I have a piece of code where I need to find the latest modified date file of the below mentioned 3 patterns.
array=( $(find /path -maxdepth 1 -type f \( -name "REF_DATA*" -o -name "XR_CUST_LIST*" -o -name "PB_INSIGHTS*" \) -printf '%f\n' ))
Basically there can files of many dates at /path directory, but i need to pick the latest one.
How can i achieve that?
One option is this command line (to keep your first approach) :
array=( $(find /path -maxdepth 1 -type f \( -name "REF_DATA*" -o -name "XR_CUST_LIST*" -o -name "PB_INSIGHTS*" \) -printf '%c %f\n' ))|sort |tail -n 1
Focus on the part added/updated :
-printf '%c %f\n' ))|sort |tail -n 1
add %c in printf option add the update time of the file
add sort to sort this list by this date
add tail -n1 to have the last element of this list which is the last updated file here
Tried using:
find /home/ -user student -exec rm -fr {}
or
find /home/ -group student -exec rm -fr {} \
but had error message: find: missing argument to '-exec'.
Welcome to stackoverflow!
The easiest way (even mentioned in manual page for [find(1)][1]) is:
find /tmp -name core -type f -print | xargs /bin/rm -f
adapted to your case:
find /home/ -user student -print | xargs /bin/rm -rf
But certainly there are several variants how to accomplish this task. You can simply start from different example with -exec:
find . -type f -exec file '{}' \;
adapted to your use case:
find /home/ -group student -exec rm -rf '{}' \;
We
would need monitoring on below folder for respective directories & sub directories to see if the files in the directory are greater than 100 files. Also none of the file should sit more than 4 hrs.
If files in the directory is more than 100 we would need an alert. Not sure why this script is working. Could you please confirm?
Path – /export/ftpaccounts/image-processor/working/
The Script:
#!/bin/bash
LOCKFILE=/tmp/findimages.lock
if [ -f ${LOCKFILE} ]; then
exit 0
fi
touch ${LOCKFILE}
NUM=`find /mftstaging/vim/inbound/active \
-ignore_readdir_race -depth -type f -m min +60 -print |
xargs wc -l`
if [[ ${NUM:0:1} -ne 0 ]]; then
echo "${NUM:0:1} files older than 60minutes" |
mail -s "batch import is slow" ${MAILTO}
fi
rm -rf ${LOCKFILE}
The format of your original post made it difficult to tell what you were trying to accomplish. If I understand you just want to find the number of files in the remote directory that are greater than 60 minutes old, then with a couple of changes your script should work fine. Try:
#!/bin/bash
LOCKFILE=/tmp/findimages.lock
ACTIVE=/mftstaging/vim/inbound/active
[ -f ${LOCKFILE} ] && exit 0
touch ${LOCKFILE}
# NUM=`find /mftstaging/vim/inbound/active \
# -ignore_readdir_race -depth -type f -m min +60 -print |
# xargs wc -l`
NUM=$(find $ACTIVE -type f -mmin +60 | wc -l)
## if [ $NUM -gt 100 ]; then # if you are test for more than 100
if [ $NUM -gt 0 ]; then
echo "$NUM files older than 60minutes" |
mail -s "batch import is slow" ${MAILTO}
fi
rm -rf ${LOCKFILE}
Note: you will want to implement some logic that deals with a stale lock file, and perhaps use trap to insure the lock is removed regardless of how the script terminates. e.g.:
trap 'rm -rf ${LOCKFILE}' SIGTERM SIGINT EXIT
I have multiple(more than 100) .c files and I want to change a particular text from all the file in which that text exists. I am using ubuntu!
How can I do it?(I will prefer command line rather than installing any application)
Thanks a lot!
OLD=searchtext
NEW=replacedtext
YOURFILE=/path/to/your/file
TMPFILE=`mktemp`
sed "s/$OLD/$NEW/g" $YOURFILE > $TMPFILE && mv $TMPFILE $YOURFILE
rm -rf $TMPFILE
you can also use find to find your files:
find /path/to/parent/dir -name "*.c" -exec sed 's/$OLD/$NEW/g' {} > $TMPFILE && mv $TMPFILE {} \;
find /path/to/parent/dir -name "*.c" finds all files with name *.c under /path/to/parent/dir. -exec command {} \; executes the command in the found file. {} stands for the found file.
You should check out sed, which lets your replace some text with other text (among other things)
example
sed s/day/night/ oldfile newfile
will change all occurences of "day" with "night" in the oldfile, and store the new, changed version in the newfile
to run on many files, there are a few things you could do:
use foreach in your favorite shell
use find like this
find . -name "namepattern" -exec sed -i "sed-expr" "{}" \;
use file patterns like this: sed -i "sed-expr" *pattern?.cpp
where *pattern?.cpp is just a name pattern for all files that starts with some string, then has "pattern" in them, and has any letter and a ".cpp" suffix
How do I find out the files in the current directory which do not contain the word foo (using grep)?
If your grep has the -L (or --files-without-match) option:
$ grep -L "foo" *
You can do it with grep alone (without find).
grep -riL "foo" .
This is the explanation of the parameters used on grep
-L, --files-without-match
each file processed.
-R, -r, --recursive
Recursively search subdirectories listed.
-i, --ignore-case
Perform case insensitive matching.
If you use l (lowercased) you will get the opposite (files with matches)
-l, --files-with-matches
Only the names of files containing selected lines are written
Take a look at ack. It does the .svn exclusion for you automatically, gives you Perl regular expressions, and is a simple download of a single Perl program.
The equivalent of what you're looking for should be, in ack:
ack -L foo
The following command gives me all the files that do not contain the pattern foo:
find . -not -ipath '.*svn*' -exec grep -H -E -o -c "foo" {} \; | grep 0
The following command excludes the need for the find to filter out the svn folders by using a second grep.
grep -rL "foo" ./* | grep -v "\.svn"
If you are using git, this searches all of the tracked files:
git grep -L "foo"
and you can search in a subset of tracked files if you have ** subdirectory globbing turned on (shopt -s globstar in .bashrc, see this):
git grep -L "foo" -- **/*.cpp
You will actually need:
find . -not -ipath '.*svn*' -exec grep -H -E -o -c "foo" {} \; | grep :0\$
I had good luck with
grep -H -E -o -c "foo" */*/*.ext | grep ext:0
My attempts with grep -v just gave me all the lines without "foo".
Problem
I need to refactor a large project which uses .phtml files to write out HTML using inline PHP code. I want to use Mustache templates instead. I want to find any .phtml giles which do not contain the string new Mustache as these still need to be rewritten.
Solution
find . -iname '*.phtml' -exec grep -H -E -o -c 'new Mustache' {} \; | grep :0$ | sed 's/..$//'
Explanation
Before the pipes:
Find
find . Find files recursively, starting in this directory
-iname '*.phtml' Filename must contain .phtml (the i makes it case-insensitive)
-exec 'grep -H -E -o -c 'new Mustache' {}' Run the grep command on each of the matched paths
Grep
-H Always print filename headers with output lines.
-E Interpret pattern as an extended regular expression (i.e. force grep
to behave as egrep).
-o Prints only the matching part of the lines.
-c Only a count of selected lines is written to standard output.
This will give me a list of all file paths ending in .phtml, with a count of the number of times the string new Mustache occurs in each of them.
$> find . -iname '*.phtml$' -exec 'grep -H -E -o -c 'new Mustache' {}'\;
./app/MyApp/Customer/View/Account/quickcodemanagestore.phtml:0
./app/MyApp/Customer/View/Account/studio.phtml:0
./app/MyApp/Customer/View/Account/orders.phtml:1
./app/MyApp/Customer/View/Account/banking.phtml:1
./app/MyApp/Customer/View/Account/applycomplete.phtml:1
./app/MyApp/Customer/View/Account/catalogue.phtml:1
./app/MyApp/Customer/View/Account/classadd.phtml:0
./app/MyApp/Customer/View/Account/orders-trade.phtml:0
The first pipe grep :0$ filters this list to only include lines ending in :0:
$> find . -iname '*.phtml' -exec grep -H -E -o -c 'new Mustache' {} \; | grep :0$
./app/MyApp/Customer/View/Account/quickcodemanagestore.phtml:0
./app/MyApp/Customer/View/Account/studio.phtml:0
./app/MyApp/Customer/View/Account/classadd.phtml:0
./app/MyApp/Customer/View/Account/orders-trade.phtml:0
The second pipe sed 's/..$//' strips off the final two characters of each line, leaving just the file paths.
$> find . -iname '*.phtml' -exec grep -H -E -o -c 'new Mustache' {} \; | grep :0$ | sed 's/..$//'
./app/MyApp/Customer/View/Account/quickcodemanagestore.phtml
./app/MyApp/Customer/View/Account/studio.phtml
./app/MyApp/Customer/View/Account/classadd.phtml
./app/MyApp/Customer/View/Account/orders-trade.phtml
When you use find, you have two basic options: filter results out after find has completed searching or use some built in option that will prevent find from considering those files and dirs matching some given pattern.
If you use the former approach on a high number of files and dirs. You will be using a lot of CPU and RAM just to pass the result on to a second process which will in turn filter out results by using a lot of resources as well.
If you use the -not keyword which is a find argument, you will be preventing any path matching the string on the -name or -regex argument behind from being considered, which will be much more efficient.
find . -not -regex ".*/foo/.*" -regex ".*"
Then, any path that is not filtered out by -not will be captured by the subsequent -regex arguments.
For completeness the ripgrep version:
rg --files-without-match "pattern"
You can combine with file type and search path, e.g.
rg --files-without-match -t ruby "frozen_string_literal: true" app/
another alternative when grep doesn't have the -L option (IBM AIX for example), with nothing but grep and the shell :
for file in * ; do grep -q 'my_pattern' $file || echo $file ; done
My grep does not have any -L option. I do find workaround to achieve this.
The ideas are :
to dump all the file name containing the deserved string to a txt1.txt.
dump all the file name in the directory to a txt2.txt.
make the difference between the 2 dump file with diff command.
grep 'foo' *.log | cut -c1-14 | uniq > txt1.txt
grep * *.log | cut -c1-14 | uniq > txt2.txt
diff txt1.txt txt2.txt | grep ">"
find *20161109* -mtime -2|grep -vwE "(TRIGGER)"
You can specify the filter under "find" and the exclusion string under "grep -vwE". Use mtime under find if you need to filter on modified time too.
Open bug report
As commented by #tukan, there is an open bug report for Ag regarding the -L/--files-without-matches flag:
ggreer/the_silver_searcher: #238 - --files-without-matches does not work properly
As there is little progress to the bug report, the -L option mentioned below should not be relied on, not as long as the bug has not been resolved. Use different approaches presented in this thread instead. Citing a comment for the bug report [emphasis mine]:
Any updates on this? -L completely ignores matches on the first line of the file. Seems like if this isn't going to be fixed soon, the flag should be removed entirely, as it effectively does not work as advertised at all.
The Silver Searcher - Ag (intended function - see bug report)
As a powerful alternative to grep, you could use the The Silver Searcher - Ag:
A code searching tool similar to ack, with a focus on speed.
Looking at man ag, we find the -L or --files-without-matches option:
...
OPTIONS
...
-L --files-without-matches
Only print the names of files that don´t contain matches.
I.e., to recursively search for files that do not match foo, from current directory:
ag -L foo
To only search current directory for files that do not match foo, simply specify --depth=0 for the recursion:
ag -L foo --depth 0
This may help others. I have mix of files Go and with test files. But I only need .go files. So I used
ls *.go | grep -v "_test.go"
-v, --invert-match select non-matching lines see https://stackoverflow.com/a/3548465
Also one can use this with vscode to open all the files from terminal
code $(ls *.go | grep -v "_test.go")
grep -irnw "filepath" -ve "pattern"
or
grep -ve "pattern" < file
above command will give us the result as -v finds the inverse of the pattern being searched
The following command could help you to filter the lines which include the substring "foo".
cat file | grep -v "foo"