I have the following SQL Server table with the following data:
PRICE(decimal 9,2) PRICETYPE(int) EVENTDETAILID (int)
PRICE PRICETYPE EVENTDETAILID
------------------------------------------------
99 1 1
99 1 1
99 1 1
15 0 1
15 0 1
50 1 2
50 1 2
I want to SUM the PRICE of the results with the following conditions:
for each EVENTDETAILID, SUM every line with a pricetype is 0 and for every line per EVENTDETAILID pricetype is 1, then add it only 1 time.
For the above example the required output would be:
99 + 15 + 15 for eventDetailId = 1
50 for eventDetailsId = 2
I've tried the following but doesn't work as expected as I'm not able to add PRICE only once if PRICETYPE is 1:
SELECT
SUM(PRICE)
FROM
ReservationDetails
GROUP BY
eventDetail_id
You may phrase this as an aggregation (GROUP BY) query over the event detail ID. The sum can be broken into a conditional sum when the detail ID is 0, combined with the maximum price when the detail ID is 1. Since you told us that the price is always the same when PRICETYPE=1, therefore we can choose any single value.
SELECT
EVENTDETAILID,
SUM(CASE WHEN PRICETYPE = 0 THEN PRICE ELSE 0 END) +
MAX(CASE WHEN PRICETYPE = 1 THEN PRICE ELSE 0 END) AS total
FROM yourTable
GROUP BY
EVENTDETAILID
ORDER BY
EVENTDETAILID;
Demo
Related
I have 2 tables, Tbl1 and Tbl2 :
Tbl1:
ID Col1 Col2 Sold Total
1 AA 0 100
1 BB CC 2 200
1 DD EE 3 300
2 FF GG 1 100
Tbl2:
ID Sold Total TotalPerPax
I need to calculate the TotalPerPax in Tbl2 depending on the ID But the calculation of the TotalPerPax is like this. Example:
ID = 1
Sold: 0 + 2 + 3 = 5
Total = 100 + 200 + 300 = 600
TotalPerPax = (Total minus the Total of the row that has 0 sold / Sold )
(600 -100 ) / 5 = 500
The output should look like this
Tbl2:
ID Sold Total TotalPerPax
1 5 600 100 -- (500 Total / 5 Sold)
2 1 100 100
So far I have this:
When executing it throws an error "Divide by zero error encountered" thus I can't compute the totalPerPax correctly. Can anyone can help me to with this? Thanks
SELECT ID,
Col1
Col2,
Sold,
Total,
SUM(COALESCE(Total, 0))/SUM(COALESCE(Sold, 0)) As TotalPerPax
FROM Tbl1 t1
Where ID = 1
GROUP BY ID, Col1, Col2,Sold, Total
Sample sql fiddle: http://sqlfiddle.com/#!18/09971/2
aI would phrase this as:
SELECT
ID,
SUM(Sold) AS Sold,
SUM(Total) AS Total,
CASE WHEN SUM(Sold) > 0
THEN SUM(CASE WHEN Sold > 0 THEN Total ELSE 0 END) /
SUM(CASE WHEN Sold > 0 THEN Sold ELSE 0 END)
ELSE 0 END AS TotalPerPax
FROM TBl1
GROUP BY ID;
Demo
The CASE expression for TotalPerPax uses logic which does not include any total or sold amount when the latter happens to be zero. As a note, for any ID which only might have zero sold amounts, TotalPerPax would be reported as zero.
select
sum(case when Apt.productionValue != '-1.0' then Apt.subTotal
else Apt.productionValue end) as ProductionValue,Apt.date
from Appointment Apt
group by Apt.date
order by Apt.date asc
ApppointmentID
Production Value
SubTotal
Date
1
-1
10
2021-09-02
2
10
0
2021-09-02
3
-1
20
2021-09-01
4
-1
20
2021-09-01
5
5
0
2021-09-01
I'm trying to get the sum of Production value only if it is over 0, else add subtotal instead for that row.
End goal is to still have 20 as the sum for 2021-09-02 and 45 for 2021-09-01
You were close in your attempt. This should work based on the sample data provided.
select Apt.[Date]
, sum(case when Apt.ProductionValue < 0 then Apt.SubTotal else Apt.ProductionValue end)
from Appointment Apt
group by Apt.[Date]
order by Apt.[Date]
You can select the expected column in a subquery like :
select Date, SUM(ProductionValue) as ProductionValue
from (
select
Date,
case when ProductionValue > 0
then ProductionValue
else SubTotal end
as ProductionValue
from Appointment
) as d
group by Date
order by Date
I need some help with my query...I am trying to get a count of names in each house, all the col#'s are names.
Query:
SELECT
House#,
COUNT(CASE WHEN col#1 IS NOT NULL THEN 1 ELSE 0 END) +
COUNT(CASE WHEN col#2 IS NOT NULL THEN 1 ELSE 0 END) +
COUNT(CASE WHEN col#3 IS NOT NULL THEN 1 ELSE 0 END) AS count
FROM
myDB
WHERE
House# IN (house#1, house#2, house#3)
GROUP BY
House#
Desired results:
house 1 - the count is 3
house 2 - the count is 2
house 3 - the count is 1
...with my current query the results for count would be just 3's
COUNT by design doesn't count NULL values.
SELECT House#,
COUNT(col1#) + COUNT(col2#) + COUNT(col3#) AS count
FROM myDB
WHERE House# IN (house#1,house#2,house#3)
GROUP BY House#;
For a SQL Server based report,
Table:
CID Date ID Service Days
1 3/7/2016 1 Individual 3
2 4/5/2016 2 Individual 4
3 5/24/2016 1 Individual 3
4 4/4/2016 4 Group 2
5 4/4/2016 4 Group 2
6 2/18/2016 4 Group 2
7 5/5/2016 5 Group 1
8 5/5/2016 5 Group 1
I used this code:
SELECT
ID,
Service,
COUNT(WHEN Days = 4 THEN 1 END) AS '4Days',
COUNT(WHEN Days = 3 THEN 1 END) AS '3Days',
COUNT(WHEN Days = 2 THEN 1 END) AS '2Days',
COUNT(WHEN Days = 1 THEN 1 END) AS '1Day'
FROM Table T1
GROUP BY
ID,
Service
which gives me this Output:
ID Service 4Days 3Days 2Days 1Day
1 Individual 0 2 0 0
2 Individual 1 0 0 0
4 Group 0 0 3 0
5 Group 0 0 0 2
What I want to do is not count the Group services as separate services for separate individuals, but just as one service per group. A Count Distinct used with the Date or ID could help me do that but I don't know how to make that play with the Individual services where I just wanna count them individually and not using DISTINCT. So the desired output is:
ID Service 4Days 3Days 2Days 1Day
1 Individual 0 2 0 0
2 Individual 1 0 0 0
4 Group 0 0 2 0
5 Group 0 0 0 1
I'll edit the post in case I oversimplified the problem since this is dummy data.
Looks like you could use distinct this way if you wanted:
count(distinct
case when Days = 1 then case when Service = 'Group' then 1 else "Date" end end
) as [1Day]
Depending on your indexing it's possible that introducing another column in the query would change the query plan. I suspect that probably isn't the case though.
If I am not wrong for '2Days' column service type 'Group' count should be '2' if our grouping based on 'Date' column, if so then try this:
SELECT
ID,
Service,
CASE WHEN MAX(t.days) = 4 THEN MAX(t.date) ELSE 0 END AS '4Days',
CASE WHEN MAX(t.days) = 3 THEN MAX(t.date) ELSE 0 END AS '3Days',
CASE WHEN MAX(t.days) = 2 THEN MAX(t.date) ELSE 0 END AS '2Days',
CASE WHEN MAX(t.days) = 1 THEN MAX(t.date) ELSE 0 END AS '1Day'
FROM table T1
OUTER APPLY (SELECT days,
COUNT(DISTINCT(date)) date
FROM Table WHERE days = t1.days GROUP BY days) t
GROUP BY id, service
ORDER BY ID
Based on your last edit, this is the most straight forward way I could think of to handle the query:
with cte as (
select id, service, days
from table t1
where service = 'Individual'
union all
select id, service, days
from table t1
where service = 'Group'
group by id, service, days, date
)
select id,
service,
count(case when days = 4 then 'X' end) as [4Days],
count(case when days = 3 then 'X' end) as [3Days],
count(case when days = 2 then 'X' end) as [2Days],
count(case when days = 1 then 'X' end) as [1Day]
from cte
group by id, service
My table looks like this:
ID | ItemID | ItemQualityID | Amount | UnitPrice
My goal is to find the top x% rows for each ItemID + ItemQualityID pair based on Amount cumulative sum and ordered by UnitPrice.
For example:
ID | ItemID | ItemQualityID | Amount | UnitPrice
1 1 1 18 2
2 1 1 1 1
3 1 1 1 1
4 2 1 18 2
5 2 1 1 1
6 2 1 1 1
7 1 1 1 3
and I want the top 10%, then the resulting table should contain row #2, 3, 5, 6. Since the total amount for ItemID 1 and 2 are 21 and 20 respectively, thus 10% would be 2 items each. If I want the top 20%, the resulting table should still be the same since if I include row 1 and 4 it would make it 100%. Row #7 has unit price > row #1 so if row #1 is not included then row #7 shouldn't be included as well.
Ideally I want the table with all the filtered rows for some other calculations but I will be happy even if I can only get the sum of Amount * UnitPrice of the filtered table. Something like
ItemID | ItemQualityID | Sum
1 1 2
2 1 2
for the above example.
You can use SUM OVER :
DECLARE #percent DECIMAL(5, 2) = .1
;WITH CteSum AS(
SELECT *,
TotalSum = SUM(Amount) OVER(PARTITION BY ItemID, ItemQualityID),
CumSum = SUM(Amount) OVER(PARTITION BY ItemID, ItemQualityID ORDER BY UnitPrice, ID)
FROM tbl
)
SELECT
ItemID,
ItemQualityID,
[Sum] = SUM(Amount * UnitPrice)
FROM CteSum
WHERE CumSum <= #percent * TotalSum
GROUP BY ItemID, ItemQualityID
ONLINE DEMO