React Native - Identify the active screen. Drawer navigator - reactjs

Question

I am using stack navigator inside the drawer navigator. What I want to do is, I need to know the activeItem (the active screen), so as to display it as active.
StackNavigator
const stackNav = StackNavigator({
homeComponent: { screen: HomeScreen },
serviceScreen: { screen: ServiceScreen },
serviceDetailScreen: { screen: ServiceDetailScreen },
selectVehicleScreen: { screen: SelectVehileScreen },
addEditVehicle: { screen: AddVehicle },
dateTimeScreen: { screen: DateTimeScreen },
reviewScreen: { screen: ReviewScreen },
notesScreen: { screen: NotesScreen },
}, {
headerMode: 'none'
});
DrawerNavigator
const DrawerStack = DrawerNavigator({
appointment: {
screen: stackNav,
},
}, {
headerMode: 'none',
gesturesEnabled: false,
contentComponent: DrawerContainer
});
export default DrawerStack;

Answer 1

What you can do is
In your context there is only one screen that can be active and that is appointment screen.
If you want to know that if appointment screen is focused then you should check the props inside the DrawerContainer Component. It will give you the activeItemKey i.e appointment.
And then you can simply check in DrawerComponent that if
this.props.activeItemKey === 'appointment' ? { color: '#000' } : { color: '#fff' }]}
You can also pass the activeTintColor prop from DrawerNavigator as shown below
You can find other DrawerNavigatorConfigs here
const DrawerStack = DrawerNavigator({
appointment: {
screen: stackNav,
},
}, {
headerMode: 'none',
gesturesEnabled: false,
contentComponent: DrawerContainer,
contentOptions: {
activeTintColor: '#e91e63',
itemsContainerStyle: {
marginVertical: 0,
},
iconContainerStyle: {
opacity: 1
}
}
});
export default DrawerStack;