Write a C program that sequentially writes two strings into each other? - c

Question

I got given this assignment:
Write a C program that sequentially writes two strings into each other as shown in the figure below. Start with a string
consisting of “X”-es and with each iteration, the first and last X characters must be rewritten until the entire string is
rewritten and the final message is displayed.
Hint: Make use a function in the library, strlen(), to determine the length of a string.
It should output like this:
XXXXXXXXXXXXXXXXXXXXX
IXXXXXXXXXXXXXXXXXXX!
I XXXXXXXXXXXXXXXXXg!
I lXXXXXXXXXXXXXXXng!
I loXXXXXXXXXXXXXing!
I lovXXXXXXXXXXXming!
I loveXXXXXXXXXmming!
I love XXXXXXXamming!
I love CXXXXXramming!
I love C-XXXgramming!
I love C-PXogramming!
I love C-Programming!
Final String= I love C-Programming!
This is what I have so far:
#include <stdio.h>
#include <string.h>
int main(int argc, char **argv)
{
//data
char str[] = "I love C-Programming!";
int rows;
int columns;
int length = strlen(str);
int format =5;
//process
{
rows = 0;
while (rows <= length)
{
rows++;
}
while (rows > 0)
{
int count = length;
columns = rows - 1;
while (columns > 0)
{
printf("X");
columns--;
count --;
}
if (rows <= length)
{
printf("%.*s", count, str);
}
printf("\n");
rows-=2;
}
printf("%s", str);
}
//output
printf("\n");
printf("\n");
printf("Final String = %s\n", str);
return 0;
}
It doesn't display properly. Please help!
Thanks.

Answer 1

#include <stdio.h>
#include <string.h>
int main()
{
char s1[] = "XXXXXXXXXXXXXXXXXXXXX";
const char s2[] = "I love C-Programming!";
const int n = strlen(s1);
const int h = n / 2;
int i;
int j;
puts(s1);
for (i = 0, j = n - 1; i <= h; ++i, --j) {
s1[i] = s2[i];
s1[j] = s2[j];
puts(s1);
}
return 0;
}

Answer 2

Hi this is indeed a very simple program. Actually your teacher want you to write a program like below:-
int main(int argc, char **argv)
{
//data
char str1[] = "I love C-Programming!";
char str2[strlen(str1)];
memset(str2, 'X', sizeof(str2));//Set all the character to X
str2[strlen(str1)-1]=0;//end of string character value of '\0'
//int rows;
//int columns;
int length = strlen(str1);
//int format =5;
int i = 0;
int j = length - 1;
do
{
printf("%s\n", str2);//Print the second string first
str2[i]=str1[i];//copy from first character from str1
str2[j]=str1[j];//copy from last character from str1
//so in each iteration we are coping two characters from str1 to str2
}while(i++ != j-- );//once I and j are equal break the loop
printf("%s", str2);
/*
//process
{
rows = 0;
while (rows <= length)
{
rows++;
}
while (rows > 0)
{
int count = length;
columns = rows - 1;
while (columns > 0)
{
printf("X");
columns--;
count --;
}
if (rows <= length)
{
printf("%.*s", count, str);
}
printf("\n");
rows-=2;
}
printf("%s", str);
}
*/
//output
printf("\n");
printf("\n");
printf("Final String = %s\n", str2);
return 0;
}
It will out put like below:-
XXXXXXXXXXXXXXXXXXXX
IXXXXXXXXXXXXXXXXXXX!
I XXXXXXXXXXXXXXXXXg!
I lXXXXXXXXXXXXXXXng!
I loXXXXXXXXXXXXXing!
I lovXXXXXXXXXXXming!
I loveXXXXXXXXXmming!
I love XXXXXXXamming!
I love CXXXXXramming!
I love C-XXXgramming!
I love C-PXogramming!
I love C-Programming!
Final String = I love C-Programming!