Disclaimer: I read this and this before, but it doesn't work as I want.
Description: I decided to create set of batch files for convenient way to run different projects in VSCode from desktop in one click(double-click). I want close cmd terminal after running a batch file, but terminal remains. I tried:
start code "C:\Users\MyUserName\path\to\my\project\directory"
and
cmd /c start code "C:\Users\MyUserName\path\to\my\project\directory"
It quickly runs command, runs code and opens my project, then, it seems to me, closes terminal and runs a new one in desktop directory.
I found solution with help of DavidPostill. This works fine for me:
start "" cmd /b /c code "C:\Users\MyUserName\path\to\my\project\directory" && exit 0
UPDATE:
There is a more simple way to run VSCode using command line interface:
cd path/to/my/project
code .
If anyone else comes across this in 2022, I found a solution that works great for me.
code "" "C:\path\to\folder\with\project" | exit
Also, below is my batch I made for a quick workspace that:
asks for a folder name, this will also be used as the project name
makes the vscode project
makes 2 text files, one for things I had to look up, and another for answers to my question
makes a png file called work.png that opens with paint for diagrams I might need for thinking through things
Lastly (the part I love the most) it CLOSES the command window once everything is opened!
Hope this helps someone like me who doesn't know everything about batch files!
#echo off &setlocal
set /p "folder=Enter the folder name to be created: "
md "%folder%" ||(pause &goto :eof)
cd %folder%
echo. > Things_I_had_to_look_up.txt
echo. > Answers.txt
dotnet new console
xcopy /s "C:\xPaintFileTemplate" "C:\Users\TBD\Documents\Program Work\%folder%"
start mspaint.exe Work.png
code "" "C:\Users\TBD\Documents\Program Work\%folder%" | exit
Rem not needed but to be safe
exit
The C:\xPaintFileTemplate is a folder in my C drive that contains only a png file named Work.png. The png file is blank, and sized to what I want mspaint to open with. If there are more files in that folder, it will copy all of them, so be careful with xcopy!
The Rem is a comment, saying the exit command doesn't seem to be required but I added it in anyways as I believe it is good practice.
Try using: start cmd /C code . :0 It should be able to close the cmd terminal. At least that worked for me on my Windows 10.
Another version:
start cmd /C code "C:\Users\MyUserName\path\to\my\project\directory" :0
Based on Blake Daugherty's answer, I found the first pair of double quotes seems unnecessary:
code "D:\proj\directory-1" | exit
code "D:\proj\directory-2" | exit
exit
None of the above worked for me; at worst one of the left-over CMD's needed its close button clicking three times before it would go away.
I tried the URL method and this worked just as I wanted: VSCode opened, and the cmd window went away; my batch file ("VSCode on project.bat") contains just one line:
start vscode://file/C:/path/to/project
or:
start "" "vscode://file/C:/path/to/project"
One line code:
code C:\Users\MyUserName\path\to\my\project\directory pause
Related
I'm writing a .bat file to launch two programs, not having success so far. I've followed the guide here.
#echo off
cd "D:\CRCR 0.4.0\"
start "" "D:\CRCR 0.4.0\Chernobyl Relay Chat Rebirth.exe"
cd "D:\MO2\"
start "" "D:\MO2\ModOrganizer.exe moshortcut://:Anomaly Launcher"
exit
Whenever I try to launch the batch file, it tells me "Windows cannot find 'D:\MO2\ModOrganizer.exe "moshortcut://:Anomaly Launcher'. Make sure you've typed the name correctly, then try again."
I've tried removing 'start' from those lines, removing quotations from the cd lines, etc. How can I get this working?
You probably want to pass moshortcut://:Anomaly Launcher as a parameter.
In that case you should also separate the string:
start "" "D:\MO2\ModOrganizer.exe" "moshortcut://:Anomaly Launcher"
Otherwise Windows will interpret the path as D:\MO2\ModOrganizer.exe moshortcut://:Anomaly Launcher not D:\MO2\ModOrganizer.exe and assume that the entire string is part of the path.
I'm having a weird problem when i try to open multiple files in geany with a batch script.
The script is simple going in the folders i gave him as a list, and in each folder it'll open the Makefile here with geany. That is working; however, it'll first open the first Makefile, and then wait until i close the window to open the second one, and so on.
It'll open the next Makefile in another tab, so at the end i still have all my makefiles opened, but i need to close the window between each one and i have a lot to open (that's why i made a script -_- )
Has anyone an idea on how to correct this weird behavior?
I made it in Linux with geany: it works well.
I made it in Windows with notepad: it works well.
But windows with geany doesn't work as i want it to do.
I've also tried using the command start, but it'll ask me with which prog i want to open the files and then do nothing at all.
Here is my script, a bit simplified:
rem set prog="C:\Program Files\Notepad++\notepad++.exe
set prog="C:\Program Files\Geany\bin\geany.exe
set FOLDERLIST="Some Folders Names Separate ByASpace"
for /d %%C in (%FOLDERLIST%) do (
cd %%~C
%prog% Makefile
cd ..
)
So i want it to open all the files at once, without having to close the window between each. As you can see i have a rem line with notepad as prog, and this one is working as expected; geany isn't. But again, i made it in Linux with geany and it does open all files at once.
I found a working answer within this question : SuperUser: Execute command line in background
So, i've found out that, when geany is open and i launch my batch script, it works perfectly. Then i tried to open geany in the batch script before opening all files, but it didn't work. Then, with some advice, i tried to open it like a deamon. And that's how the previously cited answer helped.
Here is the result:
rem set prog="C:\Program Files\Notepad++\notepad++.exe
set prog="C:\Program Files\Geany\bin\geany.exe
set FOLDERLIST="Some Folders Names Separate ByASpace"
for /d %%C in (%FOLDERLIST%) do (
cd %%~C
start "" %prog% Makefile
cd ..
)
It seems that start "" launch the file in the background and so let the script going on and open the others files.
PS: Note that start /B without the "", also given as an answer, does not work for me since it's asking me with which prog i want to open the files.
I want to create a batch file to launch my executable file after it has made some changes to itself.
My batch file is:
START /D "C:\Users\me\AppData\Roaming\Test\Test.exe"
When I run it though I just get a brief console flash and Test.exe doesn't start up.
I've verified the EXE is there in the directory.
I've launched the exe manually to verify it is working as well.
My batch file resides in
C:\Users\admin\AppData\Roaming\run.bat"
There are two issues:
The /D option solely defines the starting or working directory, but not the program to execute.
The start command considers the first quoted argument as the title of the new window. To avoid confusion with other arguments, always provide a window title (that may also be empty).
There are two solutions, which are actually not exactly equivalent:
Remove the /D option, so the current working directory is used:
start "" "C:\Users\me\AppData\Roaming\Test\Test.exe"
Keep the /D option and explicitly provide the new working directory to be used:
start "" /D "C:\Users\me\AppData\Roaming\Test" "Test.exe"
try changing to this
start /d "C:\Users\me\AppData\Roaming\Test" Test.exe
You will see the console flash and your program should startup.
Update
Thanks for #SomethingDark 's suggestion to use the following code.
start "" C:\Users\me\AppData\Roaming\Test\Test.exe
However, the above code will not work if your filename contains space.
Try with the following command.Add it to your batch script.Notice that you have to add double quotes after start keyword if there is/are whitespaces in the path string.
start "" "C:\Users\me\AppData\Roaming\Test\Test.exe"
Enclose any directory names which are longer than one-word into quotation marks. So the following path:
start C:\Program Files\MySQL\MySQL Workbench 8.0 CE\MySQL.exe
Should become something like this:
start C:\"Program Files"\MySQL\"MySQL Workbench 8.0 CE"\MySQL.exe
This is sort of a follow-up to my question earlier (link).
To test things out I made this simple batch file to ensure the Task Scheduler was properly executing the batch file:
cd "C:\Users\user\Desktop"
echo. 2>test.txt
So after the test.txt document is created on the desktop, the batch file should end but it continues to run:
Is there a way, either at the end of the batch file or a setting in the Task's Properties, to ensure that the cmd process quits?
Thanks!
I ran into the exact same problem. However, I felt duped when I read what Trevor778 wrote in this post:
I had the same problem - the task worked but the status kept showing Running. One simple thing to try is click on the Task Scheduler Library in the left column. Click Action/Refresh. Presto. Status changed to Ready. That's all it was for me, the task ran fine, just the status didn't update. Hope this helps.
ref: https://social.technet.microsoft.com/Forums/en-US/2f6dc29c-3b8b-45f5-a2a7-53e076acc062/task-scheduler-scheduler-status-is-being-running-always?forum=winservergen
you can add "exit" to last line of your script
cd "C:\Users\user\Desktop"
echo. 2>test.txt
exit
Running TASKKILL /F /IM cmd.exe will kill all cmd.exe processes whether it was the one that spawned this batch file or not. That's probably not desirable behavior. :-)
Judging by your last question, I'm guessing you're still running your task with cmd.exe /k, which will keep that window open indefinitely. For an unattended task, cmd.exe /c is a better choice. When the batch file finishes, the process should end.
Same here on Windows 7.
Putting all batch files in a directory in the user User specific path who runs the task
run programm = " cmd.exe " (without a path)
Your extras, mine where = " /c "C:\Users[username]\whatever\your_batchfile.bat" >> log.txt" "
" >> log.txt " so that i can see the output of the batch...
start in = " C:\Users[username]\whatever "
I also checked the "run with highest privilges" box
after that everything worked fine :)
Use following
exit /B
you may find more information in windows console area then type:exit/?
I know it's an old question, but I personally found that if I let a pause at the end of the bat file, it would keep the status as "Running".
I usually leave a pause at the end to help with debugging, but I found when I removed it, the task scheduler finally recognised it as having exited. It didn't help if I just refreshed it.
The solution I found was to add this line at the very end of the batch file:
TASKKILL /F /IM cmd.exe
Now after the batch file task runs and completes, it is no longer in the All Running Tasks list and the status goes back to 'Ready' instead of staying at 'Running'.
Warning:
That command will kill all running command processor instances so it may be potentially harmful!
On a cmd prompt or bat file, I issue the following:
start textpad myfile.txt and it works fine.
If the program textpad does not exist on the computer, then an error sound and a popup occurs which the OK button must be pushed.
I desire to trap this error so that I could do something like
start textpad myfile.txt || start notepad myfile.txt
where the || implies that if the start of textpad is not successful, then the start of notepad should occur. HOWEVER, I still get the error sound and requirement of hitting OK.
My intent is to avoid the sound and the requirement of any user intervention.
I have also tried the following bat approach below, to no avail.
start textpad
if not %ERRORLEVEL% == 0 GOTO END
start notepad
:END
Any help would be great.
thanks
ted
You can use the following little snippet to find out whether the program you intend to launch exists:
for %%x in (textpad.exe) do set temp=%%~$PATH:x
if [%temp%]==[] echo Didn't exist.
But may I suggest that you simply use
start foo.txt
instead of forcing a specific editor onto the user? File type associations are there for a reason.
I do not believe you will find a way to make that work. Perhaps look for the existence of textpad.exe on the machine? If you can predict what directory it would be loaded from, this should be pretty easy using IF EXIST.
There are some techniques to detect the presence of a specific tool, but this only works for command line tool, or with GUI applications also supporting command line options.
For these tricks, take a look at this page.
"/wait" parameter would do the trick for you..
START /wait NOTEPAD.EXE SOME.TXT
echo %ERRORLEVEL%
# This gives zero as output.
START /wait TEXTPAD.EXE SOME.TXT
echo %ERRORLEVEL%
# This gives non-zero output.
You probably already have an answer, but my over-sized ego has forced me to post my answer.
So, this should work.
start textpad 2> nul||start notepad
This will start notepad if the command start texpad fails, while also redirecting any error message you may get from the first command.