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I have to add elements in array.
I have function:
function d = kronDel(j,k)
if j == k
d = 1;
else
d = 0;
end
And i have n=0:31.
I tried this:
x2=j*kronDel(n-2,0);
Why doesnt this work?
I only get x2=0;
You want to make a kronecker delta function but you don't need it.
x2 = j(n==2)
or, if you want to keep the zeros
x2 = j.*(n==2)
If you really want to make the function, just adapt it to:
function d = kronDel(j,k)
d = j==k;
From your comment: "x2=[0,0,j,0,0,0,0...to the 31 all 0s] j=sqrt(-1)"
x2=zeros(1,31);x2(3)=i
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If I have a string, say "abcdefghij"
How can I iterate and get to characters backwards at a time.
For example
first loop : ghij
second loop: fedc
third loop: ab
Im using C++ but dont feel like its simple enough i should be able to adapt any language
Heres what I have so far:
for(long unsigned int i=0; i<s.length();i+=4){
digits.push_back(std::stoi(s.substr(i, 4)));
}
My issue is that this is left justified, not right justified
In pseudo code:
iterate i from s.length stepping by -4, while i > 0
start = max(i - 4, 0)
part = s.substring(start, i)
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This code prints the array elements, but I can't understand how does k[x-1] gives the array elements.
#include<stdio.h>
int main()
{
int x[]={2,4,6,8,10},k=1;
while (k<=5)
{
printf ("%3d",k[x-1]);
k++;
}
return 0;
}
Array indexes start at 0 in C. An array like int x[]={2,4,6,8,10} will have a value x[0]=2 and so forth. Typically, when iterating through an array, a convention like this is used:
for (int i = 0; i < length; i++)
printf("%3d",x[i]);
Since the code you provided begins the indexing at 1, you have to subtract one to fetch the proper element.
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Can someone explain me the most simple way the meaning of this syntax of C?
for(i=0;i<n-1;i++)
{
for(j=i+1;j<n;j++)
{
if(number[i]<number[j])
{
aux=number[i];
number[i]=number[j];
number[j]=aux;
}
}
}
I just trying to figure out I know is an iteration or a loop but specifically aux is a var. Why i need to follow this i'm trying to get pos and negs, into an array but this part i'm stuck is there another way ?
I just need to figure this syntax.
This looks like Bubble Sort. aux is a temporary variable used for exchanging the values of number[i] and number[j]. You can't do
number[i] = number[j];
number[j] = number[i];
to exchange the two, as both would be equal to number[j] this way. So you need a temporary variable.
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I have an input number that it's value is not always consistent, i mean the value change plus 1 or minus 1 and etc. So, i want to compare it with a const but have a small range value, for example a const int Dist that have value between 14 to 16. Is that possible to implement it on C programming? Please help me.
You can set constant for lower bound, and constant for upper bound and check if the value falls within the range.
Pseudocode:
int const LOWER_BOUND = 14;
int const UPPER_BOUND = 16;
if (input <= UPPER_BOUND && input >= LOWER_BOUND)
... logic here ...
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I am using an array,i want to call 4 element from the array at the same time so i can use them in an equation ,any one knows how.
example
int a[10]={1,2,3,4,5,6,7,8};
I want 1234+15
how?
using C#:
1234 = 1*1000 + 2*100 + 3*10 + 4*1
double result = 0;
int ex = 3; // Math.Pow(10,3) = 1000.00
for(int i = 0; i < 4 0; i++)
{
result += a[i] * Math.Pow(10, ex);
ex--;
}
result += 15;