I'm trying to find out the average count of IIS calls per second (GET, POST, PUT, etc) in a time span of one week
Here's an example of a SELECT I'd use to get total counts in a week:
SELECT Method, COUNT(*)
AS TotalCalls
FROM IISLog
WHERE dDate
BETWEEN '2018-05-10'
AND '2018-05-17'
GROUP BY Method
How can I granularise this SELECT to get an average count of Method calls per second in this date range?
Expected output for calls per second:
Method CallsPerSecond
Get 15
Put 10
Post 14
Delete 12
The number counts are just example estimates
Just divide by the amount of seconds that compose your filter ranges.
DECLARE #StartDate DATETIME = '2018-05-10'
DECLARE #EndDate DATETIME = '2018-05-17'
SELECT
Method,
CallsPerSecond = COUNT(*) / NULLIF(DATEDIFF(SECOND, #StartDate, #EndDate), 0),
TotalCalls = COUNT(*)
FROM
IISLog AS I
WHERE
I.dDate BETWEEN #StartDate AND #EndDate
GROUP BY
I.Method
Related
i have a table with datetime, i need to find the avg of the time. i tried CASE statement but it gave me an error Operand data type time is invalid for avg operator.
select * from datestime
dates
2015-11-23 15:05:40.923
2015-11-23 15:05:43.610
2015-11-23 15:05:45.790
2015-11-23 15:05:48.293
first I split the colum into two column date and time
"select convert(date,dates,104) as date,convert(time,dates,108) as time from datestime"
then use CASE To calculate the avg of time.
;with avgtime as(
select convert(date,dates,104) as date,convert(time,dates,108) as time from datestime)
select avg(time) from avgtime
please help me to find the avg time
You can get the midpoint between the start/end date in the range by doing this:
declare #start datetime = '2015-12-01T10:00:00'
declare #finish datetime = '2015-12-01T11:00:00'
print dateadd( second, ( datediff( second, #start, #finish ) / 2 ), #start )
I need to get the number of elapsed days between any two dates with respect to the current date. IE:
mm/dd/yyyy
Current day = 07/10/2015
07/08/2013 ... 07/11/2013 - 4 days elapsed
Current day = 07/10/2015
07/08/2015 ... 07/11/2015 - 2 days have elapsed
I've tried several combinations using DATEDIFF with day as the date part, however, I can't seem to get a clean way to get the days elapsed when the date could be past or present.
EDIT
I know the start date and the end date of a certain business process. They could be this year, last year, two years ago and so on. I need a way via SQL Server functions to figure out the days total elapsed. If it's not the current year, obviously the entire span/range would have elapsed. If it's the current year, perhaps the entire span/range hasn't elapsed and it needs to say how many days are "into the process" based on the respected start time, end time and current time.
Hopefully this makes more sense?
Please help.
I used #Sean Lange, with a small tweak:
DATEDIFF(DAY, #StartDate, case when #EndDate < GETDATE() then #EndDate + 1 else GETDATE() end)
Thanks all.
This is pretty similar to the answer provided by Stan but here is my take on this.
with Something as
(
select CAST('2013-07-08' as datetime) as StartDate
, CAST('2013-07-11' as datetime) as EndDate
union all
select '2015-07-08', '2015-07-11'
)
select *
, DATEDIFF(DAY, StartDate, case when EndDate < GETDATE() then EndDate else GETDATE() end)
from Something
How about this:
Given:
CREATE TABLE dbo.test ( ChildID INT Identity,
Start DateTime
, Finish DateTime
)
and your test data:
insert into dbo.test (start,finish) values('07/08/2013','07/11/2013')
insert into dbo.test (start,finish) values('07/08/2015','07/11/2015')
then
select start,finish
, DATEDIFF(DAY, start, CASE WHEN GETDATE() BETWEEN start and finish
THEN GETDATE() - 1 ELSE finish END) + 1 as elapsed
from dbo.test
gives the result from your example.
You might have to tweak if there are other adjustments for how the current date fits between the range.
We have a requirement to bill our customers per day. We bill for an asset's existence in our system on that day. So, I started with datediff...
select datediff(dd ,'2015-04-24 12:59:32.050' ,'2015-05-01 00:59:59.000');
Returns this:
7
But I need to count the following dates: 4/24,4/25,4/26,4/27,4/28,4/29, 4/30, 5/1, which are 8 days. So datediff isn't quite working right. I tried these variations below
--too simple, returns 7, i need it to return 8
select datediff(dd ,'2015-04-24 12:59:32.050', '2015-05-01 23:59:59.000');
--looking better, this returns the 8 i need
select ceiling(datediff(hh,'2015-04-24 12:59:32.050', '2015-05-01 23:59:59.000')/24.0);
-- returns 7, even though the answer still needs to be 8. (changed enddate)
select ceiling(datediff(hh,'2015-04-24 12:59:32.050', '2015-05-01 00:59:59.000')/24.0);
So, my question... How, in SQL, would I derive the date count like i described, since I believe datediff counts the number of day boundaries crossed.... My current best approach is loop through each day in a cursor and count. Ick.
Use CONVERT to get rid of the time part, add 1 to get the desired result:
SELECT DATEDIFF(dd,
CONVERT(DATE, '2015-04-24 12:59:32.050'),
CONVERT(DATE, '2015-05-01 00:59:59.000')) + 1;
It turns out the time part does not play any significant role in DATEDIFF when dd is used as the datepart argument. Hence, CONVERT is redundant. This:
SELECT DATEDIFF(dd, '2015-04-24 23:59:59.59','2015-05-01 00:00:00.000') + 1
will return 8 as well.
You could try this which would return 8 days.
select datediff(dd ,'2015-04-24 12:59:32.050' ,CASE DATEDIFF(Second,'2015-05-01 00:00:00.000','2015-05-01 23:59:59.000') WHEN 0 THEN '2015-05-01 23:59:59.000' ELSE DATEADD(dd,+1,'2015-05-01 23:59:59.000') END)
If you want to use variables for your dates then something like this would work.
BEGIN
DECLARE #StartDate DATETIME
DECLARE #EndDate DATETIME
DECLARE #EndDateOnly DATE
SET #StartDate = '2015-04-24 12:59:32.050'
SET #EndDate = '2015-05-01 23:59:59.000'
SET #EndDateOnly = CAST(#EndDate AS DATE)
SELECT datediff(dd ,#StartDate ,CASE DATEDIFF(Second,CAST(#EndDateOnly||' 00:00:00.000' AS DATETIME),#EndDate) WHEN 0 THEN #EndDate ELSE DATEADD(dd,+1,#EndDate) END)
END
I'm trying to create utilization graph for a telephone system. I have sets of data which is in the table format
ID *
StartDate
EndDate
From
To
What I'm trying to do is get SQL to to output me a list of plot points every 5 minutes, so basically
The count of active calls (between StartDate and EndDate) for every 5 minutes in a day.
The result beign something like
Date Time Count
2000-01-01 00:00:00 10
2000-01-01 00:05:00 2
2000-01-01 00:10:00 7
Can anyone suggest a way to generate said data? I'm at a loss here! The stuff I've been thinking abut all involves a creating a big loop and running a query for every 5 seconds which seems super inefficient.
The method I was originally thinking was :-
storedProc GetSamples(SampleStartDate, SampleEndDate)
Create memory table for result data
for every 5mins as sample between SampleStartDate and SampleEndDate
SELECT #SampleCount = COUNT(1) FROM Samples where 5mins BETWEEN StartDate AND EndDate
UPDATE memoryTable SET count=#SampleCount WHERE time = 5mins
end
end
If you have a recent enough version of SQL Server (2008+), you ought to be able to do this with a CTE joined to your phone call log, like this (CTE base found here):
DECLARE #StartDate DATETIME
DECLARE #EndDate DATETIME
SET #StartDate = '2000-01-01 00:00:00.000'
SET #EndDate = '2000-01-02 00:00:00.000'
;WITH DateSequence( [PlotPointDate] ) AS
(
SELECT #StartDate AS [PlotPointDate]
UNION ALL
SELECT DATEADD(MINUTE, 5, [PlotPointDate] )
FROM DateSequence
WHERE [PlotPointDate] < #EndDate
)
--select result
SELECT
PlotPointDate, COUNT(YourTable.ID) AS TotalActiveCalls
FROM
DateSequence
LEFT JOIN
YourTable ON
YourTable.StartDate <= DateSequence.PlotPointDate AND
(YourTable.EndDate >= DateSequence.PlotPointDate OR YourTable.EndDate IS NULL)
GROUP BY PlotPointDate
OPTION (MaxRecursion 10000)
I'm having a little trouble getting a count of dates in SQL SERVER. I require the number of calender days between 2 dates start and ends dates included. The problem with the example below is that it always returns 10 when I believe it should be 11.
DECLARE #FROM DATETIME, #TO DATETIME
SET #FROM = '18/12/2011 00:00:00'
SET #TO = '28/12/2011 00:00:00'
SELECT
DATEDIFF(MINUTE,#FROM,#TO), -- Returns 14459
DATEDIFF(HOUR,#FROM,#TO), -- Returns 241
DATEDIFF(DAY,#FROM,#TO), -- Returns 10
CEILING(CAST((DATEDIFF(HOUR,#FROM,#TO) / 24) as DECIMAL(9,5))) --Returns 10
CEILING(CAST(CEILING(CEILING(CAST(DATEDIFF(SECOND,#FROM,#TO) as DECIMAL(18,5))) / 60) / 60 as DECIMAL(9,5)) / 24) --Returns 10
The bottom line works if there is at least 1 second between the times but I must account for all scenarios.
My only other thought was to simply add one to the date diff to account for the part days? Is that reliable?
DATEDIFF(DAY,#FROM,#TO) + 1
I came across when answering this question How to find the total between the dates for each values
Is an expression that can be resolved to a time, date, smalldatetime,
datetime, datetime2, or datetimeoffset value. date can be an
expression, column expression, user-defined variable or string
literal. startdate is subtracted from end date.
This is taken from MSDN here.
28-18 = 10. I think you will always have to add 1 in the scenario you have because of the definition for DATEDIFF.
You need to set the #TO date to:
SET #TO = '28/12/2011 23:59:59'
To get the number of days between two dates (ignoring the time of day), including the start and end date, try;
SELECT FLOOR(CONVERT(FLOAT, #TO))-FLOOR(CONVERT(FLOAT, #FROM))+1
Edit:
SELECT DATEDIFF(d, #FROM, #TO)+1
seems to return the exact same results, which would indeed make it a more elegant way of doing it. Always thought DATEDIFF timeparts were about truncating after the calculation (which would give the wrong result if the start time was later in the day than the end time) and not truncating before the calculation which gives the correct result for your case. You learn something new every day :)
If you want a close equivalent of the C# DateTime.TotalDays() function (i.e. to know fractional days) you can use the following:
DECLARE #start DATETIME = '10 Apr 2012 15:00'
DECLARE #end DATETIME = '12 Apr 2012 16:00'
SELECT CONVERT(FLOAT, DATEDIFF(SECOND, #start, #end)) / 86400
*Note: 86400 = seconds in a day = 24 hours x 60 mins x 60 seconds