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I have an ASCII string coming from UART that looks something like "43.533a,5532" and I'd like to extract the two numbers. My idea was to separate them using strtok with the comma as delimiter and then remove the last character from the first string and afterwards convert the numbers using atoi() or is there an easier way with sscanf()? String manipulation is nothing I'm regularly using.
Another problem is, if the String looks different, how could I catch that beforehand?
Yes you can do this easily with sscanf().
Following is an example. See it working here:
#include <stdio.h>
int main(void) {
float a;
int b;
char *sNum = "43.533a,5532";
sscanf(sNum, "%fa,%d", &a, &b);
printf("a= %f || b= %d", a,b);
return 0;
}
Output:
a= 43.533001 || b= 5532
Note: Since float is having precision to 6 decimal place by default, so you may need to consider it and correct it if necessary.
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So i'm trying to solve this codeforce problem https://codeforces.com/contest/431/problem/A
.Basically i input 4 integers(a[0]...a[3]) and an array of integers between 1 and 4 then i need to output the sum of the string values according to the 4 initial integers.(check the codeforce's exemples)
So my code did work on the 5 initial tests but i had a wrong output on the 6th test
enter image description here
Here's the code
#include <stdio.h>
int main()
{
int test=1;
long s,result=0;
long a[3];
int i,x;
for (i=0;i<4;i++)
{
scanf("%d",&a[i]);
if (a[i]==0)
test=0;
}
scanf("%d",&s);
while (s!=0)
{
if (test==0)
break;
x=s%10;
s=s/10;
result=a[x-1]+result;
}
printf("%d",result);
return 0;
}
Your help would be much appreciated.
There have several problems with your code. But the most severe problem for which you are getting wrong output because you are using "%d" format specifier for long values, but its "%ld" actually. Using %ld will solve the problem.
Leaving rest of the problems for you to find out. Happy coding!
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Question 1.
#include <stdio.h>
int main(void)
{
int c;
while((c=getchar())!='\0')
{
putchar(c);
}
}
Input
Hello C.
Tell me about you.
Output
Hello C.
Tell me about you.
ÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿ
and it continues with status-time limit exceeded.
Question 2.
#include <stdio.h>
int main(void)
{
float a;
a=46.43253;
printf("\n%d",a);
printf("\n%f",a);
return 0;
}
Output
536870912
46.432529
Output- 536870912
46.432529
In general using incorrect format specifier triggers undefined behavior - which is what you have when you use %d in printf for printing float. In this case, you can expect any output usually.
However, it may also be the case that since you have specified to read the float number as integer (e.g. by using %d specifier), it simply interpreted the result as integer - hence the strange number (since floats and integers are stored differently).
If you are interested why the second printf prints a number slightly different from yours, this may help you.
This block is fine:
float a;
a=46.43253;
This block is also fine:
printf("\n%f",a);
The problem is with this block:
printf("\n%d",a);
Particularly this part:
"\n%d"
Please keep in mind you declared a float and using the integer syntax to output it. That's why you are getting the negative output
If it is a case where you don't want to change the "%d," then simply cast it as a float before output
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What code do you have to include to get C to produce an output from number inputted into the system.
#include <stdio.h>
int main()
{
int z;
printf("Please enter a number");
return 0;
}
I want the programme to work out a mathematical equation to the number that the user enters, for example if I enter 5 I want it to work out the exponent 2 of 1 up to that integer input.
You can use scanf function to get input from user like this:
#include <stdio.h>
int main()
{
int z;
printf("Please enter a number");
scanf("%d", &z);
// do your calculations on z
printf("Result: %d", z);
return 0;
}
You can use the scanf function.
For a number (or in your case an integer specifically) the line is
scanf("%d", &z);
where the %d specifies that its reading in an integer and the &z is a pointer to your integer variable z.
Information here: https://www.tutorialspoint.com/c_standard_library/c_function_scanf.htm
I'm guessing you're new to C programming, so once you get the basics down I would suggest familiarizing yourself with pointers as they are a critical aspect of the language. Some useful resource here using google-fu : https://www.tutorialspoint.com/cprogramming/c_pointers.htm
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I have a char array composed of elements 5 3. The array is used to represent number 53. What should be the approach to convert this number of three chars to its binary equivalent? I am implementing this in C, later on it will need to be rewritten in assembly. The solution I seek should be purely low stuff work without any helper libraries.
I am basically stuck with an idea to convert separately 5 and 4 (via mapping 5 and 4 to their ascii equivalents). Yet the idea would not work for sure. I have another idea to convert char '5' to int 5 by right shifting the byte by 4. Same with 4. Then multiply 5 by 10 and add 4, and then use division by two algorithm to find remainder and compose the binary number.
In C:
int asciToInteger(char *c)
{
int result = 0;
while (*c)
{
result *= 10;
result += (*c - '0');
c++;
}
return result;
}
Assumes input is valid.
You can get a head start on the assembly language version by compiling with certain switches which will output as ... assembly language! For example in GNU C: gcc -S -c ascii2int.c.
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Write a C program that reads lines containing floating point values of type double one per line from the standard input ( e.g. using scanf ), converts those values to integers and then prints those values as right justified integers in a 20-character wide field one per line on the standard output.
#include <stdio.h>
My biggest problem is I don't know where to start. Any tips and help would be appreciated.
The concept is to TYPECAST the float to an integer.
The loop here is for multiple values if you want.
This is the program. I hope this helps; it runs as you want.
#include <stdio.h>
int main()
{
float n;
int t;
//loop here
scanf("%f", &n);
t = (int)n;
printf("%20d", t);
// end loop here
return 0;
}