How to ensure every command is Successful in batch script - batch-file

Question

I have a batch file with 10 lines and 5 functions in a batch script. How can I ensure that all the commands in a batch file are successful.
In other way, what's the logic to calculate return code of each command at the end of a script.
1. #ECHO OFF
2. if not exist "%Destination%\%NAME%" md %Destination%\%NAME%
3. if not exist "%Destination%\%NAME2%" md %Destination%\%NAME2%
4. rmdir %Destination%\%NAME3%
5. if not exist "%Destination%\NAME4%" md %Destination%\%NAME4%
6. cd /d X:\test1
in the above 5 lines, 4th line returns %ERRORLEVEL% 1 and 6th line returns the same. But, I could not put IF %ERRORLEVEL%==0 after every command. So, how could i script to handle this.

Answer 1

You should firstly save your file as .cmd instead of .bat for better error handling. Also always enclose your paths with double quotes. Then I suggest you test existance as well to overcome errorlevel.
If exist "%Destination%\%NAME3%" rmdir "%Destination%\%NAME3%"

Answer 2

For the code example I suggest following:
#echo off
rem Verify the existence of all used environment variables.
for %%I in (Destination NAME NAME2 NAME3 NAME4) do (
if not defined %%I (
echo Error detected by %~f0:
echo/
echo Environment variable name %%I is not defined.
echo/
exit /B 4
)
)
rem Verify the existence of all used directories by creating them
rem independent on existing already or not and next verifying if
rem the directory really exists finally.
for %%I in ("%Destination%\%NAME%" "%Destination%\%NAME2%") do (
md %%I 2>nul
if not exist "%%~I\" (
echo Error detected by %~f0:
echo/
echo Directory %%I
echo does not exist and could not be created.
echo/
exit /B 3
)
)
rem Remove directories independent on their existence and verify
rem if the directories really do not exist anymore finally.
for %%I in ("%Destination%\%NAME3%") do (
rd /Q /S %%I 2>nul
if exist "%%~I\" (
echo Error detected by %~f0:
echo/
echo Directory %%I
echo still exists and could not be removed.
echo/
exit /B 2
)
)
cd /D X:\test1 2>nul
if /I not "%CD%" == "X:\test1" (
echo Error detected by %~f0:
echo/
echo Failed to set "X:\test1" as current directory.
echo/
exit /B 1
)
This batch file handles nearly all possible errors which could occur during execution of this batch file. A remaining problem could be caused by an environment variable containing one or more double quotes in its value. The solution would be using delayed expansion.
Linux shell script interpreters have the option -e to exit immediately execution of a script if any command or application returns with a value not equal 0. But Windows command interpreter cmd.exe does not have such an option. The options of cmd.exe can be read on running in a command prompt window cmd /?.
So it is necessary to use in a batch file:
if exist "..." exit /B 1 or goto :EOF
if not exist "..." exit /B 1 or goto :EOF
if errorlevel 1 exit /B 1 or goto :EOF
... || exit /B 1 or ... || goto :EOF
See also the Stack Overflow articles:
Windows batch files: .bat vs .cmd?
Where does GOTO :EOF return to?
Single line with multiple commands using Windows batch file
What are the ERRORLEVEL values set by internal cmd.exe commands?
Which cmd.exe internal commands clear the ERRORLEVEL to 0 upon success?