Excluding unique values from an array in C [closed] - c

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This code aims to exclude non-repeating values in a number list, but does not return repeats in their original sequence. How to keep all repeats with their precedence?
My code:
#include <stdio.h>
#include <stdlib.h>
int count=0;
int main ()
{
int i,j,k,x, altarray[1000],array[1000];
printf("Please enter the number of integers in your list:\n");
scanf("%d",&x);
printf ("Please enter the list of numbers\n");
for (i=0; i<x; i++)
scanf("%d",&array[i]);
printf("\nThe corrected array is...\n");
for (i=0; i<x; i++)
{
for (j=i+1; j<x; j++)
{
if(array[i]==array[j])
{
altarray[count]=array[i];
count++;
}
}
}
for (i=0; i<count; i++)
printf("%d",altarray[i]);
}

Answer 1

To search for duplicated number, you have to cover all elements of your array in the j for loop except the one that have the index i. So that loop should look like this:
for (j = 0; j < x; j++)
{
if ((array[i] == array[j]) && (i != j))
{
altarray[count] = array[i];
count++;
break;
}
}
I have added a break, to avoid wasting cycles after detecting the existence of the duplicated number.