the Checkbox is connected to a basic
datasource field, not only if connected to an edit method.
It seems that the more fields there are in the datasource, the more
flickering I get.
I have created a custom type with multiple fields.
1 field is a checkbox to "show for all people"
2nd field is a textfield ( you can add multiple textfields ) for adding a code.
I created a view where all those content types are being shown in a page. ( this works )
But now:
When a person enters the site, he has to insert a code. This code is saved into a cookie because it needs to be remembered for about 2 weeks.
So I can't use the contextual filters.
If the checkbox "show for all people" is checked, this block is shown.
if the checkbox "show for all people" is unchecked, this block is hidden, except for people who came in without a code, or if the code is one of the values that was inserted in the 2nd field.
I don't wan't to use views php_filter. But I have no clue how to proceed with this problem.
I tried some solutions on the web to create a custom filter, but the problem here is, that we can't access the form values.
I found a solution, but I'm not sure if this is the correct drupal way.
I used the hook_node_view function to get all nodes that are printed on that page. I check if the code that was inserted into a cookie with the codes that are allowed ( created in the text fields of the content type )
function code_node_view($node, $view_mode, $langcode) {
if ($node->type == 'winning_codes') {
$code = _code_read_cookie('code');
$winning_codes = (!empty($node->field_winning_codes['und'])) ? $node->field_winning_codes['und'] : array();
$winning_codes = array_map(function ($ar) {
return $ar['value'];
}, $winning_codes);
if (!empty($code) && (!in_array($code, $winning_codes))) {
hide($node->content);
}
}
}
i am working in extjs4. i have grid with checkbox selection model. Grid is displaying files and folders. If folder get selected then i want to hide some menu. So have written code as-
selectionchange:function( model, selected, eOpts ){
var centralPanel = me.up();
var actionBtn = centralPanel.queryById('libraryactionBtn');
if(selected.length > 1) {
actionBtn.show();
//var i=0;
for(i=0;i<selected.length;i++)
{
if(selected[i].data.isLeaf)
{
centralPanel.queryById('library-action-menu-view').hide();
centralPanel.queryById('library-action-menu-viewOrAddTag').hide();
centralPanel.queryById('library-action-menu-viewOrAddNotes').hide();
centralPanel.queryById('library-action-menu-copyToCompaign').hide();
centralPanel.queryById('library-action-menu-copyToProject').hide();
centralPanel.queryById('library-action-menu-sendLink').hide();
centralPanel.queryById('library-action-menu-addtofavorite').hide();
centralPanel.queryById('library-action-menu-downloadItem').hide();
}
}
} else {
actionBtn.hide();
}
where selected.data.isLeaf is false for folder. Its executing correctly only first time. Next time when i am selecting file,then also its hiding menu for file. And if folder is deselected then also its hiding menu. So what modifications i need to do
first of all I don't see any code that shows the menu..You are just hiding the menu.
Secondly make sure selected[i].data.isLeaf is false and not "false".
i would like to have a form where i have an additional checkbox (will not store input to db) which will be readout in the controller.
For Example.
In a Job Edit view i can select a user. Under this user is a checkbox. This checkbox will send after i have assigned the Job to the User an email.
In my Controller i write
$post_array = $this->request->data;
if ($post_array['Job']['mailcheck'] == NULL) {
// DO SOMETHING
} else {
// DO SOMETHING
}
But it doesn´t read out the checkbox value...
Any ideas how to solve this problem?
Thx for help
While mark's answer is correct, allow me to elaborate.
Keep in mind that checkboxes sometimes behave curiously. An unchecked checkbox may not get posted at all, and that may be why your condition fails.
Regarding why you couldn't make it work:
It seems you are performing a redirect in either case, which is why you never see the edit form. Check to see if you missed something or just try this:
if ($this->request->is('post')) {
if (!empty($this->request->data['Job']['mailcheck'])) {
$this->redirect(array('action' => 'sendMails',$id));
} else {
$this->redirect(array('action' => 'sorted'));
}
}
This suffices:
if (!empty($this->request->data['Job']['mailcheck'])) {
// yes, checkbox was selected
} else {
// no, it was not selected
}
I ve tried to implemented filtering data (list base on selected category) using dropdown with observefield and ajax pagination. I use session to remember selected category in order to keep pagination.
Here is my code (Cakephp 1.2)
In view :
echo $form->select('Category.id', $categories, null, array('id' => 'categories'),'Filter by Categories')
echo $ajax->observeField('categories' ,array('url' =>'update_category','update' => 'collectionDiv'));
In Controller:
if(!empty($this->data['Category']['id']))
{
$cat_id=$this->data['Category']['id'];
$filters=array('Collection.category_id' => $cat_id);
$this->set('collections', $this->paginate('Collection', $filters));
$this->Session->write($this->name.'.$cat_id', $category_id);
}
else
{
$cat_id=$this->Session->read($this->name.'.cat_id');
$filters=array('Collection.category_id' => $cat_id);
$this->set('collections', $this->paginate('Collection'));
}
The filter work as I wanted but the problem is when I select empty value('Filter by Category) it still remember last category session so I can't back to the default list (All record list without filter).
I've tried to make some condition but still not success. Is there another way? Please I appreciate your help. thank
hermawan
Perhaps I don't understand the question, but it looks to me like it might be worth changing:
else
{
$cat_id=$this->Session->read($this->name.'.cat_id');
$filters=array('Collection.category_id' => $cat_id);
$this->set('collections', $this->paginate('Collection'));
}
to:
else
{
$this->set('collections', $this->paginate('Collection',array()));
}
In effect your code appears to be doing this anyway. Check what the URL is at the top of the browser window after it has returned. Does it still contain pagination directives from the previous query?
You might want to review http://book.cakephp.org/view/167/AJAX-Pagination and make sure you've 'ticked all the boxes'.
I got it, It work as I hope now. I my self explain the condition and solution.
When I select category from combobox, then it render the page the code is :
If ($this->data['Category']['id']) {
$cat_id=$this->data['Category']['id'];
$this->Session->write($this->name.'.category_id', $category_id);
// I will use this session next when I click page number
$filters=array('Collection.art_type_id' => $category_id);
$this->set('collections', $this->paginate('Collection', $filters));
}else{
//if clik page number, next or whatever, $this->data['Category']['id'] will empty so
// use session to remember the category so the page will display next page or prev
// page with the proper category, But the problem is, when I set category fillter to
// "All Category" it will dislpay last category taked from the session. To prevent it
// I used $this->passedArgs['page']. When I clik the page paginator it will return
// current number page, but it will be empty if we click dropdown.
if (!empty($this->passedArgs['page']) {
$cat_id=$this->Session->read($this->name.'.category_id');
$filters=array('Collection.category_id' => $cat_id);
$this->set('collections', $this->paginate('Collection',$filters));
}else{
$this->set('collections', $this->paginate('Collection'));
}
}
From this case, I think that observefield will not send passedArg as we get from url such from ajax link or html->link. I hope this will usefull to anybody