Laravel WHERE ALL IN or Nothing - database

Question

I'm making a system to filter demands of the user and for one part I must filter by all attributes selected, here is my query builder :
return EncyclopedieModel::with('stats')
->join('equipement_stats', 'equipement_stats.id_equipement', '=', 'equipement.id_equipement')
->join('stats', 'stats.id_stats','=','equipement_stats.id_stats')
->whereIn('stats.id_stats', $filterStats)
->whereIn('id_typeequipement', $filterEquipement)
->whereIn('id_rarete', $filterRarity)
->skip(0 + $toskip)
->take(10)
->get()
->toJson();
I must filter on multiple demands for stats.
I firstly take all equipements that fit the demand of the user then I get the statistics of the item with eager loading.
My problem is that I must get item that has both stats at the same time. For example if my item has the statistic "3" and "7" I must get all items that have both these statistics.
Now, I'm getting all equipements with the statistic "3" and all equipements with the statistic "7"...
I don't know how I should implement it
EDIT : I tried so simplifize with a car and caracteristics
[
{
"id_car":1,
"nom_car":"Car A",
"rarity": 1,
"caracteristic":[
{
"id_caracterstic":3,
"nom_stats":"Caracteristic A"
},
{
"id_caracterstic":8,
"nom_stats":"Caracteristic W"
},
{
"id_caracterstic":4,
"nom_stats":"Caracteristic Z"
}
]
},
{
"id_car":2,
"nom_car":"Car B",
"rarity": 2,
"caracteristic":[
{
"id_caracterstic":5,
"nom_stats":"Caracteristic P"
},
{
"id_caracterstic":8,
"nom_stats":"Caracteristic W"
},
{
"id_caracterstic":12,
"nom_stats":"Caracteristic ZA"
}
]
},
{
"id_car":1,
"nom_car":"Car C",
"rarity": 2,
"caracteristic":[
{
"id_caracterstic":12,
"nom_stats":"Caracteristic P"
},
{
"id_caracterstic":8,
"nom_stats":"Caracteristic W"
},
{
"id_caracterstic":14,
"nom_stats":"Caracteristic ZDD"
}
]
},
]
It's like I must find cars in my database which rarity is "2" and caracteristics are 8 and 12.
The way I'm doing now, I'm getting Car A, Car B and Car C because my query looks through all cars with caracteristic 8 and all cars with caracteristic 12
What I want is to only get Car B and Car C when I'm looking for a car with caracteristic "8" and "12"

Answer 1

From your question, my understanding is that you want to filter your models to include only those that have all of the requisite equipment types.
With that in mind, you simply need to modify your existing query to use HAVING and GROUP BY.
return EncyclopedieModel::with('stats')
->join('equipement_stats', 'equipement_stats.id_equipement', '=', 'equipement.id_equipement')
->join('stats', 'stats.id_stats','=','equipement_stats.id_stats')
->whereIn('stats.id_stats', $filterStats)
->whereIn('id_typeequipement', $filterEquipement)
->whereIn('id_rarete', $filterRarity)
->groupBy('enclopedie.id_car')
->havingRaw('COUNT(id_typeequipement) = ?', [count($filterEquipement)])
->skip(0 + $toskip)
->take(10)
->get()
->toJson();
The GROUP BY is required to group the equipment types per distinct model for comparision later. The HAVING is essentially a WHERE clause applied to an aggregate function. In this case, COUNT.
So we want to find all models that exactly match the number of specified equipment types.
Edit - HAVING definition
A HAVING clause in SQL specifies that an SQL SELECT statement should only return rows where aggregate values meet the specified conditions. It was added to the SQL language because the WHERE keyword could not be used with aggregate functions.