Using JEXL, I am trying to initialize array and than adding elements into it, however below code gives me 'unsolvable property '0' error.
var abc=[];
abc[0]=5;
1) How can I initialize empty array and keep adding values in it?
2) Can I use it like List, where I do not need to specify size at the time of initialization ?
in JEXL syntax you can initialize objects with new function.
Other option is to add to context arraylist:
This is a working example with jexl2:
JexlEngine jexl = new JexlEngine();
String jexlExp = "var abc=new(\"java.util.ArrayList\", 1);abc[0]=5";
Expression e = jexl.createExpression( jexlExp );
List<Integer> abc = new ArrayList<>(1);
JexlContext jc = new MapContext();
//jc.set("abc", abc ); second option to add arraylist to context
Object o = e.evaluate(jc);
In JEXL, the syntax [] creates a Java array, not a List. As an array, it has a fixed size, so you cannot add values to it. However, JEXL 3.2 has a new syntax for creating an ArrayList literal. Basically, you add ... as the final element.
So in JEXL 3.2, your example could be written as:
var abc=[...];
abc.add(5);
See the JEXL literal syntax reference for more information.
Related
Contract function is defined as:
function createAggregate (string memory key, bytes32[2] memory part_array) public returns (bytes32)
and have incoming a list of parts, defined as...
List<Bytes32> elements
so was trying to use:
List<Type> items = new ArrayList<Type>();
items.add(...); // user reference
items.add(new DynamicArray<>(elements));
final Function function = new Function("createAggregate",
items,
Arrays.asList(new TypeReference<Bytes32>() {})
);
...
But this does not work, seems to be an encoding issue - what is the right what of encoding the Bytes32 ? (This seems to work fine for an array of strings)
Sort of solved this with the following (although was really looking for a more dynamic size solution)
new StaticArray2(Bytes32.class, Utils.typeMap(elements, Bytes32.class));
I am pushing an object into an array but cannot do it?
I'm doing it like this
this.passData = this.tribeForm.value;
var id = {"tribe_id": 1}
this.passData.push(id)
This is the value in the tribeForm
I also tried
var id = {tribe_id: 1}
and
this.passData.splice(0,0, id)
and
this.passData = Array.prototype.slice(id)
and
this.passData.concat(id)
but it all ends up with
TypeError: this.passData.push/splice/concat is not a function
The question is not that clear, But I understood you are manipulating form data, value of form data returns an Object, Not an array. Objects in JavaScript are represented as key-value pairs, (or attribute-value) pairs.
Example :
var object = {
name : "Jhon",
grade : 12,
gpa : 8.12
}
It is just a collection of key-value pairs, push(), concat() and other methods are supported only for Arrays not for Objects. You can achieve whatever you want simply by creating a new key/attribute and assigning the value to it.
this.passData = this.tribeForm.value
this.passData['tribe_id'] = 1
//or, Objects can also contain nested object
this.passData['someKey'] = {'tribe_id' : 1}
You can create an empty array and push objects to it
Example :
var exampleArray = []
exampleArray.push({'tribe_id' : 1})
Now, it works because exampleArray is an Array not JS object.
Thanks for A2A
First, you need to understand the error:
TypeError: this.passData.push/splice/concat is not a function
Push/splice/concat is functions for Array and because of that the console is yelling at you that the passData is not an Array.
Make sure your passData is an Array and you will able to do so.
I have an Array of [Long, Q] and would like to make a binary search on it. I tried below :
import scala.collection.Searching._
class Q (val b:Double, val a:Double)
val myArray = Array(5L -> new Q(1,2), 6L-> new Q(6,9), 7L-> new Q(7,6))
val i = myArray.search(6L).insertionPoint
but had this error
No implicit Ordering defined for Any
Unspecified value parameter ord.
I understand that I need to specify an odering rule for this collection Array[(Long,Q)] but can't figure this out myself.
Please help
Signature of search is search[B >: A](elem: B)(implicit ord: Ordering[B]). You've got an array of type [Long, Q]. So in order for the compiler to infer Ordering correctly, you'd have to invoke search like that:
myArray.search(6L-> q/*Q(6,9)*/)(Ordering.by(_._1)) //ordering by the first value in a tuple.
and what you're doing is: myArray.search(6L). If I understand correctly what you're trying to do, it's probably to find both value and position in the array.
You could solve it by using two separate data structures:
keys could be stored in the array, like this:
val myArray = Array(5L, 6L, 7L).toList
myArray.search(6L).insertionPoint
and if you'd need values, you could use map which would work as a dictionary:
val dictionary = Map(
5L -> new Q(1,2),
6L-> new Q(6,9),
7L-> new Q(7,6)
)
EDIT:
Actually, I noticed something like that would work:
val dummy = new Q(0,0) //any instance of Q
myArray.search(6L-> dummy)(Ordering.by(_._1)).insertionPoint //1
It works since for lookup of the insertion point Ordering is used and no equality test is performed.
I have an array loaded in, and been playing around in the REPL but can't seem to get this to work.
My array looks like this:
record_id|string|FALSE|1|
offer_id|decimal|FALSE|1|1,1
decision_id|decimal|FALSE|1|1,1
offer_type_cd|integer|FALSE|1|1,1
promo_id|decimal|FALSE|1|1,1
pymt_method_type_cd|decimal|FALSE|1|1,1
cs_result_id|decimal|FALSE|1|1,1
cs_result_usage_type_cd|decimal|FALSE|1|1,1
rate_index_type_cd|decimal|FALSE|1|1,1
sub_product_id|decimal|FALSE|1|1,1
campaign_id|decimal|FALSE|1|1,1
When I run my command:
for(i <- 0 until schema.length){
val convert = schema(i).toString;
convert.split('|').drop(2);
println(convert);
}
It won't drop anything. It also is not splitting it on the |
Strings are immutable, and so split and drop don't mutate the string - they return a new one.
You need to capture the result in a new val
val split = convert.split('|').drop(2);
println(split.mkString(" "));
Consider also defining a lambda function for mapping each item in the array, where intermediate results are passed on with the function,
val res = schema.map(s => s.toString.split('|').drop(2))
In the library of the .fla file I have a square exported as Class "cuad" on frame 1
I want to create an Array with 100 squares so as to move them later
So I do like this:
for (var i:uint = 0; i<100;i++)
{
var cuad_mc = new cuad();
addChild(cuad_mc);
myArray.push("cuad_mc");
trace(myArray[i]);
}
I have a runtime error
The error you experience is
Error #1069: Did not find alpha propiety in the String and there is not any value predetermined
The problem comes from your line
myArray.push("cuad_mc");
What you are doing here is pushing a String Object into your Array, not the cuad Object you want. String Objects don't have Alpha values, or x values.
What you want to do is
myArray.push(cuad_mc);
cuad_mc (without the " quotation marks) is a reference to the object you just created.
This should solve your problem. I also recommend using Vectors instead of Array if you only need to store one type of Object. Like this:
var myArray:Vector<cuad> = new Vector<cuad>();
for(var i:int=0;i<100;i++){
var cuad_mc:cuad = new cuad();
addChild(cuad_mc);
myArray.push(cuad_mc);
trace(myArray[i]);
}
Vectors are just like Arrays, but they only allow one specific type, so that a situation like yours doesn't occur.