I have table that shows these information
Month NewClients OnHoldClients
5-2017 10 2
6-2017 16 4
7-2017 11 1
8-2017 15 6
9-2017 18 7
I am trying to find the accumulative total for each month
which is
(NewClients - OnHoldClients) + Previous Month Total
Something like this
Month NewClients OnHoldClients Total
5-2017 10 2 8
6-2017 16 4 20
7-2017 11 1 30
8-2017 15 6 39
9-2017 18 7 50
the query i tried to build was something like this but I think should be an easier way to do that
UPDATE MyTable
SET Total = (SELECT TOP 1 Total FROM MyTable B WHERE B.Month < A.Month) + NewClients - OnHoldClients
FROM MyTable A
Before we begin, note the mere fact that you're facing such calculative problem is a symptom that maybe you don't have the best possible design. Normally for this purpose calculated values are being stored along the way as the records are inserted. So i'd say you'd better have a total field to begin with and calculate it as records amass.
Now let's get down to the problem at hand. i composed a query which does that nicely but it's a bit verbose due to recursive nature of the problem. However, it yields the exact expected result:
DECLARE #dmin AS date = (SELECT min(mt.[Month]) from dbo.MyTable mt);
;WITH cte(_Month, _Total) AS (
SELECT mt.[Month] AS _Month, (mt.NewClients - mt.OnHoldClients) AS _Total
FROM dbo.MyTable mt
WHERE mt.[Month] = #dmin
UNION ALL
SELECT mt.[Month] AS _Month, ((mt.NewClients - mt.OnHoldClients) + ccc._Total) AS _Total
FROM dbo.MyTable mt
CROSS APPLY (SELECT cc._Total FROM (SELECT c._Total,
CAST((row_number() OVER (ORDER BY c._Month DESC)) AS int) as _Rank
FROM cte c WHERE c._Month < mt.[Month]) as cc
WHERE cc._Rank = 1) AS ccc
WHERE mt.[Month] > #dmin
)
SELECT c._Month, max(c._Total) AS Total
FROM cte c
GROUP BY c._Month
It is a recursive CTE structure that goes about each record all along the way to the initial month and adds up to the final Total value. This query only includes Month and Total fields but you can easily add the other 2 to the list of projection.
Try this
;WITH CTE([Month],NewClients,OnHoldClients)
AS
(
SELECT '5-2017',10,2 UNION ALL
SELECT '6-2017',16,4 UNION ALL
SELECT '7-2017',11,1 UNION ALL
SELECT '8-2017',15,6 UNION ALL
SELECT '9-2017',18,7
)
SELECT [Month],
NewClients,
OnHoldClients,
SUM(MonthTotal)OVER( ORDER BY [Month]) AS Total
FROM
(
SELECT [Month],
NewClients,
OnHoldClients,
SUM(NewClients-OnHoldClients)OVER(PArtition by [Month] Order by [Month]) AS MonthTotal
FROM CTE
)dt
Result,Demo:http://rextester.com/DKLG54359
Month NewClients OnHoldClients Total
--------------------------------------------
5-2017 10 2 8
6-2017 16 4 20
7-2017 11 1 30
8-2017 15 6 39
9-2017 18 7 50
Related
I want to know who has the most friends from the app I own(transactions), which means it can be either he got paid, or paid himself to many other users.
I can't make the query to show me only those who have the max friends number (it can be 1 or many, and it can be changed so I can't use limit).
;with relationships as
(
select
paid as 'auser',
Member_No as 'afriend'
from Payments$
union all
select
member_no as 'auser',
paid as 'afriend'
from Payments$
),
DistinctRelationships AS (
SELECT DISTINCT *
FROM relationships
)
select
afriend,
count(*) cnt
from DistinctRelationShips
GROUP BY
afriend
order by
count(*) desc
I just can't figure it out, I've tried count, max(count), where = max, nothing worked.
It's a two columns table - "Member_No" and "Paid" - member pays the money, and the paid is the one who got the money.
Member_No
Paid
14
18
17
1
12
20
12
11
20
8
6
3
2
4
9
20
8
10
5
20
14
16
5
2
12
1
14
10
It's from Excel, but I loaded it into sql-server.
It's just a sample, there are 1000 more rows
It seems like you are massively over-complicating this. There is no need for self-joining.
Just unpivot each row so you have both sides of the relationship, then group it up by one side and count distinct of the other side
SELECT
-- for just the first then SELECT TOP (1)
-- for all that tie for the top place use SELECT TOP (1) WITH TIES
v.Id,
Relationships = COUNT(DISTINCT v.Other),
TotalTransactions = COUNT(*)
FROM Payments$ p
CROSS APPLY (VALUES
(p.Member_No, p.Paid),
(p.Paid, p.Member_No)
) v(Id, Other)
GROUP BY
v.Id
ORDER BY
COUNT(DISTINCT v.Other) DESC;
db<>fiddle
Imagine a table :
ID Month Year Value 1
1 May 17 58
2 June 09 42
3 December 18 58
4 December 18 58
5 September 10 84
6 May 17 42
7 January 16 3
I want to return all the data that shares the same month and year where Value 1 is different. So in our example, I want to return 1 and 6 only but not 3 and 4 or any of the other entries.
Is there a way to do this? I am thinking about a combination of distinct and group by but can't seem to come up with the right answer being new to SQL.
Thanks.
It could be done without grouping, but with simple self-join:
select distinct t1.*
from [Table] t1
inner join [Table] t2 on
t1.Month = t2.Month
and t1.Year = t2.Year
and t1.Value_1 <> t2.Value_1
You can find some information and self-join examples here and here.
For each row you can examine aggregates in its group with the OVER clause. eg:
create table #t(id int, month varchar(20), year int, value int)
insert into #t(id,month,year,value)
values
(1,'May' ,17, 58 ),
(2,'June' ,09, 42 ),
(3,'December' ,18, 58 ),
(4,'December' ,18, 58 ),
(5,'September',10, 84 ),
(6,'May' ,17, 42 ),
(7,'January' ,16, 3 );
with q as
(
select *,
min(value) over (partition by month,year) value_min,
max(value) over (partition by month,year) value_max
from #t
)
select id,month,year,value
from q
where value_min <> value_max;
If I understood your question correctly, you are looking for the HAVING keyword.
If you GROUP BY Month, Year, Value_1 HAVING COUNT(*) = 1, you get all combinations of Month, Year and Value_1 that have no other occurrence.
IP QID ScanDate Rank
101.110.32.80 6 2016-09-28 18:33:21.000 3
101.110.32.80 6 2016-08-28 18:33:21.000 2
101.110.32.80 6 2016-05-30 00:30:33.000 1
I have a Table with certain records, grouped by Ipaddress and QID.. My requirement is to find out which record missed the sequence in the date column or other words the date difference is more than 30 days. In the above table date diff between rank 1 and rank 2 is more than 30 days.So, i should flag the rank 2 record.
You can use LAG in Sql 2012+
declare #Tbl Table (Ip VARCHAR(50), QID INT, ScanDate DATETIME,[Rank] INT)
INSERT INTO #Tbl
VALUES
('101.110.32.80', 6, '2016-09-28 18:33:21.000', 3),
('101.110.32.80', 6, '2016-08-28 18:33:21.000', 2),
('101.110.32.80', 6, '2016-05-30 00:30:33.000', 1)
;WITH Result
AS
(
SELECT
T.Ip ,
T.QID ,
T.ScanDate ,
T.[Rank],
LAG(T.[Rank]) OVER (ORDER BY T.[Rank]) PrivSRank,
LAG(T.ScanDate) OVER (ORDER BY T.[Rank]) PrivScanDate
FROM
#Tbl T
)
SELECT
R.Ip ,
R.QID ,
R.ScanDate ,
R.Rank ,
R.PrivScanDate,
IIF(DATEDIFF(DAY, R.PrivScanDate, R.ScanDate) > 30, 'This is greater than 30 day. Rank ' + CAST(R.PrivSRank AS VARCHAR(10)), '') CFlag
FROM
Result R
Result:
Ip QID ScanDate Rank CFlag
------------------------ ----------- ----------------------- ----------- --------------------------------------------
101.110.32.80 6 2016-05-30 00:30:33.000 1
101.110.32.80 6 2016-08-28 18:33:21.000 2 This is greater than 30 day. Rank 1
101.110.32.80 6 2016-09-28 18:33:21.000 3 This is greater than 30 day. Rank 2
While Window Functions could be used here, I think a self join might be more straight forward and easier to understand:
SELECT
t1.IP,
t1.QID,
t1.Rank,
t1.ScanDate as endScanDate,
t2.ScanDate as beginScanDate,
datediff(day, t2.scandate, t1.scandate) as scanDateDays
FROM
table as t1
INNER JOIN table as t2 ON
t1.ip = t2.ip
t1.rank - 1 = t2.rank --get the record from t2 and is one less in rank
WHERE datediff(day, t2.scandate, t1.scandate) > 30 --only records greater than 30 days
It's pretty self-explanatory. We are joining the table to itself and joining the ranks together where rank 2 gets joined to rank 1, rank 3 gets joined to rank 2, and so on. Then we just test for records that are greater than 30 days using the datediff function.
I would use windowed function to avoid self join which in many case will perform better.
WITH cte
AS (
SELECT
t.IP
, t.QID
, LAG(t.ScanDate) OVER (PARTITION BY t.IP ORDER BY T.ScanDate) AS beginScanDate
, t.ScanDate AS endScanDate
, DATEDIFF(DAY,
LAG(t.ScanDate) OVER (PARTITION BY t.IP ORDER BY t.ScanDate),
t.ScanDate) AS Diff
FROM
MyTable AS t
)
SELECT
*
FROM
cte c
WHERE
Diff > 30;
First of all my result looks like this:
KONTONR
Month
SELSKAPSKODE
BELOP
459611
1
BAGA
156000
459611
2
BAGA
73000
459611
4
BAGA
217000
459611
5
BAGA
136000
459611
1
CIVO
45896
459611
3
CIVO
32498
459611
4
CIVO
9841
330096
1
BAGA
42347
330096
3
BAGA
3695
I'm trying to show month 2 month bookings on several accounts, per account (KONTONR) there are several codes (SELSKAPSKODE) on which bookings are recorded (the sum of the bookings as BELOP). I would like to give an overview of the sum of the bookings (BELOP) per account (KONTONR) per month per code (SELSKAPSKODE). My problem is the codes don't show in a month if no bookings are made on that code. Is there a way to fix this? I understand why the codes don't show, since they're simply not in the table I'm querying. And I suspect that the solution is in making a 'fake' table which I then join (left outer join?) with 'another' table.
I just can't get it to work, I'm pretty new to SQL. Can someone please help?
My query looks like this (I only inserted the 'nested' query to make a set-up for a join, if this makes sense?!):
SELECT TOP (100) PERCENT KONTONR, Month, SELSKAPSKODE, BELOP
FROM (
SELECT SELSKAPSKODE, KONTONR, SKIPS_KODE, MONTH(POSTDATO) AS Month, SUM(BELOP) AS BELOP
FROM dbo.T99_DETALJ
WHERE (POSTDATO >= '2012-01-01') AND (BILAGSART = 0 OR BILAGSART = 2)
GROUP BY SELSKAPSKODE, KONTONR, SKIPS_KODE, MONTH(POSTDATO)
) AS T99_summary
GROUP BY KONTONR, SELSKAPSKODE, Month, BELOP
ORDER BY KONTONR, SELSKAPSKODE, Month
So concluding I would like to 'fill up' the missing months (see table at the start), for instance for account (KONTONR) 459611 month 3 is 'missing'. I would like to show month 3, with the sum of the bookings (BELOP) as '0'. Any help is greatly appreciated, thanks in advance!
You can query a table with the values 1-12 and left outer join your result.
Here is a sample using a table variable instead of your query and a CTE to build a table with numbers.
declare #T table
(
Month int
)
insert into #T values(1)
insert into #T values(1)
insert into #T values(1)
insert into #T values(3)
insert into #T values(3)
;with Months(Month) as
(
select 1
union all
select Month + 1
from Months
where Month < 12
)
select M.Month,
count(T.Month) Count,
isnull(sum(T.Month), 0) Sum
from Months as M
left outer join #T as T
on M.Month = T.Month
group by M.Month
Result:
Month Count Sum
----------- ----------- -----------
1 3 3
2 0 0
3 2 6
4 0 0
5 0 0
6 0 0
7 0 0
8 0 0
9 0 0
10 0 0
11 0 0
12 0 0
if you don't want to do all that you could also modify this: SUM(BELOP) with this:
Sum (case when BELOP is not null then 1 else 0 end)
You can also add in the year if you have a creation date for the interactions you are counting which may be helpful if your interactions span the course of many years.
with Months(Month) as
(
select 1
union all
select Month + 1
from Months
where Month < 12
)
select M.Month, year(CreatedOn) as Year,
count(amount) Count,
isnull(sum(amount), 0) Sum
from Months as M
left outer join Charge as C
on M.Month = (month(CreatedOn))
group by M.Month, year(CreatedOn) order by year(CreatedOn)
Say I have a table like the following:
PK Code Value
1 A 200
2 A 300
3 A 25
4 A 75
5 A 50
6 A 15
7 A 300
8 A 75
How would I get the value of the top 4 highest values where code=A (i.e. just want the sum of 300 + 300 + 200 + 75)
Thanks
You can use a derived table or Common Table Expression to get the top 4 then SUM that.
SELECT SUM(Value) As Top4Sum
FROM
(
SELECT TOP (4) Value
FROM YourTable
WHERE Code = 'A'
ORDER BY Value DESC
) T
If you wanted the SUM of the TOP 4 for every Code you could do
;WITH CTE
AS (SELECT *,
ROW_NUMBER() OVER (PARTITION BY Code ORDER BY Value DESC) RN
FROM YourTable)
SELECT Code,
SUM(Value)
FROM CTE
WHERE RN <= 4
GROUP BY Code