Alphabetical order error in C code - c

Question

I have created a program that reads a series of strings from a .txt file and after compiling a new .txt file is created where the strings should be in alphabetical order.The problem is that I can't write more than 10 words, the compiler just stops/crashes, WHY? Does it depend by the type of compiler? I am currently using Code-Bloks.How can I optimize the code to run more smoothly?
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
void arrange(int n, char *x[])
{
char *temp;
int i,str;
for(str = 0; str < n-1; ++str)
{
for(i = str+1; i < n; ++i)
{
if(strcmp(x[str],x[i]) > 0)
{
temp = x[str];
x[str] = x[i];
x[i] = temp;
}
}
}
return;
}
int number_of_lines = 0;
void countOfLinesFromFile(char *filename){
FILE* myfile = fopen(filename, "r");
int ch;
do
{
ch = fgetc(myfile);
if(ch == '\n')
number_of_lines++;
}
while (ch != EOF);
if(ch != '\n' && number_of_lines != 0)
number_of_lines++;
fclose(myfile);
return number_of_lines;
}
int main()
{
int i , ts=0;
char *x[10];
char *fileName = "WORDS.txt";
countOfLinesFromFile(fileName);
printf("%d",number_of_lines);
FILE * fp;
fp = fopen ("WORDS.txt", "r");
for(i = 0; i < number_of_lines; i++)
{
x[i] = (char*) malloc (1200*sizeof(char));
fscanf(fp, "%s", x[i]);
}
FILE *fPointer;
fPointer=fopen("Alphabetical.txt","w+");
arrange(i,x);
for(i = 0; i < number_of_lines; i++)
{
fprintf(fPointer,"%s\n",x[i]);
}
fclose(fPointer);
fclose(fp);
return 0;
}

Answer 1

char *x[10];
The buffer size is too small

Answer 2

These two lines define how much information you can store
char *x[10]; // 10 strings
x[i] = (char*) malloc (1200*sizeof(char)); // 1200 characters each
As it is written now, you can only hold a maximum of 10 strings with each string being no longer than 1200 characters.
The crash is caused when number_of_lines >= 11 in the following for loop:
for(i = 0; i < number_of_lines; i++)
{
x[i] = (char*) malloc (1200*sizeof(char));
fscanf(fp, "%s", x[i]);
}
When i is 11 you write to x[11] which is past the end of x.